Problem 22
Question
a. Expand each expression as a difference, sum, and/or multiple of logarithms. b. Find the value of each expression. \(\frac{1}{2} \log _{3} 3(243)\)
Step-by-Step Solution
Verified Answer
The expanded expression is \(\frac{1}{2}(1 + 5)\), and the value is 3.
1Step 1: Recognize the Expression Format
The given expression is \(\frac{1}{2} \log_{3} (3 \times 243)\). This is a product inside the logarithm, which we can expand using logarithmic properties.
2Step 2: Apply the Product Rule for Logarithms
The product rule for logarithms says \(\log_b (xy) = \log_b x + \log_b y\). Thus, \(\log_{3} (3 \times 243) = \log_{3} 3 + \log_{3} 243\).
3Step 3: Calculate Each Logarithm
We know \(\log_{3} 3 = 1\) because any number log base to the same number equals 1. Next, we find \(\log_{3} 243\). Since \(243 = 3^5\), we use \(\log_b (a^n) = n \cdot \log_b a\), getting \(\log_3 243 = 5 \cdot \log_3 3 = 5 \cdot 1 = 5\).
4Step 4: Sum the Logarithms
From the previous calculations, \(\log_{3} (3 \times 243) = 1 + 5 = 6\).
5Step 5: Apply the Coefficient
The expression starts with \(\frac{1}{2} \cdot \log_{3} (3 \times 243)\), which means we multiply our result by \(\frac{1}{2}\): \(\frac{1}{2} \cdot 6 = 3\).
Key Concepts
Product Rule for LogarithmsLogarithmic PropertiesCalculating Logarithms
Product Rule for Logarithms
The product rule for logarithms is a powerful tool when dealing with logarithmic expressions involving multiplication. This rule states that for any base \( b \), the logarithm of a product is equal to the sum of the logarithms of its factors. Mathematically, the rule is represented as:
- \( \log_b(xy) = \log_b x + \log_b y \)
- \( \log_{3} 3 + \log_{3} 243 \)
Logarithmic Properties
Logarithmic properties are essential when working to simplify or expand expressions involving logarithms. These properties include the product rule, the power rule, and the quotient rule. They form the foundation for manipulating logarithmic expressions. One crucial property we used is the power rule, represented as:
- \( \log_b (a^n) = n \cdot \log_b a \)
- \( \log_3 243 = 5 \cdot \log_3 3 \)
Calculating Logarithms
Calculating logarithms can seem daunting, but with the right approach, it becomes straightforward. Start by recognizing simple logarithmic values, such as \( \log_3 3 = 1 \). This is known because a logarithm indicates the power needed for the base to reach a number: here, \( 3^1 = 3 \). Additionally, when factoring numbers—like 243 into \( 3^5 \)—and employing logarithmic properties, you can simplify calculations. After breaking down the logarithmic expression using properties, we calculated:
- \( \log_3 (3 \times 243) = 6 \)
- Multiplying by any coefficient, like \( \frac{1}{2} \), if present gives the final answer.
- \( \frac{1}{2} \cdot 6 = 3 \)
Other exercises in this chapter
Problem 22
In \(15-23,\) evaluate each logarithm to the nearest hundredth. $$ \frac{\log 100-\frac{1}{2} \log 36}{\log 6} $$
View solution Problem 22
In \(15-26,\) write each logarithmic equation in exponential form. $$ \log _{100} 0.01=-1 $$
View solution Problem 22
In \(11-22,\) solve each equation for \(y\) in terms of \(x\) $$ x=\log _{0.1} y $$
View solution Problem 23
In \(21-32,\) for each given logarithm, find \(x,\) the antilogarithm. Write the answer to four decimal places. $$ \ln x=1.3826 $$
View solution