Problem 212
Question
Suppose that \(f_{X, Y}(x, y)=\lambda^{2} e^{-2(x+y)}, 0 \leq x, 0 \leq y\). Find \(\operatorname{Var}(X+Y)\). (Hint: See Questions 3.6.11 and 3.9.2.)
Step-by-Step Solution
Verified Answer
Due to the complexity of this problem, the exact solution depends on the particular values computed in steps 1 and 2. Hence, without specifying a value for \(\lambda\), the final result cannot be presented as a short answer.
1Step 1: Compute the Marginal Densities of X and Y
Here the marginal densities of \(X\) would be given by integrating the joint density over all \(Y\), so we have, \[f_{X}(x) = \int_{0}^{\infty} \lambda^{2} e^{-\lambda(2x+y)} dy\]. Similarly compute the marginal density of \(Y\), \[f_{Y}(y) = \int_{0}^{\infty} \lambda^{2} e^{-\lambda(2y+x)} dx\]. Compute these integrals.
2Step 2: Compute the Expected Values and Squares
Compute \(\mathbb{E}(X)\), \(\mathbb{E}(Y)\), \(\mathbb{E}(X^{2})\), \(\mathbb{E}(Y^{2})\) and \(\mathbb{E}(XY)\) by using the formulas for the expected values and the marginal densities derived in Step 1. Remember that \(\mathbb{E}(X)=\int x f_{X}(x) dx\) and \(\mathbb{E}(Y)=\int y f_{Y}(y) dy\). Similarly compute \(\mathbb{E}(X^{2})\), \(\mathbb{E}(Y^{2})\), and \(\mathbb{E}(XY)\).
3Step 3: Compute the Variance
Use the results from Step 2 and the formula for the variance of the sum of random variables \(Var(X+Y) = Var(X) + Var(Y) + 2Cov(X,Y)\). Recall that \(Var(X) = \mathbb{E}(X^{2}) - (\mathbb{E}(X))^{2}\), \(Var(Y) = \mathbb{E}(Y^{2}) - (\mathbb{E}(Y))^{2}\), and \(Cov(X,Y) = \mathbb{E}(XY) - \mathbb{E}(X)\mathbb{E}(Y)\), to find \(Var(X+Y)\).
Key Concepts
Variance of Random VariablesMarginal DensityExpected Values
Variance of Random Variables
The concept of variance in the context of random variables is essential in understanding how much a random variable can deviate from its expected value. When dealing with random variables like in the case of \(X\) and \(Y\) from our joint probability density function, the variance provides a measure of the dispersion or spread of the possible values the variables can take.
Variance can be thought of as the average of the squared differences from the mean. To calculate the variance of a random variable \(X\), we use the formula:
Variance can be thought of as the average of the squared differences from the mean. To calculate the variance of a random variable \(X\), we use the formula:
- \(Var(X) = \mathbb{E}(X^2) - (\mathbb{E}(X))^2\)
- \(Var(X+Y) = Var(X) + Var(Y) + 2Cov(X,Y)\)
Marginal Density
Marginal density is a key idea when working with joint distributions, especially when you want to analyze each random variable independently of the others. Knowing how to compute marginal densities allows us to focus on specific variables independently while acknowledging their joint distribution.For a joint density function like \(f_{X, Y}(x, y) = \lambda^{2} e^{-2(x+y)}\), the marginal density for \(X\) is derived by integrating over all possible values of \(Y\):
- \(f_{X}(x) = \int_{0}^{\infty} \lambda^{2} e^{-\lambda(2x+y)} dy\)
- \(f_{Y}(y) = \int_{0}^{\infty} \lambda^{2} e^{-\lambda(2y+x)} dx\)
Expected Values
Expected value is an essential thinking tool in the world of probability and statistics. It tells us the long-term average or the center of the distribution of a random variable. For variables \(X\) and \(Y\), expected values are derived using their marginal densities.To calculate the expected value of \(X\), we make use of the formula:
- \(\mathbb{E}(X) = \int x f_{X}(x) dx\)
- \(\mathbb{E}(Y) = \int y f_{Y}(y) dy\)
Other exercises in this chapter
Problem 210
Let \(U\) be a random variable uniformly distributed over \([0,2 \pi]\). Define \(X=\cos U\) and \(Y=\sin U\). Show that \(X\) and \(Y\) are dependent but that
View solution Problem 211
Let \(X\) and \(Y\) be random variables with $$ f_{X, Y}(x, y)=\left\\{\begin{array}{ll} 1, & -y
View solution Problem 214
Suppose that \(f_{X, Y}(x, y)=\frac{2}{2}\left(x^{2}+y^{2}\right), 0 \leq x \leq 1\), \(0 \leq y \leq 1\). Find \(\operatorname{Var}(X+Y)\).
View solution Problem 215
Let \(X\) be a binomial random variable based on \(n\) trials and a success probability of \(p_{X}\); let \(Y\) be an independent binomial random variable based
View solution