Problem 213
Question
The bond dissociation energy of \(\mathrm{B}-\mathrm{F}\) in \(\mathrm{BF}_{3}\) is 646 \(\mathrm{kJ} \mathrm{mol}^{-1}\) whereas that of \(\mathrm{C}-\mathrm{F}\) in \(\mathrm{CF}_{4}\) is \(515 \mathrm{~kJ} \mathrm{~mol}^{-1}\). The correct reason for higher B - F bond dissociation energy as compared to that of \(\mathrm{C}-\mathrm{F}\) is: [2009](a) stronger bond between \(\mathrm{B}\) and \(\mathrm{F}\) in \(\mathrm{BF}_{3}\) as compared to that between \(\mathrm{C}\) and \(\mathrm{F}\) is \(\mathrm{CF}_{4}\) (b) significant \(\mathrm{p}-\mathrm{p}\) interaction between \(\mathrm{B}\) and \(\mathrm{F}\) in \(\mathrm{BF}_{3}\) whereas there is no possibility of such interaction between \(\mathrm{C}\) and \(\mathrm{F}\) in \(\mathrm{CF}_{4}\) (c) lower degree of \(\mathrm{p}\) - p interaction between \(\mathrm{B}\) and \(\mathrm{F}\) \(\mathrm{BF}_{3}\) than that between \(\mathrm{C}\) and \(\mathrm{F}\) in \(\mathrm{CF}_{4}\) (d) smaller size of \(\mathrm{B}\) - atom as compared to that of C- atom
Step-by-Step Solution
VerifiedKey Concepts
p-p Interaction
- p-p interactions, both participating atoms must have available and compatible p orbitals.
- This overlap increases the electron density between the atoms, strengthening the bond.
- In \( ext{BF}_3\), significant p-p orbital overlap occurs between boron and fluorine, resulting in stronger bonds.
Thus, the presence and efficiency of p-p interactions can determine why certain bonds, like B-F, might have higher bond dissociation energies compared to others.
B-F Bond
- \(\text{BF}_3\) is highly polar, with fluorine being more electronegative than boron.
- This polarity results in a bond with partial ionic character.
- Additionally, the significant p-p orbital overlap, as explained before, contributes to an exceptionally stable and strong bond configuration.
C-F Bond
- \(\text{CF}_4\) also features a considerable electronegativity difference.
- This bond also leans towards being polar, yet it lacks the p-p interactions found in B-F.
- In carbon tetrafluoride, the structure forms through sp3 hybridization, which does not favor the same level of p orbital overlap.
Atomic Size
- Boron, being a smaller atom than carbon, can form tighter and more effective bonds due to greater orbital proximity.
- Fluorine, being the same size in both B-F and C-F, adds to this interaction by bringing its high electronegativity to play.
- Smaller atoms allow for closer interaction and overlap of orbitals, which can account for increased bond stability and energy in boron-fluorine bonds.
Orbital Interactions
- In molecules like \(\text{BF}_3\), the interaction between atomic orbitals contributes to creating strong bonds.
- These interactions depend on how well the orbitals can overlap, their shapes, and energy similarities.
- Efficient orbital overlap in B-F stems from available and compatible orbitals, creating stronger bonds due to increased electron sharing.