Problem 22
Question
For the exponential function $$ f(x)=3\left(0.4^{x}\right) $$ a. Calculate the percentage change and average rate of change of \(f\) for each of the following intervals: $$ \begin{array}{l} \text { i. From } x=1 \text { to } x=3 \\ \text { ii. From } x=3 \text { to } x=5 \end{array} $$ iii. From \(x=5\) to \(x=7\) b. On the basis of the results in part \(a\) and the characteristics of exponential functions presented in Chapter 1 , what generalizations can be made about percentage change and average rate of change for an exponential function?
Step-by-Step Solution
Verified Answer
The percentage change is constant at -84% for all intervals, while the average rate of change decreases. Exponential decay has a consistent percentage change.
1Step 1: Calculate Function Values at Given Points
First, calculate \(f(x)\) at the specified points for each interval.\(f(1) = 3(0.4^1) = 1.2\)\(f(3) = 3(0.4^3) = 3\times0.064 = 0.192\)\(f(5) = 3(0.4^5) = 3\times0.01024 = 0.03072\)\(f(7) = 3(0.4^7) = 3\times0.0016384 = 0.0049152\)
2Step 2: Calculate Percentage Change for Each Interval
Next, find the percentage change for each interval. The formula is:\[\text{Percentage Change} = \frac{f(x_2) - f(x_1)}{f(x_1)} \times 100\%\]i. From \(x=1\) to \(x=3\):\[\frac{0.192 - 1.2}{1.2} \times 100\% = -84\%\]ii. From \(x=3\) to \(x=5\):\[\frac{0.03072 - 0.192}{0.192} \times 100\% = -84\%\]iii. From \(x=5\) to \(x=7\):\[\frac{0.0049152 - 0.03072}{0.03072} \times 100\% = -84\%\]
3Step 3: Calculate Average Rate of Change for Each Interval
Find the average rate of change using the formula:\[\text{Average Rate of Change} = \frac{f(x_2) - f(x_1)}{x_2 - x_1}\]i. From \(x=1\) to \(x=3\):\[\frac{0.192 - 1.2}{3 - 1} = \frac{-1.008}{2} = -0.504\]ii. From \(x=3\) to \(x=5\):\[\frac{0.03072 - 0.192}{5 - 3} = \frac{-0.16128}{2} = -0.08064\]iii. From \(x=5\) to \(x=7\):\[\frac{0.0049152 - 0.03072}{7 - 5} = \frac{-0.0258048}{2} = -0.0129024\]
4Step 4: Generalizations About Exponential Functions
Based on the calculations, notice that the percentage change for each interval remains constant at \(-84\%\). This illustrates a consistent rate of change for exponential decay, where each interval changes by the same percentage, reflecting a fixed base multiplier less than one. However, the average rate of change decreases, indicating a more rapid decline in function value as \(x\) increases.
Key Concepts
Percentage ChangeAverage Rate of ChangeExponential Decay
Percentage Change
When analyzing an exponential function, understanding the percentage change is crucial to see how rapidly a function grows or decays over a specific range. Percentage change measures how much a function's value changes in terms of percentage in one interval compared to its starting value at the beginning of that interval.
- The formula for percentage change is given by \[ \text{Percentage Change} = \frac{f(x_2) - f(x_1)}{f(x_1)} \times 100\% \]
- This formula helps us calculate the relative change between two function values, \(f(x_1)\) and \(f(x_2)\).
- In the original exercise, when we computed the percentage change for the interval from \(x=1\) to \(x=3\), \(x=3\) to \(x=5\), and \(x=5\) to \(x=7\), each resulted in a consistent \(-84\%\) change.
Average Rate of Change
Another important concept in analyzing functions is the average rate of change. This gives us a sense of how the function's value changes on average over a specific interval of the variable \(x\). Unlike percentage change, which is relative, the average rate of change gives us an absolute measure.
- The formula for the average rate of change is \[ \text{Average Rate of Change} = \frac{f(x_2) - f(x_1)}{x_2 - x_1} \]
- This depicts how the function's value shifts from \(f(x_1)\) to \(f(x_2)\) over the interval \(x_2 - x_1\).
- In our specific problem, the average rate of change diminished with each interval from \(x=1\) to \(x=7\).
Exponential Decay
Exponential decay is a type of exponential function where the value of the function decreases by a consistent factor for every increase in \(x\).
- In the standard exponential decay function \(f(x) = a(b^x)\), the base \(b\) is a positive number less than 1, indicating decay.
- As \(b\) approaches zero, the function decreases very quickly, which is reflected in the original exercise's constant percentage change of \(-84\%\) across intervals.
- The consistent factor by which the function's value decreases can also describe how sharply or gradually a function decays.
Other exercises in this chapter
Problem 20
Social Networking In \(2007,\) Bebo was the largest social networking site in the UK, Ireland, and New Zealand, and was the third largest social networking site
View solution Problem 21
For the linear function $$ f(x)=3 x+4 $$ a. Calculate the average rate of change and the percentage change in \(f\) for each of the following intervals: $$ \beg
View solution Problem 23
Discuss any advantages or disadvantages of finding rates of change graphically and numerically. Include a brief description of when each method might be appropr
View solution Problem 24
Explain why there may be differences between the numerical estimate of a rate of change of a modeled function at a point and the actual rate of change that occu
View solution