Problem 22
Question
Expand each expression using the Binomial Theorem. $$ (2 x+3)^{5} $$
Step-by-Step Solution
Verified Answer
\( (2x+3)^5 = 32x^5 + 240x^4 + 720x^3 + 1080x^2 + 810x + 243 \)
1Step 1: Understand the Binomial Theorem
The Binomial Theorem states that \[ (a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k \] . Here, \( a = 2x \), \( b = 3 \), and \( n = 5 \).
2Step 2: Identify the terms for the formula
Using the values identified: \( a = 2x \), \( b = 3 \), and \( n = 5 \) , we will expand \( (2x + 3)^5 \).
3Step 3: Calculate the binomial coefficients
Calculate \( \binom{5}{k} \) for all values of \( k \) from 0 to 5. These are the coefficients for each term in the expansion: \[ \binom{5}{0} = 1 \quad \binom{5}{1} = 5 \quad \binom{5}{2} = 10 \quad \binom{5}{3} = 10 \quad \binom{5}{4} = 5 \quad \binom{5}{5} = 1 \] .
4Step 4: Apply the Binomial Theorem
Plug in the values into the Binomial Theorem: \[ (2x + 3)^5 = \binom{5}{0} (2x)^{5} (3)^{0} + \binom{5}{1} (2x)^{4} (3)^{1} + \binom{5}{2} (2x)^{3} (3)^{2} + \binom{5}{3} (2x)^{2} (3)^{3} + \binom{5}{4} (2x)^{1} (3)^{4} + \binom{5}{5} (2x)^{0} (3)^{5} \] .
5Step 5: Simplify each term
Simplify each term step by step: \[ (2x + 3)^5 = 1 \cdot (2x)^{5} \cdot 1 + 5 \cdot (2x)^{4} \cdot 3 + 10 \cdot (2x)^{3} \cdot 9 + 10 \cdot (2x)^{2} \cdot 27 + 5 \cdot (2x)^{1} \cdot 81 + 1 \cdot (2x)^{0} \cdot 243 \] .
6Step 6: Finalize the calculations
Perform the final multiplications and powers for each term: \[ (2x + 3)^5 = 32x^5 + 240x^4 + 720x^3 + 1080x^2 + 810x + 243 \] .
Key Concepts
Binomial TheoremBinomial CoefficientsPolynomial ExpansionExponentiation
Binomial Theorem
Binomial Theorem is a fundamental principle used to expand expressions that are raised to a power. It states that any binomial expression \[ (a + b)^n \] can be expanded into a sum involving terms of the form \[ \binom{n}{k} a^{n-k} b^k \]. The binomial theorem allows us to write out the polynomial expansion without directly multiplying the terms repeatedly. In our example, we expanded \[ (2x + 3)^5 \] using the binomial theorem.
To break it down:
To break it down:
- \[ a \] and \[ b \] are the terms inside the binomial (here, \[ 2x \] and \[ 3 \]).
- \[ n \] is the power to which the binomial is raised (in this case, 5). This exponent tells us the number of terms in the expansion.
Binomial Coefficients
Binomial Coefficients are the numbers that appear in the binomial theorem expansion. They are represented as \[ \binom{n}{k} \] and are calculated using the formula:
In our example, for \[ (2x + 3)^5 \], the binomial coefficients are \[ \binom{5}{0}, \binom{5}{1}, \binom{5}{2}, \binom{5}{3}, \binom{5}{4}, \] and \[ \binom{5}{5} \]. Each coefficient multiplies the corresponding terms in the binomial expansion.
These coefficients are crucial since they determine the weight and contribution of each term in the expanded form. They also ensure the balance and symmetry in the polynomial expressions.
- \[ \binom{n}{k} = \frac{n!}{k!(n-k)!} \]
In our example, for \[ (2x + 3)^5 \], the binomial coefficients are \[ \binom{5}{0}, \binom{5}{1}, \binom{5}{2}, \binom{5}{3}, \binom{5}{4}, \] and \[ \binom{5}{5} \]. Each coefficient multiplies the corresponding terms in the binomial expansion.
These coefficients are crucial since they determine the weight and contribution of each term in the expanded form. They also ensure the balance and symmetry in the polynomial expressions.
Polynomial Expansion
Polynomial Expansion involves breaking down a polynomial expression into a sum of simpler polynomials. When we expand \[ (2x + 3)^5 \] using the binomial theorem, we get a sum of several simpler polynomials:
- \[ (2x + 3)^5 = 32x^5 + 240x^4 + 720x^3 + 1080x^2 + 810x + 243 \]
Exponentiation
Exponentiation refers to the operation of raising a number or expression to a given power. It is a fundamental concept in mathematics, especially in algebra. In our binomial theorem example, we dealt with exponentiating the terms \[ 2x \] and 3 in each phrase of the expansion. For instance:
In the final result for our example, each term is formed by multiplying the binomial coefficient, the exponential powers of the first term \[ 2x \], and the exponential powers of the second term (constant) 3. Mastery of exponentiation helps with accuracy and simplifies polynomial and algebraic solutions.
- \[ (2x)^5 = 32x^5 \]
- \[ (3)^1 = 3 \]
- \[ (3)^2 = 9 \]
In the final result for our example, each term is formed by multiplying the binomial coefficient, the exponential powers of the first term \[ 2x \], and the exponential powers of the second term (constant) 3. Mastery of exponentiation helps with accuracy and simplifies polynomial and algebraic solutions.
Other exercises in this chapter
Problem 21
Find the nth term of the arithmetic sequence \(\left\\{a_{n}\right\\}\) whose first term \(a_{1}\) and common difference d are given. What is the 51st term? $$
View solution Problem 22
Use the Principle of Mathematical Induction to show that the given statement is true for all natural numbers \(n\). $$ n(n+1)(n+2) \text { is divisible by } 6 $
View solution Problem 22
Find the fifth term and the nth term of the geometric sequence whose first term \(a_{1}\) and common ratio \(r\) are given. $$ a_{1}=6 ; \quad r=-2 $$
View solution Problem 22
List the first five terms of each sequence. \(\left\\{s_{n}\right\\}=\left\\{\left(\frac{4}{3}\right)^{n}\right\\}\)
View solution