Problem 22
Question
Find \(\mathbf{x}+\mathbf{y}\) for each pair of vectors \(\mathbf{x}\) and \(\mathbf{v}\). Represent \(\mathrm{x}, \mathbf{y}\), and \(\mathrm{x}+\mathrm{y}\) in the plane, and explain graphically how you add \(\mathbf{x}\) and \(\mathbf{y}\). \(\mathbf{x}=\left[\begin{array}{l}-3 \\ -1\end{array}\right]\) and \(\mathbf{y}=\left[\begin{array}{l}-1 \\ -1\end{array}\right]\)
Step-by-Step Solution
Verified Answer
\( \mathbf{x} + \mathbf{y} = \begin{bmatrix} -4 \\ -2 \end{bmatrix} \). Graphically, add vectors head-to-tail to find the resultant.
1Step 1: Understand Vector Notation
Vector notation \( \mathbf{x} = \begin{bmatrix} -3 \ -1 \end{bmatrix} \) and \( \mathbf{y} = \begin{bmatrix} -1 \ -1 \end{bmatrix} \) indicate that \( \mathbf{x} \) and \( \mathbf{y} \) are composed of two components, with the first component representing the horizontal direction (x-axis) and the second representing the vertical direction (y-axis).
2Step 2: Add Vectors Component-wise
To find \( \mathbf{x} + \mathbf{y} \), add each corresponding component of \( \mathbf{x} \) and \( \mathbf{y} \):\[ \mathbf{x} + \mathbf{y} = \begin{bmatrix} -3 \ -1 \end{bmatrix} + \begin{bmatrix} -1 \ -1 \end{bmatrix} = \begin{bmatrix} (-3) + (-1) \ (-1) + (-1) \end{bmatrix} = \begin{bmatrix} -4 \ -2 \end{bmatrix} \]This result shows the vector sum \( \mathbf{x} + \mathbf{y} = \begin{bmatrix} -4 \ -2 \end{bmatrix} \).
3Step 3: Graphical Representation of Vectors
Draw \( \mathbf{x} \), \( \mathbf{y} \), and \( \mathbf{x} + \mathbf{y} \) on a coordinate plane. Start \( \mathbf{x} \) at the origin and move \(-3\) units to the left and \(-1\) unit down. Similarly, for \( \mathbf{y} \), add it tail-to-head starting from the head of \( \mathbf{x} \) moving \(-1\) unit to the left and \(-1\) unit down.The final position reached is \( \mathbf{x} + \mathbf{y}: \begin{bmatrix} -4 \ -2 \end{bmatrix} \), which aligns with starting at the origin, moving \(-4\) units left and \(-2\) units down from the origin.
4Step 4: Summary of Vector Addition
Graphically, adding vectors \( \mathbf{x} \) and \( \mathbf{y} \) involves placing them head-to-tail. The resultant vector \( \mathbf{x} + \mathbf{y} \) is the vector pointing from the origin to the endpoint of the second vector (\( \mathbf{y} \)), showing a new vector that represents the combined effect of \( \mathbf{x} \) and \( \mathbf{y} \).
Key Concepts
Component-wise AdditionGraphical RepresentationCoordinate Plane
Component-wise Addition
Vector addition is a crucial concept in mathematics and physics. It involves combining two or more vectors to get a resultant vector. To perform vector addition, we use the method of component-wise addition. Simply put, this means adding the corresponding components of the vectors separately.
For example, given vectors \( \mathbf{x} = \begin{bmatrix} -3 \ -1 \end{bmatrix} \) and \( \mathbf{y} = \begin{bmatrix} -1 \ -1 \end{bmatrix} \), each vector has two components. The first component refers to the horizontal or x-direction, while the second indicates the vertical or y-direction.
To find the sum \( \mathbf{x} + \mathbf{y} \), add their respective x and y components:
For example, given vectors \( \mathbf{x} = \begin{bmatrix} -3 \ -1 \end{bmatrix} \) and \( \mathbf{y} = \begin{bmatrix} -1 \ -1 \end{bmatrix} \), each vector has two components. The first component refers to the horizontal or x-direction, while the second indicates the vertical or y-direction.
To find the sum \( \mathbf{x} + \mathbf{y} \), add their respective x and y components:
- The x-components: \(-3 + (-1) = -4\)
- The y-components: \(-1 + (-1) = -2\)
Graphical Representation
Graphical representation of vectors can greatly aid in understanding vector addition. When visualizing vectors, you can draw them on a coordinate plane. The process of adding vectors can be grasped intuitively by drawing them head-to-tail.
Let's take the vectors \( \mathbf{x} \) and \( \mathbf{y} \) from our example. To draw \( \mathbf{x} \), start from the origin, move 3 units to the left (since it’s negative) and 1 unit down. For \( \mathbf{y} \), begin from where \( \mathbf{x} \) ends, moving 1 unit more to the left and 1 unit further down.
Let's take the vectors \( \mathbf{x} \) and \( \mathbf{y} \) from our example. To draw \( \mathbf{x} \), start from the origin, move 3 units to the left (since it’s negative) and 1 unit down. For \( \mathbf{y} \), begin from where \( \mathbf{x} \) ends, moving 1 unit more to the left and 1 unit further down.
- Start at the origin for \( \mathbf{x} \)
- Move left and down respecting the vector's components
- From the end of \( \mathbf{x} \), trace \( \mathbf{y} \)
Coordinate Plane
Using a coordinate plane simplifies understanding the position and direction of vectors. It's like having a grid map where you can plot points based on coordinates. With axes labeled x and y, you can easily visualize vectors like \( \mathbf{x} = \begin{bmatrix} -3 \ -1 \end{bmatrix} \).
The coordinate plane helps show how each vector moves from one point to another. The origin, usually at point \((0, 0)\), serves as a starting point to ensure the positions are clear and organized.
The coordinate plane helps show how each vector moves from one point to another. The origin, usually at point \((0, 0)\), serves as a starting point to ensure the positions are clear and organized.
- The x-value indicates horizontal movement: left for negative, right for positive.
- The y-value signals vertical movement: down for negative, upward for positive.
Other exercises in this chapter
Problem 21
In Problems 19-24, solve each system of linear equations. $$ \begin{array}{r} 2 x+y+z=7 \\ 3 x+2 y+z=9 \\ x+y-z=0 \end{array} $$
View solution Problem 22
Use the dot product to compute the length of \([1,2,3,0]\).
View solution Problem 22
Let $$A=\left[\begin{array}{rr} -1 & 0 \\ 1 & 2 \end{array}\right], \quad B=\left[\begin{array}{rr} 2 & 0 \\ -1 & -1 \end{array}\right], \quad C=\left[\begin{ar
View solution Problem 22
In Problems 19-24, solve each system of linear equations. $$ \begin{array}{r} -2 x+4 y-z=-1 \\ x+7 y+2 z=-4 \\ 3 x-2 y+3 z=-3 \end{array} $$
View solution