Problem 22
Question
Evaluate the function for the given value of x. $$y=\sqrt{32 x} ; 2$$
Step-by-Step Solution
Verified Answer
The value of the function \(y = \sqrt{32x}\) at the point \(x = 2\) is 8.
1Step 1: Substitute x into the function
To find the value of the function \(y\) at the point \(x = 2\), substitute \(2\) into the equation wherever \(x\) appears. This gives us: \(y = \sqrt{32*2}\) = \( \sqrt{64} \).
2Step 2: Simplify the Square Root
The next step is to simplify the square root. The square root of 64 is 8. So, \(y = 8\).
Key Concepts
Square RootsFunction SubstitutionSimplifying Expressions
Square Roots
Square roots are fundamental in mathematics and are often encountered when dealing with quadratic equations and functions. A square root asks the question: what number, when multiplied by itself, results in the given number? For example, the square root of 64, denoted as \( \sqrt{64} \), is 8 because \( 8 \times 8 = 64 \).
When you encounter a square root in an expression, the goal is usually to simplify it by finding the positive number that, when squared, returns to the original value under the square root symbol. These roots are useful in various calculations, especially when dealing with geometrical problems or physics equations.
When you encounter a square root in an expression, the goal is usually to simplify it by finding the positive number that, when squared, returns to the original value under the square root symbol. These roots are useful in various calculations, especially when dealing with geometrical problems or physics equations.
- Remember: the square root of zero is always zero.
- The square root is only defined for non-negative numbers in the realm of real numbers.
Function Substitution
Function substitution is a basic operation in algebra where you replace a variable with a given number. This is essential for finding specific values of functions at certain inputs. For instance, given \( y = \sqrt{32x} \) and \( x = 2 \), you substitute 2 for every instance of \( x \).
This substitution turns \( y = \sqrt{32x} \) into \( y = \sqrt{32 \times 2} \) which simplifies further. Function substitution is crucial because it allows us to evaluate or solve functions for specific inputs, thus providing clear and concrete results.
This substitution turns \( y = \sqrt{32x} \) into \( y = \sqrt{32 \times 2} \) which simplifies further. Function substitution is crucial because it allows us to evaluate or solve functions for specific inputs, thus providing clear and concrete results.
- Always ensure the value you're substituting fits the domain of the function.
- Double-check your substitution to make sure all instances of the variable have been replaced.
Simplifying Expressions
Simplifying expressions is a central skill in algebra. It involves reducing expressions into their most basic form while keeping their value intact. This skill is critical in solving equations efficiently and accurately.
In our example, after substituting \( x = 2 \) into \( y = \sqrt{32x} \), you are left with \( y = \sqrt{64} \). Simplifying that involves recognizing that 64 is a perfect square, so \( \sqrt{64} = 8 \).
In our example, after substituting \( x = 2 \) into \( y = \sqrt{32x} \), you are left with \( y = \sqrt{64} \). Simplifying that involves recognizing that 64 is a perfect square, so \( \sqrt{64} = 8 \).
- Look for common factors or patterns in numbers to simplify quicker.
- Always aim to express answers in the simplest form possible for clarity.
Other exercises in this chapter
Problem 22
Simplify the expression. $$ \sqrt{72}-\sqrt{18} $$
View solution Problem 22
Solve the equation. $$ \sqrt{x}-15=0 $$
View solution Problem 23
Find the distance between the two points. Round your solution to the nearest hundredth if necessary. $$ (4,11),(-5,2) $$
View solution Problem 23
USING THE PYTHAGOREAN THEOREM Find the missing length of the right triangle if \(a\) and \(b\) are the lengths of the legs and \(c\) is the length of the hypote
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