Problem 22
Question
Determine whether the equation represents \(y\) as a function of \(x.\) $$y=\sqrt{x+5}$$
Step-by-Step Solution
Verified Answer
Yes, the equation \(y=\sqrt{x+5}\) represents \(y\) as a function of \(x\) because every value of \(x\) yields a unique value of \(y\).
1Step 1: Determine the domain
\(y = \sqrt{x+5}\) is defined when \(x + 5 \geq 0\), i.e., \(x \geq -5\).
2Step 2: Check the function criterion
For each \(x \geq -5\), the square root \(\sqrt{x+5}\) produces exactly one non-negative value. Therefore, each input \(x\) yields a unique output \(y\).
\(y = \sqrt{x+5}\) \(\textbf{does}\) represent \(y\) as a function of \(x\).
\(y = \sqrt{x+5}\) \(\textbf{does}\) represent \(y\) as a function of \(x\).
Key Concepts
FunctionsDomain and RangeSquare Roots
Functions
Functions are fundamental concepts in algebra and mathematics as a whole. In simple terms, a function is a special relationship where each input has a unique output. Essentially, for a given input, you should always get the same output every time.
To determine if an equation is a function, you need to check if every input results in exactly one output. An easy way to visualize this is by using the "vertical line test" on a graph. If a vertical line crosses the graph more than once at any point, it's not a function. However, in many cases, especially when working with equations, this test can be done algebraically.
For the equation given in the exercise, \(y=\sqrt{x+5}\), each \(x\) value within a specified range gives one and only one \(y\) value. This aspect makes the equation a function because, in its domain, no \(x\) maps to multiple values of \(y\).
To determine if an equation is a function, you need to check if every input results in exactly one output. An easy way to visualize this is by using the "vertical line test" on a graph. If a vertical line crosses the graph more than once at any point, it's not a function. However, in many cases, especially when working with equations, this test can be done algebraically.
For the equation given in the exercise, \(y=\sqrt{x+5}\), each \(x\) value within a specified range gives one and only one \(y\) value. This aspect makes the equation a function because, in its domain, no \(x\) maps to multiple values of \(y\).
Domain and Range
When talking about functions, the domain and range are important concepts to grasp. The domain of a function is the complete set of possible values of the independent variable \(x\). In simpler terms, it is the list of "allowable" inputs into your function. For the equation \(y=\sqrt{x+5}\), the domain is \([-5, \infty)\). This is because \(x+5\) must not be negative inside the square root for real numbers; it needs to be zero or greater.
On the other hand, the range includes all possible outputs (or results) for the \(y\) values. For the equation \(y=\sqrt{x+5}\), since square roots of positive numbers or zero are always non-negative, \(y\) must be greater than or equal to zero. Thus, the range is \([0, \infty)\).
On the other hand, the range includes all possible outputs (or results) for the \(y\) values. For the equation \(y=\sqrt{x+5}\), since square roots of positive numbers or zero are always non-negative, \(y\) must be greater than or equal to zero. Thus, the range is \([0, \infty)\).
- The domain answers: "What \(x\) values can I use?"
- The range answers: "What \(y\) values can I get?"
Square Roots
Square roots are a key mathematical concept and are involved when you need to find a number that multiplies by itself to achieve a given value. In simpler terms, if \(y\) is the square root of \(x\), then \(y \times y = x\).
The square root function is denoted by the radical symbol \(\sqrt{}\). It's crucial in our equation \(y=\sqrt{x+5}\). Here are a few important points to consider:
The square root function is denoted by the radical symbol \(\sqrt{}\). It's crucial in our equation \(y=\sqrt{x+5}\). Here are a few important points to consider:
- The expression under the square root \(\sqrt{x+5}\) should never be negative in the realm of real numbers because a square root of a negative number becomes imaginary.
- This affects the domain since \(x \geq -5\) is needed to keep \(x+5 \geq 0\).
- Square roots produce non-negative numbers, resulting in a range starting at zero.
Other exercises in this chapter
Problem 22
Evaluate the indicated function for \(f(x)=x^{2}-1\) and \(g(x)=x-2\) algebraically. If possible, use a graphing utility to verify your answer. $$(f+g)(1)$$
View solution Problem 22
Show that \(f\) and \(g\) are inverse functions algebraically. Use a graphing utility to graph \(f\) and \(g\) in the same viewing window. Describe the relation
View solution Problem 23
Determine the open intervals on which the function is increasing, decreasing, or constant. $$f(x)=\frac{3}{2} x$$
View solution Problem 23
Show that \(f\) and \(g\) are inverse functions algebraically. Use a graphing utility to graph \(f\) and \(g\) in the same viewing window. Describe the relation
View solution