Problem 22
Question
Explain why a \(2 \times 2\) matrix will not have an inverse if either a column or a row contains all 0 s.
Step-by-Step Solution
Verified Answer
A \(2 \times 2\) matrix cannot have an inverse if it has an all-zero row or column because its determinant is zero.
1Step 1: Understanding Matrix Non-Invertibility
A matrix is non-invertible (or singular) if its determinant is zero. It's crucial to analyze how specific properties of a matrix lead to a zero determinant.
2Step 2: Evaluate Determinant Formula for a 2x2 Matrix
For a general \(2 \times 2\) matrix: \(\begin{pmatrix} a & b \ c & d \end{pmatrix}\), the determinant is calculated as \(ad - bc\). A non-zero determinant implies the matrix is invertible.
3Step 3: Assess Impact of All-Zero Row or Column
If one row or column of a \(2 \times 2\) matrix is all zeros, substitute zero values into the determinant formula. For an all-zero row: \(\begin{pmatrix} 0 & 0 \ c & d \end{pmatrix}\) yields a determinant of \(0 \times d - 0 \times c = 0\). For an all-zero column: \(\begin{pmatrix} a & b \ 0 & 0 \end{pmatrix}\) yields a determinant of \(a \times 0 - b \times 0 = 0\).
4Step 4: Conclusion on Non-Invertibility
The determinant is zero in both cases, confirming that having a row or a column of all zeros makes the matrix singular, meaning it does not have an inverse.
Key Concepts
2x2 matricesdeterminant calculationsingular matrix
2x2 matrices
A 2x2 matrix is a simple yet fundamental concept in linear algebra. This type of matrix has two rows and two columns, making it easy to visualize and work with. As such, it is represented as:
- \( \begin{pmatrix} a & b \ c & d \end{pmatrix} \)
determinant calculation
Calculating the determinant of a 2x2 matrix is a fundamental skill in matrix algebra. The determinant, essentially a special scalar, provides insights into the matrix's properties. For a general 2x2 matrix:
- \( \begin{pmatrix} a & b \ c & d \end{pmatrix} \)
singular matrix
A matrix is described as singular when it does not have an inverse. For a 2x2 matrix, this occurs when its determinant equals zero. A singular matrix usually arises when the matrix has been improperly defined—such as having a row or a column consisting entirely of zeros:
- \( \begin{pmatrix} 0 & 0 \ c & d \end{pmatrix} \) or \( \begin{pmatrix} a & b \ 0 & 0 \end{pmatrix} \)
Other exercises in this chapter
Problem 22
Each augmented matrix is in row echelon form and represents a linear system. Use back-substitution to solve the system if possible. $$\left[\begin{array}{rr|r}
View solution Problem 22
Find the partial fraction decomposition for each rational expression. $$\frac{6 x^{5}+7 x^{4}-x^{2}+2 x}{3 x^{2}+2 x-1}$$
View solution Problem 22
Perform each operation if possible. $$\left[\begin{array}{rr}12 & -5 \\ 10 & 3\end{array}\right]-\left[\begin{array}{rr}6 & 9 \\ -2 & 0\end{array}\right]$$
View solution Problem 22
Solve each system analytically. If the equations are dependent, write the solution set in terms of the variable \(z\). $$\begin{aligned} 2 x-5 y+4 z &=-35 \\ 5
View solution