Problem 22
Question
Exercises \(17-30\) contain equations with constants in denominators. Solve each equation. $$ \frac{x}{2}=\frac{3 x}{4}+5 $$
Step-by-Step Solution
Verified Answer
The solution to the equation is \(x = -20\).
1Step 1: Identify the LCM and Multiply Every Term
The LCM of 2 and 4 is 4. So, multiply every term by 4 to get rid of the fractions. The equation will then be \(4*\frac{x}{2} = 4*\frac{3x}{4} + 4*5\). This simplifies to \(2x = 3x + 20\).
2Step 2: Move Variable to One Side of the Equation
Create a new equation with \(x\) on one side by subtracting \(3x\) from both sides, resulting in \(-x = 20\).
3Step 3: Solve for x
Finally, multiply both sides of the equation by -1 to get x on its own, resulting in \(x = -20\).
Key Concepts
Least Common MultipleVariable IsolationFraction Elimination
Least Common Multiple
When dealing with equations containing fractions, it becomes crucial to simplify them as much as possible. One effective technique is using the Least Common Multiple (LCM). The LCM of two numbers is the smallest number that both can divide into without leaving a remainder. For instance, in the equation \( \frac{x}{2} = \frac{3x}{4} + 5 \), we identify the denominators, 2 and 4. Finding the LCM involves listing the multiples of both numbers until we find the smallest common one.
- The multiples of 2 are: 2, 4, 6, 8, etc.
- The multiples of 4 are: 4, 8, 12, 16, etc.
Variable Isolation
After clearing fractions in an equation, the next step is variable isolation. This process involves getting the variable on one side of the equation by itself. From the equation \(2x = 3x + 20\), we want all terms with the variable \(x\) on just one side. To do this, we perform operations that move terms around:
- Subtract \(3x\) from both sides, which gives us \(-x = 20\).
Fraction Elimination
Eliminating fractions from equations can make solving them much simpler. This process converts the equations into more comfortable forms to handle. Using our example, the original equation \(\frac{x}{2} = \frac{3x}{4} + 5\) contained fractions. By multiplying each term by the LCM of the denominators (which we've decided was 4), the equation becomes:
By clearing the fractions early on, we execute "Fraction Elimination," making the equations simpler to manipulate, paving the way for straightforward algebraic operations that lead to an answer. Hence, always address the fractions first for smooth sailing through the rest of the solution!
- \(4 \cdot \frac{x}{2} = 4 \cdot \frac{3x}{4} + 4 \cdot 5\)
By clearing the fractions early on, we execute "Fraction Elimination," making the equations simpler to manipulate, paving the way for straightforward algebraic operations that lead to an answer. Hence, always address the fractions first for smooth sailing through the rest of the solution!
Other exercises in this chapter
Problem 22
Solve each equation in Exercises \(15-26\) by the square root method. $$(4 x-1)^{2}=16$$
View solution Problem 22
In Exercises 13-26, express each interval in terms of an inequality and graph the interval on a number line. $$[-5, \infty)$$
View solution Problem 23
In Exercises \(21-28,\) divide and express the result in standard form. $$\frac{2 i}{1+i}$$
View solution Problem 23
Solve each quadratic inequality in Exercises \(1-28\) and graph the solution set on a real number line. Express each solution set in interval notation. $$ 2 x^{
View solution