Problem 22
Question
Determine whether the series is convergent or divergent. If it is convergent, find its sum. $$\sum_{k=1}^{\infty}(\cos 1)^{k}$$
Step-by-Step Solution
Verified Answer
The series is convergent with sum approximately 1.175.
1Step 1: Recognize the series type
The series given is \( \sum_{k=1}^{\infty}(\cos 1)^{k} \). Since each term is of the form \((\cos 1)^k\), where \(\cos 1\) is a constant, this is a geometric series with the first term \(a = (\cos 1)^1 = \cos 1\) and common ratio \(r = \cos 1\).
2Step 2: Check the convergence criteria for a geometric series
A geometric series \(\sum_{k=0}^{\infty} ar^k\) is convergent if and only if \(|r| < 1\). Here, \(|r| = |\cos 1| < 1\) since \(\cos 1 \approx 0.5403\), which is less than 1. Hence, the series is convergent.
3Step 3: Use the formula for the sum of a convergent geometric series
The sum \(S\) of an infinite geometric series with first term \(a\) and common ratio \(|r| < 1\) is given by the formula \(S = \frac{a}{1-r}\). Here, \(a = \cos 1\) and \(r = \cos 1\), so the sum is \(S = \frac{\cos 1}{1 - \cos 1}\).
4Step 4: Calculate the value of the sum
Substitute the approximate value of \(\cos 1 \approx 0.5403\) into the formula to find the sum: \[ S = \frac{0.5403}{1 - 0.5403} \approx \frac{0.5403}{0.4597} \approx 1.175 \]. So, the sum is approximately 1.175.
Key Concepts
Geometric Series ConvergenceInfinite Series SumSeries Convergence Criteria
Geometric Series Convergence
A geometric series occurs when each term in the series is derived by multiplying the previous term by a constant, known as the common ratio \( r \).
If we express it formally:
The convergence of a geometric series is strictly determined by its common ratio \( r \).
If we express it formally:
- The first term of the series is represented as \( a \).
- Each subsequent term is \( ar, ar^2, ar^3, \) and so on. This forms an infinite geometric series \( \sum_{k=0}^{\infty} ar^k \).
The convergence of a geometric series is strictly determined by its common ratio \( r \).
- A series will converge if the absolute value of the common ratio is \( |r| < 1 \).
- If \( |r| \geq 1 \), the series diverges and does not sum to a finite number.
Infinite Series Sum
Once it is determined that a geometric series converges, we can calculate its sum. This applies only to infinite series where the ratio \( |r| < 1 \).
The sum of the series can be calculated using the formula:
The sum of the series can be calculated using the formula:
- \( S = \frac{a}{1-r} \) where \( a \) represents the first term and \( r \) is the common ratio.
- \( a = \cos 1 \) is the first term
- \( r = \cos 1 \) is also the common ratio
Series Convergence Criteria
The convergence criteria for any series, including geometric ones, is a set of conditions that allow us to determine if the series approaches a specific value as more terms are added.
For geometric series, the convergence criterion is simple and crucial:
For geometric series, the convergence criterion is simple and crucial:
- If the absolute value of the common ratio \( |r| \) is less than 1, the series converges.
- Conversely, if \( |r| \geq 1 \), the series is divergent.
- The value of \( \cos 1 \approx 0.5403 \), which is within the convergent range \(|r| < 1\).
- This fulfillment of the convergence criterion ensures the series adds up to a calculable finite number.
Other exercises in this chapter
Problem 21
Find a power series representation for \(f,\) and graph \(f\) and several partial sums \(s_{a}(x)\) on the same screen. What happens as \(n\) increases? $$ f(x)
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Use the Alternating Series Estimation Theorem or Taylor's Formula to estimate the range of values of for which the given approximation is accurate to within the
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\(19-40=\) Determine whether the series is absolutely convergent, conditionally convergent, or divergent. $$ \sum_{n=1}^{\infty}(-1)^{n-1} \frac{n}{n^{2}+4} $$
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Find the radius of convergence and interval of convergence of the series. $$\sum_{n=1}^{\infty} \frac{n^{2} x^{n}}{2 \cdot 4 \cdot 6 \cdot \cdots \cdot(2 n)}$$
View solution