Problem 22
Question
For exercises \(5-48\), simplify. $$ \frac{k^{2}}{k+7}-\frac{49}{k+7} $$
Step-by-Step Solution
Verified Answer
The simplified expression is \(k - 7\).
1Step 1: Identify the common denominator
The common denominator in this expression is already given as both terms have the denominator of \(k+7\).
2Step 2: Combine the numerators
Since the denominators are the same, the next step is to combine the numerators: \[ \frac{k^2}{k+7} - \frac{49}{k+7} = \frac{k^2 - 49}{k+7} \]
3Step 3: Factor the numerator
The numerator \(k^2 - 49\) is a difference of squares, and can be factored as follows: \[ k^2 - 49 = (k + 7)(k - 7) \]
4Step 4: Simplify the expression
Replace the factored form into the expression: \[ \frac{(k+7)(k-7)}{k+7} \] Since \(k+7\) is in both the numerator and the denominator, they cancel each other out, leaving: \[ k - 7 \]
Key Concepts
common denominatorcombining numeratorsdifference of squaresfactoring expressionssimplification
common denominator
When simplifying rational expressions, the first crucial step is to ensure the fractions have a common denominator.
This makes it easier to combine them into a single rational expression.
In the given exercise, both fractions already have a common denominator of \( k+7 \).
If the denominators were different, you would need to find an equivalent common denominator for both fractions.
This often involves finding the least common multiple (LCM) of the denominators.
This makes it easier to combine them into a single rational expression.
In the given exercise, both fractions already have a common denominator of \( k+7 \).
If the denominators were different, you would need to find an equivalent common denominator for both fractions.
This often involves finding the least common multiple (LCM) of the denominators.
combining numerators
Once you have a common denominator, you can combine the numerators into one fraction.
This is simply done by performing the operation indicated (addition or subtraction) on the numerators, keeping the common denominator in place.
In our exercise, the numerators are \( k^2 \) and \( 49 \) with a subtraction operation:
This is simply done by performing the operation indicated (addition or subtraction) on the numerators, keeping the common denominator in place.
In our exercise, the numerators are \( k^2 \) and \( 49 \) with a subtraction operation:
- \( \frac{k^2}{k+7} - \frac{49}{k+7} = \frac{k^2 - 49}{k+7} \)
difference of squares
The next step involves understanding and applying the concept of the difference of squares.
The difference of squares formula is:
It can be written as:
The difference of squares formula is:
- \( a^2 - b^2 = (a+b)(a-b) \)
It can be written as:
- \( k^2 - 7^2 \)
- \( (k+7)(k-7) \) This step simplifies the expression further.
factoring expressions
Factoring expressions is a crucial step while simplifying rational expressions.
You need to be vigilant in identifying patterns like the difference of squares, which simplifies complex expressions.
In our example, once we've identified the numerator \( k^2 - 49 \) as a difference of squares, we factor it into:
You need to be vigilant in identifying patterns like the difference of squares, which simplifies complex expressions.
In our example, once we've identified the numerator \( k^2 - 49 \) as a difference of squares, we factor it into:
- \( (k+7)(k-7) \)
- \( \frac{(k+7)(k-7)}{k+7} \)
simplification
The final step is simplification, where we cancel common terms in the numerator and denominator.
In the simplified form of the expression:
These terms cancel each other out, leaving:
In the simplified form of the expression:
- \( \frac{(k+7)(k-7)}{k+7} \)
These terms cancel each other out, leaving:
- \( k-7 \)
Other exercises in this chapter
Problem 22
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