Problem 22 - Chemistry Central Science

Question

(a) On Titan, the largest moon of Saturn, the atmospheric pressure is \(1.63105 \mathrm{~Pa}\). What is the atmospheric pressure of Titan in atm? (b) On Venus the surface atmospheric pressure is about 90 Earth atmospheres. What is the Venusian atmospheric pressure in kilopascals?

Step-by-Step Solution

Answer

(a) The atmospheric pressure of Titan is approximately \(1.61 \times 10^{-5}\) atm. (b) The Venusian atmospheric pressure is approximately 9119.25 kPa.

Step 1: Problem (a) Conversion of Titan's atmospheric pressure from Pa to atm

We are given that the atmospheric pressure on Titan is 1.63105 Pa. To convert this value to atm, we can use the conversion factor: 1 atm = 101325 Pa Now, we will divide the given atmospheric pressure by the conversion factor: Atmospheric pressure (atm) = \(\frac{1.63105 \mathrm{~Pa}}{101325 \mathrm{~Pa/atm}}\)

Step 2: Problem (a) Calculation

Now, let's perform the division: Atmospheric pressure on Titan (atm) = \(\frac{1.63105}{101325}\) = 1.61 x 10^{-5} atm So the atmospheric pressure of Titan is approximately 1.61 x 10^{-5} atm.

Step 3: Problem (b) Conversion of Venus' atmospheric pressure from Earth atmospheres to kPa

We are given that the surface atmospheric pressure on Venus is about 90 Earth atmospheres. To convert this value to kPa, we need to first convert it to Pascals using the conversion factor: 1 atm = 101325 Pa Then, we can convert the result to kPa using another conversion factor: 1 kPa = 1000 Pa First, let's convert 90 Earth atmospheres to Pa: Atmospheric pressure (Pa) = 90 atm * 101325 Pa/atm

Step 4: Problem (b) Calculation

Now, perform the multiplication: Atmospheric pressure on Venus (Pa) = 90 * 101325 = 9119250 Pa Now, let's convert this value to kPa: Atmospheric pressure (kPa) = \(\frac{9119250 \mathrm{~Pa}}{1000 \mathrm{~Pa/kPa}}\) Now, perform the division: Atmospheric pressure on Venus (kPa) = \(\frac{9119250}{1000}\) = 9119.25 kPa So the Venusian atmospheric pressure is approximately 9119.25 kPa.