Problem 22
Question
Find the work done lifting a 10 pound book 3 feet straight up into the air. Assume the force of gravity is acting straight downwards.
Step-by-Step Solution
Verified Answer
The work done is 30 foot-pounds.
1Step 1: Understanding Work Formula
The formula to calculate work done, when a force is applied over a distance, is given by \( W = F \times d \), where \( W \) is the work done, \( F \) is the force applied, and \( d \) is the distance over which the force is applied.
2Step 2: Identify Known Values
From the problem statement, the force \( F \) is the weight of the book, which is 10 pounds (since force due to gravity is weight), and the distance \( d \) the book is lifted is 3 feet.
3Step 3: Calculate Work Done
Substitute the known values into the work formula: \( W = 10 \text{ pounds} \times 3 \text{ feet} = 30 \text{ foot-pounds} \).
4Step 4: Final Result
The work done in lifting the 10-pound book 3 feet into the air is 30 foot-pounds.
Key Concepts
Force and MotionCalculation of WorkGravityBasic Physics Formulas
Force and Motion
In physics, force and motion are inseparable concepts that help us understand how objects move and interact. A force is any interaction that, when unopposed, will change the motion of an object. It can be a push or pull acting upon an object as a result of its interaction with another object. Motion, on the other hand, refers to the change in position of an object with respect to time.
For example, when you lift a book, you apply a force to overcome gravity and move the book. The book's motion from a lower position to a higher one shows how force and motion work in tandem. Understanding force and motion allows us to calculate work, as motion is a key component in determining how much work is done.
For example, when you lift a book, you apply a force to overcome gravity and move the book. The book's motion from a lower position to a higher one shows how force and motion work in tandem. Understanding force and motion allows us to calculate work, as motion is a key component in determining how much work is done.
Calculation of Work
Calculating work in physics involves determining how much energy is transferred when a force causes an object to move. The fundamental formula for work (W) is given by:
In the example provided, the force is the weight of the book, a direct result of gravity, and the distance is how far the book is lifted. Substituting these values into the formula gives \( W = 10 \text{ pounds} \times 3 \text{ feet} = 30 \text{ foot-pounds} \). This result shows how much energy is used to lift the book against the force of gravity.
- \( W = F \times d \)
In the example provided, the force is the weight of the book, a direct result of gravity, and the distance is how far the book is lifted. Substituting these values into the formula gives \( W = 10 \text{ pounds} \times 3 \text{ feet} = 30 \text{ foot-pounds} \). This result shows how much energy is used to lift the book against the force of gravity.
Gravity
Gravity is a natural phenomenon by which all things with mass are brought toward one another, including objects ranging from atoms to planets. On Earth, gravity provides the force that gives weight to physical objects and causes them to fall toward the ground when dropped.
When lifting an object vertically, like a 10-pound book, you are working against the force of gravity acting downward. The force due to gravity on Earth is approximately 9.8 m/s², but is often simplified to 32 feet/s² when using imperial units, as in this exercise.
This gravitational pull is what you must overcome by applying a force equal to the weight of the object to lift it, which in this case is measured in pounds force.
When lifting an object vertically, like a 10-pound book, you are working against the force of gravity acting downward. The force due to gravity on Earth is approximately 9.8 m/s², but is often simplified to 32 feet/s² when using imperial units, as in this exercise.
This gravitational pull is what you must overcome by applying a force equal to the weight of the object to lift it, which in this case is measured in pounds force.
Basic Physics Formulas
Understanding the basic physics formulas is crucial for solving problems related to force, motion, and energy. The key formula used in calculating work is just one among many essential equations in physics.
- Newton's Second Law: \( F = m \cdot a \), describing the relationship between an object's mass \( m \), its acceleration \( a \), and the applied force \( F \).
- Law of Universal Gravitation: \( F = G \frac{m_1 \cdot m_2}{r^2} \), explaining the gravitational attraction between two masses.
Other exercises in this chapter
Problem 21
Convert the point from polar coordinates into rectangular coordinates. $$ \left(\frac{3}{5}, \frac{\pi}{2}\right) $$
View solution Problem 22
In Exercises \(21-24\), plot the set of parametric equations with the help of a graphing utility. Be sure to indicate the orientation imparted on the curve by t
View solution Problem 22
Find the component form of the vector \(\vec{v}\) using the information given about its magnitude and direction. Give exact values. \(\|\vec{v}\|=2 \sqrt{5} ;\)
View solution Problem 22
In Exercises \(21-30\), find the exact polar coordinates of the points of intersection of graphs of the polar equations. Remember to check for intersection at t
View solution