Problem 22
Question
For Problems \(17-32\), indicate the solution set for each system of inequalities by shading the appropriate region. $$ \left(\begin{array}{l} x+y>1 \\ x-y<1 \end{array}\right) $$
Step-by-Step Solution
Verified Answer
The solution is the region above \( x + y = 1 \) and below \( x - y = 1 \), excluding the boundary lines.
1Step 1: Understand and Rewrite the Inequalities
The given system of inequalities is \( x + y > 1 \) and \( x - y < 1 \). These need to be solved concurrently to find the solution set.
2Step 2: Plot the Line for First Inequality
Rewrite the first inequality \( x + y > 1 \) as the line \( x + y = 1 \). This is the boundary line. Plot this line on a graph. Use a dashed line to indicate that the points on the line are not included in the solution (since it's a \(>\) inequality).
3Step 3: Determine the Shaded Region for First Inequality
To find the region of \( x + y > 1 \), choose a test point such as \((0,0)\). Plugging into the inequality gives \(0 + 0 = 0 > 1\), which is false. Thus, the region above the line \(x + y = 1\) is the solution.
4Step 4: Plot the Line for Second Inequality
Rewrite the second inequality \( x - y < 1 \) as \( x - y = 1 \). Similarly, this is the boundary line. Plot this line on the same graph. Use a dashed line here as well, indicating that points on the line aren't part of the solution.
5Step 5: Determine the Shaded Region for Second Inequality
For \( x - y < 1 \), use the test point \((0,0)\). Substitute into the inequality to get \(0 - 0 = 0 < 1\), which is true. The region below this line \( x - y = 1 \) is the solution.
6Step 6: Identify Intersection of Solutions
The solution to the system is the region where the two shaded regions from the inequalities overlap. This is the area above \( x + y = 1 \) and below \( x - y = 1 \). Be sure to exclude the lines themselves from the solution region.
Key Concepts
Graphing InequalitiesSolution SetsBoundary Lines
Graphing Inequalities
When we graph inequalities, we're essentially drawing a picture of all possible solutions to these inequalities. For the inequality system we are handling, the two inequalities to graph are:
By choosing test points, like \((0, 0)\), you can determine which side of the boundary line holds the solutions. This insight helps you shade the correct region that represents all solutions to the inequality.
- For the first inequality, \( x + y > 1 \), we treat it like an equation \( x + y = 1 \) to find the associated line.
- For the second inequality, \( x - y < 1 \), rewrite it as \( x - y = 1 \) to find the line here too.
By choosing test points, like \((0, 0)\), you can determine which side of the boundary line holds the solutions. This insight helps you shade the correct region that represents all solutions to the inequality.
Solution Sets
The solution set to a system of inequalities is the set of all points that satisfy both inequalities simultaneously. In this problem:
- For the inequality \( x + y > 1 \), the solution includes all points above the line \( x + y = 1 \).
- For \( x - y < 1 \), the solution comprises all points below the line \( x - y = 1 \).
Boundary Lines
Boundary lines are the "edges" that define where the inequality transitions. They come from the equalities when you replace the inequality symbols with equal signs:
Understanding the role of boundary lines is key in solving and graphing systems of inequalities. They serve as visual guides to separating regions of valid solutions from those that don't satisfy the inequality.
- The boundary line for \( x + y > 1 \) is \( x + y = 1 \).
- And for \( x - y < 1 \), it's \( x - y = 1 \).
Understanding the role of boundary lines is key in solving and graphing systems of inequalities. They serve as visual guides to separating regions of valid solutions from those that don't satisfy the inequality.
Other exercises in this chapter
Problem 22
For Problems 19-48, solve each system by using either the substitution or the elimination-by-addition method, whichever seems more appropriate. (Objective 2) $$
View solution Problem 22
For Problems \(1-26\), solve each system by using the substitution method. (Objective 1) $$ \left(\begin{array}{l} 2 x-3 y=-16 \\ 6 x+7 y=16 \end{array}\right)
View solution Problem 23
For Problems \(1-28\), (a) graph each system so that approximate real number solutions (if there are any) can be predicted, and (b) solve each system using the
View solution Problem 23
Use Cramer's rule to find the solution set for each of the following systems. (Objective 2) $$ \left(\begin{array}{rr} -x+3 y= & 17 \\ 4 x-5 y= & -33 \end{array
View solution