Problem 22
Question
Find the exact value of each trigonometric function. \(\sin 240^{\circ}\)
Step-by-Step Solution
Verified Answer
\(\sin 240^{\circ} = -\frac{\sqrt{3}}{2}\)
1Step 1: Determine the Reference Angle
To find the exact value of \(\sin 240^{\circ}\), start by determining the reference angle. Since 240° is in the third quadrant, subtract 180° from 240° to find the reference angle: \(240^{\circ} - 180^{\circ} = 60^{\circ}\). So, the reference angle is \(60^{\circ}\).
2Step 2: Apply Sine in the Third Quadrant
In the third quadrant, the sine function is negative because sine is positive in the first and second quadrants, but negative in the third and fourth quadrants. Thus, \(\sin 240^{\circ} = -\sin 60^{\circ}\).
3Step 3: Use the Sine of 60 Degrees
From the unit circle or trigonometric ratios, we know \(\sin 60^{\circ} = \frac{\sqrt{3}}{2}\). Since we are in the third quadrant, \(\sin 240^{\circ} = -\frac{\sqrt{3}}{2}\).
Key Concepts
Sine FunctionReference AngleUnit CircleQuadrantsExact Values of Trigonometric Functions
Sine Function
The sine function is one of the primary trigonometric functions, often denoted as \( \sin \theta \). It relates the angle in a right triangle to the ratio of the length of the opposite side to the hypotenuse. In the context of the unit circle, the sine of an angle \( \theta \) corresponds to the y-coordinate of the point where the terminal side of the angle intersects the circle.
This implies that as the angle \( \theta \) changes, the sine value varies between -1 and 1.
This implies that as the angle \( \theta \) changes, the sine value varies between -1 and 1.
- When \( \theta = 0 \) or \( \theta = 180^{\circ} \), \( \sin \theta = 0 \)
- When \( \theta = 90^{\circ} \) or \( \theta = 270^{\circ} \), \( \sin \theta = 1 \) or \( \sin \theta = -1 \) respectively
- The sine function is periodic with a period of \( 360^{\circ} \) or \( 2\pi \) radians
Reference Angle
A reference angle is the smallest angle that a given angle makes with the x-axis. It is always a positive acute angle, usually measured between 0° and 90°. To find the reference angle for any given angle, you need to:
- Identify which quadrant the original angle is in
- Use the reference angle formula based on that quadrant
Unit Circle
The unit circle is a fundamental concept in trigonometry, representing a circle with a radius of one unit centered at the origin of a coordinate plane. It is an invaluable tool when understanding trigonometric functions as it links angles directly to coordinates on the circle.
Key points to remember about the unit circle:
Key points to remember about the unit circle:
- Each angle \( \theta \) in the unit circle corresponds to a point \((x, y)\) on the circle, where \( x = \cos \theta \) and \( y = \sin \theta \)
- The entire circle is completed with an angle of \( 360^{\circ} \) or \( 2\pi \) radians
- The sine value of an angle is simply the y-coordinate of the corresponding point on the unit circle
Quadrants
The coordinate plane is divided into four quadrants, which help in determining the sign of a trigonometric function based on the angle's placement:
- Quadrant I: All trigonometric functions are positive
- Quadrant II: Sine and cosecant are positive
- Quadrant III: Tangent and cotangent are positive
- Quadrant IV: Cosine and secant are positive
Exact Values of Trigonometric Functions
Exact values of trigonometric functions refer to specific, often well-known values for sine, cosine, and tangent at key angles such as 0°, 30°, 45°, 60°, and 90°. These values are often derived from geometric principles or the unit circle.For example, the exact value of \( \sin 60^{\circ} \) is:\[\sin 60^{\circ} = \frac{\sqrt{3}}{2}\]When dealing with angles such as 240°, using the reference angle of 60° and the quadrant's properties, the exact value can easily be determined as \( \sin 240^{\circ} = -\frac{\sqrt{3}}{2} \). Having these exact values at your fingertips is crucial for solving trigonometric problems quickly and accurately.
Other exercises in this chapter
Problem 22
Find each value. Write angle measures in radians. Round to the nearest hundredth. $$ \tan \left(\cos ^{-1} \frac{6}{7}\right) $$
View solution Problem 22
Determine whether each triangle should be solved by beginning with the Law of Sines or Law of Cosines. Then solve each triangle. Round measures of sides to the
View solution Problem 22
Rewrite each degree measure in radians and each radian measure in degrees. \(-15^{\circ}\)
View solution Problem 23
Determine whether each triangle has no solution, one solution, or two solutions. Then solve each triangle. Round measures of sides to the nearest tenth and meas
View solution