Problem 22
Question
Explain how the graph of \(f\) can be obtained from the graph of \(y=\frac{1}{x}\) or \(y=\frac{1}{x^{2}}\) Draw a sketch of the graph of \(f\) by hand. Then generate an accurate depiction of the graph with a graphing calculator. Finally, give the domain and range. $$f(x)=\frac{1}{x}-2$$
Step-by-Step Solution
Verified Answer
Shift the hyperbola down 2 units, domain: \(x \neq 0\), range: \(y \neq -2\).
1Step 1: Understand the Parent Function
The parent function for this exercise is \(y = \frac{1}{x}\). This hyperbola has two branches that hug the x-axis and y-axis, with vertical and horizontal asymptotes at \(x = 0\) and \(y = 0\), respectively. Understanding its shape helps us visualize the transformations applied to it.
2Step 2: Determine the Transformation
The function given is \(f(x) = \frac{1}{x} - 2\). This represents a vertical shift downward by 2 units from the graph of \(y = \frac{1}{x}\). Hence, the asymptote that was originally at \(y = 0\) is now at \(y = -2\).
3Step 3: Sketch the Transformed Graph
To sketch the graph, start by drawing the basic hyperbola of \(y = \frac{1}{x}\). Then, shift the entire graph down by 2 units. Ensure the vertical asymptote remains at \(x = 0\) but the horizontal asymptote is now at \(y = -2\).
4Step 4: Use a Graphing Calculator
Input \(f(x) = \frac{1}{x} - 2\) into a graphing calculator to see an accurate depiction of the graph. Observe the transformation confirms the vertical shift downward and check if the asymptotes are correctly positioned.
5Step 5: Determine Domain and Range
The domain of \(f(x) = \frac{1}{x} - 2\) is all real numbers except \(x = 0\) (where the function is undefined), written as \(x eq 0\). The range consists of all real numbers except \(y = -2\) (the new horizontal asymptote), written as \(y eq -2\).
Key Concepts
HyperbolaVertical ShiftDomain and RangeGraphing Calculator
Hyperbola
A hyperbola is a type of curve on a graph that looks like two mirrored arcs facing away from each other. A basic hyperbola, such as the graph of the function \( y = \frac{1}{x} \), has two parts, or branches, that approach the x-axis and y-axis,but never touch them.These axes are called asymptotes when they act as boundaries that the graph gets very close to, but never crosses.In the parent hyperbola \( y = \frac{1}{x} \):
- The vertical asymptote is at \( x = 0 \)
- The horizontal asymptote is at \( y = 0 \)
Vertical Shift
A vertical shift occurs when every point on a graph moves up or down by a certain number of units. For instance, if we alter \( y = \frac{1}{x} \) by subtracting 2, resulting in \( f(x) = \frac{1}{x} - 2 \), we perform a vertical shift downward by 2 units.In this transformation:
- The vertical asymptote remains unchanged at \( x = 0 \)
- The horizontal asymptote moves from \( y = 0 \) to \( y = -2 \)
Domain and Range
Understanding the domain and range of a function is essential in defining its behavior. For the function \( f(x) = \frac{1}{x} - 2 \), the domain consists of all the values \( x \) can take. However, since dividing by zero is undefined,\( x \) cannot be zero, thus the domain is all real numbers except \( x = 0 \).This means we write: \( x eq 0 \).For the range, which includes all the possible values of \( y \), any horizontal line drawn to intersect the graph will not touch the asymptote.Since the horizontal asymptote is at \( y = -2 \), the function's range is all real numbers except \( y = -2 \).Thus, it is represented as: \( y eq -2 \). This understanding helps us to see where the graph of the function exists on the coordinate plane.
Graphing Calculator
Using a graphing calculator is a helpful way to visualize complex functions, like hyperbolas.When you put \( f(x) = \frac{1}{x} - 2 \) into the calculator, it automatically generates a graph,allowing you to observe the transformation clearly.Check these points while using the graphing calculator:
- Verify the vertical asymptote is still at \( x = 0 \)
- Ensure that the horizontal asymptote has shifted to \( y = -2 \)
Other exercises in this chapter
Problem 22
Find all complex solutions for each equation by hand. Do not use a calculator. $$\frac{2 x}{x-3}+\frac{4}{x}-6=0$$
View solution Problem 22
Solve each equation by hand. Do not use a calculator. $$x^{2 / 3}=16$$
View solution Problem 23
Use positive rational exponents to rewrite each expression. Assume variables represent positive numbers. $$\sqrt[3]{z^{5}}$$
View solution Problem 23
Find all complex solutions for each equation by hand. Do not use a calculator. $$x^{-4}-3 x^{-2}-4=0$$
View solution