Problem 22
Question
Find the first five terms of the sequence and determine if it is geometric. If it is geometric, find the common ratio and express the \(n\)th term of the sequence in the standard form \(a_{n}=a r^{n-1} .\) $$ a_{n}=n^{n} $$
Step-by-Step Solution
Verified Answer
The sequence is not geometric; terms are 1, 4, 27, 256, 3125.
1Step 1: Find the first term
To find the first term of the sequence, substitute \( n = 1 \) into the formula \( a_n = n^n \). So, \( a_1 = 1^1 = 1 \).
2Step 2: Find the second term
To find the second term, substitute \( n = 2 \) into the formula \( a_n = n^n \). So, \( a_2 = 2^2 = 4 \).
3Step 3: Find the third term
To find the third term, substitute \( n = 3 \) into the formula \( a_n = n^n \). So, \( a_3 = 3^3 = 27 \).
4Step 4: Find the fourth term
To find the fourth term, substitute \( n = 4 \) into the formula \( a_n = n^n \). So, \( a_4 = 4^4 = 256 \).
5Step 5: Find the fifth term
To find the fifth term, substitute \( n = 5 \) into the formula \( a_n = n^n \). So, \( a_5 = 5^5 = 3125 \).
6Step 6: Determine if sequence is geometric
A sequence is geometric if the ratio of consecutive terms is constant. Calculate the ratios: \( \frac{a_2}{a_1} = \frac{4}{1} = 4 \), \( \frac{a_3}{a_2} = \frac{27}{4} \), \( \frac{a_4}{a_3} = \frac{256}{27} \), and \( \frac{a_5}{a_4} = \frac{3125}{256} \). These are not equal, so the sequence is not geometric.
Key Concepts
Sequence and SeriesCommon RatioGeneral Term of a Sequence
Sequence and Series
A **sequence** is an ordered list of numbers where each number is called a term. Sequences can be based on many different rules. In a mathematical sequence, there is often a rule that determines how each term is related to the previous one.
In the context of mathematics, a **series** is the sum of the terms of a sequence.
To better grasp these concepts, observe how sequences are structured:
In the context of mathematics, a **series** is the sum of the terms of a sequence.
To better grasp these concepts, observe how sequences are structured:
- A given sequence of numbers could be: 2, 4, 6, 8, ..., where each term is increased by adding 2 to the previous one.
- Another sequence could be 1, 4, 9, 16, ..., where each term is a perfect square of consecutive integers (1, 2, 3, 4, ...).
Common Ratio
The term **common ratio** appears when discussing a specific type of sequence known as a geometric sequence. In a geometric sequence, each term is formed by multiplying the previous term by a fixed, non-zero number called the common ratio.
Let's delve deeper:
- Imagine a sequence: 3, 6, 12, 24, ..., where each number is multiplied by 2, so the common ratio is 2.
- In a geometric sequence with a common ratio of 3, starting from 5, you'd have: 5, 15, 45, 135, ..., continuing indefinitely.
General Term of a Sequence
The **general term** of a sequence is an expression that allows us to find any term in the sequence without computing all the preceding terms. This term is particularly useful as it provides a formula based on position within the sequence.For geometric sequences, the general term is expressed as\[ a_n = a \cdot r^{n-1} \]where:
In our example, however, the sequence was not geometric, implying that an alternative approach is needed since the sequence could not be expressed in the standard geometric form.
- \( a \) is the first term of the sequence.
- \( r \) is the common ratio.
- \( n \) is the position of the term in the sequence.
In our example, however, the sequence was not geometric, implying that an alternative approach is needed since the sequence could not be expressed in the standard geometric form.
Other exercises in this chapter
Problem 22
\(21-24\) Use the Binomial Theorem to expand the expression. $$ (1-x)^{5} $$
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Show that \(100 n \leq n^{2}\) for all \(n \geq 100.\)
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17-22 Find the first five terms of the sequence and determine if it is arithmetic. If is arithmetic, find the common difference and express the \(n\)th term of
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Use a graphing calculator to do the following. (a) Find the first 10 terms of the sequence. (b) Graph the first 10 terms of the sequence. \(a_{n}=a_{n-1}-a_{n-2
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