Problem 22
Question
Classify each series as absolutely convergent, conditionally convergent, or divergent. $$ \sum_{n=1}^{\infty}(-1)^{n+1} \frac{n-1}{n} $$
Step-by-Step Solution
Verified Answer
The series is divergent.
1Step 1: Identify the Series Type
The given series is \( \sum_{n=1}^{\infty}(-1)^{n+1} \frac{n-1}{n} \). This is an alternating series because of the factor \((-1)^{n+1}\).
2Step 2: Check Alternating Series Test Conditions
For the alternating series \( \sum (-1)^{n+1} b_n \), it will converge if \( b_n \to 0 \) as \( n \to \infty \) and \( b_{n+1} \leq b_n \) for all \( n \). Here, \( b_n = \frac{n-1}{n} \).
3Step 3: Check Convergence of \( b_n \)
As \( n \to \infty \), \( b_n = \frac{n-1}{n} \to 1 \). Since \( b_n \) does not approach 0, the alternating series test cannot be used to show convergence.
4Step 4: Absolute Convergence Test
A series \( \sum a_n \) is absolutely convergent if \( \sum |a_n| \) converges. Check if \( \sum_{n=1}^{\infty} \left| (-1)^{n+1} \frac{n-1}{n} \right| = \sum_{n=1}^{\infty} \frac{n-1}{n} \) converges.
5Step 5: Determine Divergence of \( \sum \frac{n-1}{n} \)
The series \( \sum \frac{n-1}{n} \) simplifies to \( \sum \left(1 - \frac{1}{n}\right) \). This diverges, as it is a Harmonic series minus a divergent constant series.
6Step 6: Conclusion on Convergence
Since the series fails the alternating series test and is not absolutely convergent (as the absolute value series diverges), it is divergent.
Key Concepts
Series ConvergenceAbsolute ConvergenceHarmonic SeriesAlternating Series Test
Series Convergence
Understanding series convergence is crucial for analyzing whether a series sums up to a finite value as its terms extend indefinitely. A series is said to converge when its sequence of partial sums approaches a certain limit. Convergence can be tricky, as some series might seem to approach a sum but never really settle to a single value.
When evaluating convergence, look at the general behavior of the terms:
When evaluating convergence, look at the general behavior of the terms:
- If the terms do not tend to zero, the series diverges.
- If the terms do tend to zero but at a slow rate, further tests may be needed.
Absolute Convergence
A series is absolutely convergent if the series formed by taking the absolute values of its terms also converges. To check for absolute convergence, consider \[ \sum |a_n| \].
This allows for a sharper lens on the series, assessing its behavior independently of sign changes. Absolute convergence implies convergence of the original series, but not vice versa.
This allows for a sharper lens on the series, assessing its behavior independently of sign changes. Absolute convergence implies convergence of the original series, but not vice versa.
- If \( \sum |a_n| \) converges, then \( \sum a_n \) converges absolutely.
- Absolute convergence is a strong form of convergence that guarantees regular convergence.
Harmonic Series
The harmonic series is a well-known series in mathematics defined as \[ \sum_{n=1}^{\infty} \frac{1}{n} \].
Despite the terms decreasing to zero, the harmonic series diverges. This means that its partial sums do not approach a finite limit.
It serves as a classic example of a divergent series, showing that even series that 'seem' to lessen their sums over time may still not converge.
Despite the terms decreasing to zero, the harmonic series diverges. This means that its partial sums do not approach a finite limit.
It serves as a classic example of a divergent series, showing that even series that 'seem' to lessen their sums over time may still not converge.
- This series diverges because the sum grows without bound.
- It's often compared to other series to test for divergence.
Alternating Series Test
The alternating series test is helpful for determining the convergence of series that alternate in sign. An alternating series takes the form \[ \sum_{n=1}^{\infty} (-1)^n b_n \] or \[ \sum_{n=1}^{\infty} (-1)^{n+1} b_n \].
For this test to confirm convergence, two conditions must be met:
For this test to confirm convergence, two conditions must be met:
- The terms \( b_n \) must tend to zero as \( n \to \infty \).
- The sequence \( b_n \) must be decreasing, i.e., \( b_{n+1} \leq b_n \) for all \( n \).
Other exercises in this chapter
Problem 22
Find the Taylor series in \(x-a\) through the term \((x-a)^{3}\). \(\tan x, a=\frac{\pi}{4}\)
View solution Problem 22
Determine convergence or divergence for each of the series. Indicate the test you use. \(\frac{1}{1^{2}+1}+\frac{2}{2^{2}+1}+\frac{3}{3^{2}+1}+\frac{4}{4^{2}+1}
View solution Problem 22
$$ \text { Evaluate } \sum_{k=0}^{\infty}(-1)^{k} x^{k},-1
View solution Problem 22
Use any test developed so far, including any from Section \(9.2\), to decide about the convergence or divergence of the series. Give a reason for your conclusio
View solution