Problem 22
Question
Determine whether the planes \(a_{1} x+b_{1} y+c_{1} z=d_{1}\) and \(a_{2} x+b_{2} y+c_{2} z=d_{2}\) are parallel, perpendicular, or neither. The planes are parallel if there exists a nonzero constant \(k\) such that \(a_{1}=k a_{2}, b_{1}=k b_{2}\), and \(c_{1}=k c_{2},\) and are perpendicular if \(a_{1} a_{2}+b_{1} b_{2}+c_{1} c_{2}=0\). $$ 3 x+y-4 z=3,-9 x-3 y+12 z=4 $$
Step-by-Step Solution
Verified Answer
The planes \(3 x+y-4 z=3\) and \(-9 x-3 y+12 z=4\) are parallel.
1Step 1: Extract normal vectors from the plane equations
The normal vector to the plane is given by the coefficients of x, y, and z in the equation of the plane. For the first plane, this gives you a normal vector \((3, 1, -4)\). For the second plane, the normal vector is \(-9, -3, 12)\).
2Step 2: Test for parallel planes
Planes are parallel when one normal vector is a multiple of the other. In this case, the normal vector of the second plane is exactly three times the normal vector of the first plane. So the planes are parallel.
3Step 3: Confirm with the perpendicular condition
Perpendicular planes would have normal vectors that yield a zero dot product, but as the two planes have already been found to be parallel in the previous step, testing for perpendicularity isn't necessary. However, for completeness, let's calculate the dot product as well: \(3*-9 + 1*-3 - 4*12 = -27 - 3 - 48 = -78 \neq 0\). So, as expected, the planes are not perpendicular.
Key Concepts
Parallel PlanesPerpendicular PlanesNormal Vectors
Parallel Planes
In plane geometry, understanding the concept of parallel planes is crucial for spatial reasoning. Parallel planes are always equidistant from each other and never intersect. The test for whether two planes are parallel involves comparing their normal vectors. Each plane in the equation form \(a_1 x + b_1 y + c_1 z = d_1\) has a normal vector extracted from the coefficients \((a_1, b_1, c_1)\).
To determine if two planes are parallel:
To determine if two planes are parallel:
- The normal vector of one plane must be a scalar multiple of the other.
- Mathematically, this means there is a constant \(k\) such that \(a_1 = k a_2\), \(b_1 = k b_2\), and \(c_1 = k c_2\).
Perpendicular Planes
Perpendicular planes in geometry are planes that intersect such that their intersection forms a right angle. The test for perpendicularity between two planes involves the dot product of their normal vectors.
When two planes are perpendicular:
When two planes are perpendicular:
- Their normal vectors' dot product is zero.
- The dot product for normal vectors \((a_1, b_1, c_1)\) and \((a_2, b_2, c_2)\) is calculated as \(a_1 a_2 + b_1 b_2 + c_1 c_2\).
Normal Vectors
Normal vectors are fundamental to understanding the orientation of planes in geometry. They are perpendicular to their respective planes and provide a concise way to describe the plane's direction and its orientation in space. Derived from the plane's equation coefficients, the normal vector \((a, b, c)\) succinctly encodes this geometric information.
The role of normal vectors includes:
The role of normal vectors includes:
- Determining parallelism or perpendicularity of planes by analyzing vector relationships.
- Providing critical insights into the spatial organization and orientation of multiple planes.
- Assisting in calculations involving intersections and angles between planes.
Other exercises in this chapter
Problem 22
Evaluate \(f_{x}\) and \(f_{y}\) at the point. $$ \text { Function } \quad \text { Point } $$ $$ f(x, y)=x^{2}-3 x y+y^{2} \quad(1,-1) $$
View solution Problem 22
Use Lagrange multipliers to find the given extremum of \(f\) subject to two constraints. In each case, assume that \(x, y,\) and \(z\) are nonnegative. $$ \begi
View solution Problem 23
In Exercises \(23-26,\) use a double integral to find the volume of the solid bounded by the graphs of the equations. $$ z=x y, z=0, y=0, y=4, x=0, x=1 $$
View solution Problem 23
Determine whether there is a relative maximum, a relative minimum, a saddle point, or insufficient information to determine the nature of the function \(f(x, y)
View solution