Problem 21
Question
Write formulas for the ionic compounds formed by the following ions. aluminum and bromide
Step-by-Step Solution
Verified Answer
The formula for the ionic compound formed is \(\text{AlBr}_3\).
1Step 1: Identify the charge of each ion
First, identify the charges associated with each ion. Aluminum (Al) typically forms ions with a +3 charge, denoted as \(\text{Al}^{3+}\). Bromide (Br), on the other hand, is a halogen and forms ions with a -1 charge, written as \(\text{Br}^-\).
2Step 2: Determine the ratio of ions needed for charge balance
For the compound to be electrically neutral, the positive and negative charges must balance each other. Since aluminum has a +3 charge and bromide has a -1 charge, you need three bromide ions to balance one aluminum ion. This gives us a ratio of \(1:3\) for aluminum to bromide ions.
3Step 3: Write the chemical formula
Using the ratio from Step 2, write the chemical formula by placing the charges in subscript form next to each ion. Therefore, the chemical formula for the compound is \(\text{AlBr}_3\), indicating one aluminum ion coupled with three bromide ions.
Key Concepts
Ionic CompoundsCharge BalanceSubscript NotationIon Charges
Ionic Compounds
Chemical formula writing for ionic compounds involves understanding the interaction between positively and negatively charged ions. Unlike molecular compounds that share electrons, ionic compounds are formed when electrons are transferred from one atom to another, resulting in a balance of charges. This interaction creates what is known as an "ionic bond."
When aluminum and bromide form an ionic compound, they combine in such a way that their charges are neutralized, creating a stable compound. The resultant compound maintains specific characteristics:
When aluminum and bromide form an ionic compound, they combine in such a way that their charges are neutralized, creating a stable compound. The resultant compound maintains specific characteristics:
- The structure is composed entirely of ions.
- The compound is electrically neutral.
- It often results in high melting and boiling points due to strong ionic bonds.
Charge Balance
Achieving charge balance is crucial when writing formulas for ionic compounds. This means that the total positive charge must equal the total negative charge, ensuring overall neutrality in the compound.
When you identify ions, like aluminum (\( ext{Al}^{3+}\)) and bromide (\( ext{Br}^-\)), consider their charges:
When you identify ions, like aluminum (\( ext{Al}^{3+}\)) and bromide (\( ext{Br}^-\)), consider their charges:
- Identify the charge of each ion has: +3 for aluminum and -1 for bromide.
- Ensure the total positive charge equals the total negative charge. In this case, three bromide ions (\(3 imes (-1) = -3\)) are necessary to balance one aluminum ion (\(+3\)).
Subscript Notation
Subscript notation in chemical formulas indicates the number of atoms (or ions) of each element in a compound. It plays a vital role in conveying chemical structure and composition. Understanding subscript notation allows you to represent complex chemical interactions succinctly.
For the aluminum bromide compound, the chemical formula is written as \( ext{AlBr}_3\):
For the aluminum bromide compound, the chemical formula is written as \( ext{AlBr}_3\):
- The absence of a subscript next to aluminum (\( ext{Al}\)) means there is just one aluminum ion.
- The subscript "3" next to bromide (\( ext{Br}_3\)) illustrates three bromide ions needed to balance the single aluminum ion's charge.
Ion Charges
Each element in the periodic table tends to exist naturally with a particular charge when it forms ions. This charge reflects the element's ability to lose or gain electrons, leading to stability.
Aluminum, typically, forms cations with a +3 charge, as it loses three electrons to achieve a stable electron configuration. This process results in a distinctly positive ion with notation \( ext{Al}^{3+}\).
Bromine, as a halogen, gains an electron to reach stability, earning it a negative charge with its ion form as \( ext{Br}^-\).
Understanding the charge tendencies of these ions is fundamental when predicting the resulting compounds they can form. Recognizing these specifics aids significantly in chemical formula writing, ensuring accurate charge balance and formation predictions for complex ionic compounds.
Aluminum, typically, forms cations with a +3 charge, as it loses three electrons to achieve a stable electron configuration. This process results in a distinctly positive ion with notation \( ext{Al}^{3+}\).
Bromine, as a halogen, gains an electron to reach stability, earning it a negative charge with its ion form as \( ext{Br}^-\).
Understanding the charge tendencies of these ions is fundamental when predicting the resulting compounds they can form. Recognizing these specifics aids significantly in chemical formula writing, ensuring accurate charge balance and formation predictions for complex ionic compounds.
Other exercises in this chapter
Problem 19
Write formulas for the ionic compounds formed by the following ions. potassium and iodide
View solution Problem 20
Write formulas for the ionic compounds formed by the following ions. magnesium and chloride
View solution Problem 22
Write formulas for the ionic compounds formed by the following ions. cesium and nitride
View solution Problem 24
Write formulas for ionic compounds composed of the following ions. sodium and nitrate
View solution