Problem 22
Question
Find any horizontal or vertical asymptotes. $$ f(x)=\frac{x+6}{5-2 x} $$
Step-by-Step Solution
Verified Answer
Vertical asymptote at \( x = \frac{5}{2} \) and horizontal asymptote at \( y = -\frac{1}{2} \).
1Step 1: Identify Vertical Asymptotes
Vertical asymptotes occur where the denominator of a rational function equals zero. Set the denominator of \( f(x) = \frac{x+6}{5-2x} \) equal to zero and solve for \( x \): \( 5 - 2x = 0 \). Solving for \( x \), we get \( x = \frac{5}{2} \). Thus, there is a vertical asymptote at \( x = \frac{5}{2} \).
2Step 2: Determine Horizontal Asymptotes
Horizontal asymptotes occur based on the degree of the numerator and the denominator. For \( f(x) = \frac{x+6}{5-2x} \), both the numerator and the denominator are of degree 1. When the degrees are equal, the horizontal asymptote is found by dividing the leading coefficients. The leading coefficient of the numerator (\( x \)) is 1 and that of the denominator (\( -2x \)) is -2. Thus, the horizontal asymptote is \( y = \frac{1}{-2} = -\frac{1}{2} \).
Key Concepts
Vertical asymptotesHorizontal asymptotesRational functions
Vertical asymptotes
Vertical asymptotes are a key feature of rational functions. They occur at values of \( x \) where the function becomes undefined, which happens when the denominator equals zero. Let's look at the example given: \( f(x) = \frac{x+6}{5-2x} \).
Here, to find the vertical asymptote, set the denominator \( 5-2x \) to zero:
Here, to find the vertical asymptote, set the denominator \( 5-2x \) to zero:
- Solve for \( x \): \( 5 - 2x = 0 \).
- Rearranging gives \( 2x = 5 \).
- Finally, \( x = \frac{5}{2} \) is the vertical asymptote.
Horizontal asymptotes
Horizontal asymptotes describe the behavior of rational functions as \( x \) approaches infinity or negative infinity. They help us understand how the function behaves at very large or very small values of \( x \).
For the function \( f(x) = \frac{x+6}{5-2x} \), we compare the degrees of the numerator and the denominator.
For the function \( f(x) = \frac{x+6}{5-2x} \), we compare the degrees of the numerator and the denominator.
- In this case, both degrees are 1.
- When degrees are equal, compute the horizontal asymptote by dividing the leading coefficients.
Rational functions
Rational functions are fractions with polynomials in both the numerator and the denominator. They can take the form like \( f(x) = \frac{a(x)}{b(x)} \). These types of functions are versatile as they can model real-life scenarios and showcase important asymptotic behavior.
In rational functions:
In rational functions:
- The numerator is \( a(x) \) and the denominator is \( b(x) \).
- Asymptotes provide insights into behavior in particular as \( x \) approaches critical values or extremes.
Other exercises in this chapter
Problem 22
Use positive exponents to rewrite. $$ \sqrt[5]{x^{2}} $$
View solution Problem 22
Find all real solutions. Check your results. $$ \frac{1}{x-1}+\frac{3}{x+1}=\frac{4}{x^{2}-1} $$
View solution Problem 23
Divide the expression. $$\frac{3 x^{4}-7 x^{3}+6 x-16}{3 x-7}$$
View solution Problem 23
Complete the following. (a) Find all zeros of \(f(x)\) (b) Write the complete factored form of \(f(x)\) $$ f(x)=x^{2}+25 $$
View solution