Problem 22
Question
Draw the Lewis structure for CIF \(_{3}\). What are its electronpair and molecular geometries? What is the hybridization of the chlorine atom? What orbitals on Cl and F overlap to form bonds between these elements?
Step-by-Step Solution
Verified Answer
The hybridization of chlorine is sp^3d, electron pair geometry is trigonal bipyramidal, and the molecular shape is T-shaped.
1Step 1: Count Valence Electrons
Calculate the total number of valence electrons for ClF
e_3.
Chlorine (Cl) has 7 valence electrons, and each Fluorine (F) has 7 valence electrons. Adding these up,
we get: 7 (for Cl) + 3×7 (for F) = 28 valence electrons.
2Step 2: Arrange Atoms and Form Initial Bonds
Place the chlorine (Cl) atom in the center since it is less electronegative than fluorine (F). Place three fluorine atoms around the chlorine. Form a single bond between Cl and each F atom, which uses 6 electrons from the total (2 electrons per bond).
3Step 3: Distribute Remaining Electrons
After forming bonds, you have 28 - 6 = 22 electrons remaining. Distribute these electrons to satisfy the octet rule, starting with the more electronegative atoms (fluorine). Place 6 additional electrons (in the form of lone pairs) around each F atom. This uses 18 electrons, leaving 4 electrons.
4Step 4: Complete Chlorine's Octet
Assign the remaining 4 electrons to chlorine as lone pairs. So, each of the outer fluorine atoms has 3 lone pairs, and chlorine will have 2 lone pairs as well.
5Step 5: Determine Electron Pair and Molecular Geometry
The chlorine atom has 3 bond pairs with fluorines and 2 lone pairs.
For electron pair geometry, count all regions of electron density (5 total: 3 bonds + 2 lone pairs), giving a trigonal bipyramidal geometry.
The molecular geometry, considering only atoms, is T-shaped due to the presence of 2 lone pairs on chlorine.
6Step 6: Identify Hybridization of Chlorine
The hybridization corresponds to the number of electron regions around chlorine. For 5 regions, the hybridization is
sp^3d.
7Step 7: Determine Orbital Overlap
The orbitals that overlap to form the Cl-F bonds are the sp^3d hybrid orbitals of Cl with the p orbitals of each F atom.
Key Concepts
Electron Pair GeometryMolecular GeometryHybridizationOrbital Overlap
Electron Pair Geometry
Electron pair geometry plays a pivotal role in understanding the 3D arrangement of molecules. For ClF extsubscript{3}, we start by considering all regions of electron density around the central chlorine atom. These regions include both bonding pairs and lone pairs of electrons. Each bond or lone pair counts as one region of electron density.
In ClF extsubscript{3}, there are three bonds connecting chlorine to fluorine atoms and two lone pairs on chlorine, making for a total of five regions of electron density. The arrangement that minimizes repulsion among these five regions of electron density is trigonal bipyramidal. This geometry is common in molecules with a steric number of five and gives a clear idea about the spatial orientation of electron clouds around the central atom.
In ClF extsubscript{3}, there are three bonds connecting chlorine to fluorine atoms and two lone pairs on chlorine, making for a total of five regions of electron density. The arrangement that minimizes repulsion among these five regions of electron density is trigonal bipyramidal. This geometry is common in molecules with a steric number of five and gives a clear idea about the spatial orientation of electron clouds around the central atom.
- The five electron densities form a trigonal bipyramidal shape.
- This includes three equatorial regions and two axial regions.
Molecular Geometry
Molecular geometry is slightly different from electron pair geometry, as it only considers the positions of atoms and excludes lone pairs. In ClF extsubscript{3}, although the electron pair geometry is trigonal bipyramidal, the molecular geometry is T-shaped because of the effect of the lone pairs.
The lone pairs take up more space and repel the bonded atoms, effectively pushing them into a T-shaped configuration.
The lone pairs take up more space and repel the bonded atoms, effectively pushing them into a T-shaped configuration.
- The presence of two lone pairs on chlorine affects molecular geometry.
- This results in fluorine atoms forming a T shape around the chlorine.
Hybridization
Hybridization is a concept that explains the mixing of atomic orbitals to form new hybrid orbitals. These hybrid orbitals are used in bonding with other atoms and can describe the geometry of a molecule.
In ClF extsubscript{3}, the chlorine atom undergoes sp extsuperscript{3}d hybridization. This hybridization involves the mixing of one s orbital, three p orbitals, and one d orbital, producing five sp extsuperscript{3}d orbitals. These hybrid orbitals help to accommodate the five regions of electron density around chlorine.
In ClF extsubscript{3}, the chlorine atom undergoes sp extsuperscript{3}d hybridization. This hybridization involves the mixing of one s orbital, three p orbitals, and one d orbital, producing five sp extsuperscript{3}d orbitals. These hybrid orbitals help to accommodate the five regions of electron density around chlorine.
- Chlorine atom hybridizes its orbitals to form five sp extsuperscript{3}d hybrid orbitals.
- This supports the trigonal bipyramidal electron geometry.
Orbital Overlap
Orbital overlap is a fundamental concept that describes how bonds are formed between atoms. It involves the spatial interaction and overlap of atomic or hybrid orbitals.
In ClF extsubscript{3}, the chlorine’s sp extsuperscript{3}d hybrid orbitals overlap with fluorine's p orbitals to create sigma bonds.
These sigma bonds are the primary connections holding the atoms together in the molecule.
In ClF extsubscript{3}, the chlorine’s sp extsuperscript{3}d hybrid orbitals overlap with fluorine's p orbitals to create sigma bonds.
These sigma bonds are the primary connections holding the atoms together in the molecule.
- Chlorine's sp extsuperscript{3}d orbitals overlap with the p orbitals of fluorine.
- This effective overlap creates stable sigma bonds.
Other exercises in this chapter
Problem 16
Give the electron configurations for the ions \(\mathrm{Li}_{2}^{+}\) and \(\mathrm{Li}_{2}^{-}\) in molecular orbital terms. Compare the \(\mathrm{Li}-\mathrm{
View solution Problem 18
Oxygen, \(\mathrm{O}_{2},\) can acquire one or two electrons to give \(\mathrm{O}_{2}^{-}\) (superoxide ion) or \(\mathrm{O}_{2}^{2-}\) (peroxide ion). Write th
View solution Problem 23
Describe the \(\mathrm{O}-\mathrm{S}-\mathrm{O}\) angle and the hybrid orbital set used by sulfur in each of the following molecules or ions: (a) \(\mathrm{SO}_
View solution Problem 24
Sketch the Lewis structures of \(\mathrm{ClF}_{2}^{+}\) and \(\mathrm{ClF}_{2}^{-} .\) What are the electron-pair and molecular geometries of each ion? Do both
View solution