Problem 22
Question
Find the standard form of the equation of each parabola satisfying the given conditions. Focus: \((0,20) ;\) Directrix: \(y=-20\)
Step-by-Step Solution
Verified Answer
The standard form of the equation of the parabola is \(y = 5x^2\).
1Step 1: Identify the vertex
Since the parabola is symmetric with respect to the x-axis and the focus and directrix are mirror images in relation to the x-axis, the vertex of the parabola is at the origin (0,0).
2Step 2: Determine the opening direction
Since the focus (0,20) is above the vertex, the parabola opens upwards.
3Step 3: Find the value of a
The distance from the vertex to the focus or to the directrix is |4a|. Hence, |4a| = 20, which means a = 5.
4Step 4: Formulate the standard equation
For a parabola opening upwards, the standard form is \(y = ax^2\). Thus, replacing \(a\) with 5 yields the standard form of the parabola: \(y = 5x^2\).
Other exercises in this chapter
Problem 21
Find the standard form of the equation of each parabola satisfying the given conditions. Focus: \((0,15) ;\) Directrix: \(y=-15\)
View solution Problem 21
Use vertices and asymptotes to graph each hyperbola. Locate the foci and find the equations of the asymptotes. $$9 x^{2}-4 y^{2}=36$$
View solution Problem 22
Use vertices and asymptotes to graph each hyperbola. Locate the foci and find the equations of the asymptotes. $$4 x^{2}-25 y^{2}=100$$
View solution Problem 23
Find the standard form of the equation of each parabola satisfying the given conditions. Focus: \((0,-25) ;\) Directrix: \(y=25\)
View solution