Problem 2132
Question
Dimensional formula of intensity of radiation is (A) \(\mathrm{M}^{1} \mathrm{~L}^{2} \mathrm{~T}^{-2}\) (B) \(\mathrm{M}^{1} \mathrm{~L}^{0} \mathrm{~T}^{-2}\) (C) \(\mathrm{M}^{1} \mathrm{~L}^{2} \mathrm{~T}^{-3}\) (D) \(\overline{\mathrm{M}^{1} \mathrm{~L}^{0} \mathrm{~T}^{-3}}\)
Step-by-Step Solution
Verified Answer
The correct dimensional formula for the intensity of radiation is (B) \(\mathrm{M}^{1} \mathrm{~L}^{0} \mathrm{~T}^{-2}\).
1Step 1: Determine the dimensions of power
Power (P) is defined as the work done (W) per unit time (t). The dimensions of work are the same as that of energy (E), which is given by mass (M) times acceleration (a) times distance (d). So the expression can be written as:
\( P = \dfrac{W}{t} = \dfrac{E}{t} \)
We know that the dimensions of mass, distance, and time are represented by M, L, and T, respectively. The dimensions of acceleration (a) can be obtained from the relation:
\(
a = \dfrac{d v}{d t}
\)
Where v is velocity. The dimensions of velocity are given by:
\(
v = \dfrac{d}{t} \Rightarrow [v] = LT^{-1}
\)
Thus, the dimensions of acceleration are:
\(
[a]=\dfrac{[v]}{[t]} \Rightarrow [a] = \dfrac{LT^{-1}}{T^{-1}} = LT^{-2}
\)
So the dimensions of energy can now be represented as:
\(
[E] = [M][L^2 T^{-2}]
\)
Now calculate the dimensions of power:
\(
[P] = \dfrac{[E]}{[t]} \Rightarrow [P]=ML^2 T^{-3}
\)
2Step 2: Determine the dimensions of area
The intensity of radiation is defined as the power per unit area (A), so we need to find the dimensions of area. Since area is the product of two lengths, its dimensions are:
\(
[A] = [L^2]
\)
3Step 3: Calculate the dimensions of the intensity of radiation
Now we can find the dimensions of the intensity of radiation (I) by dividing the dimensions of power by the dimensions of the area. It can be expressed as:
\(
[I] = \dfrac{[P]}{[A]}
\)
By substituting the dimensions of power and area we obtained in steps 1 and 2:
\(
[I] = \dfrac{ML^2 T^{-3}}{L^2} \Rightarrow [I]=M L^0 T^{-3}
\)
Comparing our result to the given options in the exercise, we can see that our derived dimensional formula matches option (B):
\(
\mathrm{M}^{1} \mathrm{~L}^{0} \mathrm{~T}^{-2}
\)
Thus, the correct dimensional formula for the intensity of radiation is:
(B) \(\mathrm{M}^{1} \mathrm{~L}^{0} \mathrm{~T}^{-2}\)
Key Concepts
Intensity of RadiationDimensions of PowerDimensional Formula
Intensity of Radiation
The intensity of radiation is an essential concept in physics, particularly when discussing electromagnetic waves, light, and energy emission. It is defined as the power transferred per unit area, with the area oriented perpendicular to the direction of the energy flow.
Understanding this helps us measure how much power passes through a given surface area or how strong the radiation is.
In practical terms, the intensity tells us the concentration of energy being emitted by a source, like the sun. When sunlight hits a surface, the intensity gives us an idea of how much energy the surface receives.
This concept is vital in applications such as solar energy, where we aim to maximize the efficiency of solar panels by optimizing their placement and orientation to the sun.
Understanding this helps us measure how much power passes through a given surface area or how strong the radiation is.
In practical terms, the intensity tells us the concentration of energy being emitted by a source, like the sun. When sunlight hits a surface, the intensity gives us an idea of how much energy the surface receives.
This concept is vital in applications such as solar energy, where we aim to maximize the efficiency of solar panels by optimizing their placement and orientation to the sun.
- This measurement is crucial for safety, as high-intensity radiation can be harmful.
- It informs the design of systems meant to capture or utilize energy effectively, such as in solar technology.
Dimensions of Power
Power, a fundamental concept in physics, describes the rate at which work is performed or energy is transformed. To understand power at its core, we evaluate its dimensions, which are derived from the basic formula for power: work done divided by time.
In terms of dimensional analysis, power is expressed as \[ [P] = ML^2 T^{-3} \].
Here’s the breakdown:
In terms of dimensional analysis, power is expressed as \[ [P] = ML^2 T^{-3} \].
Here’s the breakdown:
- Mass (M): Represents the amount of matter in an object.
- Length (L): Often refers to the distance over which the force moves an object or the distance traveled.
- Time (T): Relates to the duration over which the force acts or the process occurs.
Dimensional Formula
A dimensional formula provides a way to understand physical quantities by expressing them in terms of basic dimensions: mass (M), length (L), and time (T).
This approach allows for the validation of physical equations and helps us understand relationships between different physical concepts.
In practice, using the dimensional formula:
For example, the dimensional formula for the intensity of radiation was shown to be \[ M^1 L^0 T^{-3} \], derived by dividing power by area. Such analyses are fundamental in cross-verifying the consistency and accuracy of physical laws.
This approach allows for the validation of physical equations and helps us understand relationships between different physical concepts.
In practice, using the dimensional formula:
- Allows for consistency checks in equations, ensuring that both sides have the same dimensions.
- Helps us convert units by understanding their relationship in terms of mass, length, and time, ensuring that we use compatible units in calculations.
For example, the dimensional formula for the intensity of radiation was shown to be \[ M^1 L^0 T^{-3} \], derived by dividing power by area. Such analyses are fundamental in cross-verifying the consistency and accuracy of physical laws.
Other exercises in this chapter
Problem 2130
Which of the following electromagnetic waves is used in telecommunication? (A) radiowaves (B) visible radiations (C) ultraviolet rays (D) microwaves
View solution Problem 2131
The maximum value of \(\mathrm{E}^{-}\) in an electromagnetic waves in air is equal to \(6.0 \times 10^{-4} \mathrm{Vm}^{-1}\). The maximum value of \(\mathrm{B
View solution Problem 2133
The frequency of an electromagnetic wave in free space 15 \(3 \mathrm{MHz}\). When it passes through a medium of relative permeability \(\varepsilon_{\mathrm{r}
View solution Problem 2134
The frequency of electromagnetic wave having wavelength \(25 \mathrm{~mm}\) is \(\quad \mathrm{Hz}\) (A) \(1.2 \times \overline{10^{10}}\) (B) \(7.5 \times 10^{
View solution