Problem 22
Question
Factor the expression. $$ 49-a^{2} $$
Step-by-Step Solution
Verified Answer
The factored form of the expression \(49 - a^{2}\) is \((7 - a)(7 + a)\).
1Step 1: Identify a and b
In our expression, \(49 - a^{2}\), we recognize that 49 is a perfect square. Thus, \(a\) is 7 and \(b\) is \(a\).
2Step 2: Apply difference of squares formula
We apply the difference of squares formula and substitute our values of \(a\) and \(b\) into it. The formula is \(a^{2} - b^{2} = (a - b)(a + b)\), which therefore yields \((7 - a)(7 + a)\).
Key Concepts
Difference of SquaresPerfect SquaresAlgebraic Expression
Difference of Squares
The Difference of Squares is a special algebraic expression that can be factored into two binomials. It takes the form of \(a^2 - b^2\). The magic behind this expression lies in its simplicity to be broken down into
As applied in our problem, \(49 - a^2\), we recognize it as a difference of squares. This is because both 49 and \(a^2\) are perfect squares.
49 is a perfect square because it is \(7^2\), and \(a^2\) is simply \(a^2\). Hence, the expression \(49 - a^2\) becomes \((7 - a)(7 + a)\) when factored.
This method is efficient and saves time, especially in longer algebraic manipulations.
- \((a - b)(a + b)\), which is very straightforward to remember.
As applied in our problem, \(49 - a^2\), we recognize it as a difference of squares. This is because both 49 and \(a^2\) are perfect squares.
49 is a perfect square because it is \(7^2\), and \(a^2\) is simply \(a^2\). Hence, the expression \(49 - a^2\) becomes \((7 - a)(7 + a)\) when factored.
This method is efficient and saves time, especially in longer algebraic manipulations.
Perfect Squares
A Perfect Square, in algebra, refers to the product of an integer with itself. Common example: \(x^2\) is a perfect square because it is simply \(x\times x\).
In our case, the number 49 is a perfect square, since 49 equals \(7^2\).
Recognizing perfect squares assists in simplifying and solving algebraic expressions easily.
Consider the expression: 64, \(x^2\), 100. All are perfect squares because
In our case, the number 49 is a perfect square, since 49 equals \(7^2\).
Recognizing perfect squares assists in simplifying and solving algebraic expressions easily.
Consider the expression: 64, \(x^2\), 100. All are perfect squares because
- 64 is \(8^2\),
- \(x^2\) is \(x\times x\),
- 100 is \(10^2\).
Algebraic Expression
An Algebraic Expression is a mathematical phrase that includes numbers, variables, and operators. It’s a toolkit for expressing various quantities.
The expression \(49 - a^2\) is a simple algebraic expression involving a subtraction of squares.
Understanding how to manipulate these expressions is essential for solving equations and simplifying problems.
Algebraic expressions can look like:
The expression \(49 - a^2\) is a simple algebraic expression involving a subtraction of squares.
Understanding how to manipulate these expressions is essential for solving equations and simplifying problems.
Algebraic expressions can look like:
- \(3x + 4\)
- \(x^2 - 5x + 6\)
- \(a^2 - b^2\)
Other exercises in this chapter
Problem 22
Factor the trinomial. $$ 2 x^{2}-x-3 $$
View solution Problem 22
State the degree of the monomial. $$ -c^{3} $$
View solution Problem 22
Find the greatest common factor of the terms and factor it out of the expression. \(24 t^{5}+6 t^{3}\)
View solution Problem 22
Factor the trinomial. $$ w^{2}+13 w+36 $$
View solution