Problem 22
Question
Factor completely. $$ 20 x 3-45 x $$
Step-by-Step Solution
Verified Answer
The completely factored form is \( 5x(2x - 3)(2x + 3) \).
1Step 1: Identify Common Factors
First, examine each term to identify any common factors. The expression is \( 20x^3 - 45x \). Both terms have a common factor of \( 5x \).
2Step 2: Factor Out the Greatest Common Factor
Factor out the greatest common factor (GCF), which is \( 5x \), from the expression. This gives:\[ 20x^3 - 45x = 5x(4x^2 - 9) \]
3Step 3: Recognize a Difference of Squares
The expression inside the parentheses, \( 4x^2 - 9 \), is a difference of squares. It can be written as \((2x)^2 - 3^2\).
4Step 4: Apply the Difference of Squares Formula
Factor \( 4x^2 - 9 \) using the difference of squares formula, \( a^2 - b^2 = (a - b)(a + b) \). Here, \( a = 2x \) and \( b = 3 \), so:\[ 4x^2 - 9 = (2x - 3)(2x + 3) \]
5Step 5: Combine and Write the Completely Factored Form
Combine the factors obtained to write the completely factored form of the original expression:\[ 20x^3 - 45x = 5x(2x - 3)(2x + 3) \]
Key Concepts
Greatest Common FactorDifference of SquaresAlgebraic Expressions
Greatest Common Factor
When we factor polynomials, the first thing to check for is the Greatest Common Factor (GCF). The GCF is the largest expression that can be factored out of each term in the polynomial.
This simplifies the expression and makes further factorization manageable. To find the GCF in the expression \(20x^3 - 45x\):
This step simplifies the polynomial and prepares it for other techniques like the difference of squares.
This simplifies the expression and makes further factorization manageable. To find the GCF in the expression \(20x^3 - 45x\):
- Look for the highest number that divides evenly into the coefficients (numbers in front) of each term. For \(20\) and \(45\), the highest common divisor is \(5\).
- Next, identify the common variables. Here, both terms include \(x\), and the smallest power of \(x\) is \(x^1\).
This step simplifies the polynomial and prepares it for other techniques like the difference of squares.
Difference of Squares
The difference of squares is a common structure in algebra that enables specific polynomial expressions to be factored easily. It relates to expressions where you have a subtraction between two perfect squares.
These take the form \(a^2 - b^2\), and can always be factored as \((a - b)(a + b)\). In the factored expression \(4x^2 - 9\):
Understanding and identifying a difference of squares can simplify complicated expressions swiftly, saving time and effort in solving algebraic equations.
These take the form \(a^2 - b^2\), and can always be factored as \((a - b)(a + b)\). In the factored expression \(4x^2 - 9\):
- Recognize \(4x^2\) as \((2x)^2\) and \(9\) as \(3^2\). So \(4x^2 - 9\) is a difference of squares, \((2x)^2 - (3)^2\).
- Apply the formula, letting \(a = 2x\) and \(b = 3\).
Understanding and identifying a difference of squares can simplify complicated expressions swiftly, saving time and effort in solving algebraic equations.
Algebraic Expressions
Algebraic expressions contain numbers, variables, and operations. They are the fundamental building blocks in algebra.
Factoring is a technique used to simplify algebraic expressions into their products by uncovering structures like common factors or special patterns such as the difference of squares.For instance, given the expression \(20x^3 - 45x\):
Through effective manipulation of algebraic expressions like this, many mathematical problems become more straightforward and tractable.
Factoring is a technique used to simplify algebraic expressions into their products by uncovering structures like common factors or special patterns such as the difference of squares.For instance, given the expression \(20x^3 - 45x\):
- We started by factoring out the GCF, \(5x\), reducing the complexity of the expression.
- Next, we identified and applied the difference of squares to further factor \(4x^2 - 9\) into \((2x - 3)(2x + 3)\).
Through effective manipulation of algebraic expressions like this, many mathematical problems become more straightforward and tractable.
Other exercises in this chapter
Problem 22
Solve. $$ (x+5)(x+1)=0 $$
View solution Problem 22
Factor. $$ 25 x 2+40 x+16 $$
View solution Problem 23
For two consecutive positive odd integers, the product of twice the smaller and the larger is \(126 .\) Find the integers.
View solution Problem 23
Factor completely. $$ 7 x 3-14 x $$
View solution