Problem 21
Question
Which of the following gives aldol condensation reaction? (a) \(\mathrm{CH}_{3} \mathrm{CH}_{2}-\mathrm{CO}-\mathrm{CH}_{3}\) (b) \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{C}-\mathrm{CO}-\mathrm{CH}_{3}\) (c) \(\mathrm{C}_{6} \mathrm{H}_{5}-\mathrm{CO}-\mathrm{C}_{6} \mathrm{H}_{5}\) (d) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}\)
Step-by-Step Solution
Verified Answer
Butan-2-one (option a) undergoes aldol condensation.
1Step 1: Understanding Aldol Condensation
Aldol condensation is a reaction between an enolate ion and a carbonyl compound that requires at least one alpha hydrogen in order to form a β-hydroxy aldehyde or ketone, which can dehydrate to a conjugated enone.
2Step 2: Identify Alpha Hydrogens
(a) \(\mathrm{CH}_{3} \mathrm{CH}_{2}-\mathrm{CO}-\mathrm{CH}_{3}\) - This molecule (butan-2-one) has alpha hydrogens available on both sides of the keto group.(b) \((\mathrm{CH}_{3})_{3} \mathrm{C}-\mathrm{CO}-\mathrm{CH}_{3}\) - The central carbon in tert-butyl methyl ketone has no alpha hydrogen because the three methyl groups provide no alpha hydrogen under the keto group.(c) \(\mathrm{C}_{6} \mathrm{H}_{5}-\mathrm{CO}-\mathrm{C}_{6} \mathrm{H}_{5}\) - Diphenyl ketone has no alpha hydrogen as the keto group is attached to two phenyl groups.(d) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}\) - Phenol \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}\) does not have an alpha hydrogen nor a carbonyl group.
3Step 3: Determine Capability for Aldol Condensation
Only option (a), butan-2-one, has alpha hydrogens that can participate in an aldol condensation reaction, forming an enolate ion that can attack a carbonyl carbon. Options (b), (c), and (d) lack alpha hydrogens necessary for this reaction.
Key Concepts
Enolate IonAlpha HydrogenCarbonyl Compound
Enolate Ion
The enolate ion is a crucial player in aldol condensation reactions. Formed when an alpha hydrogen is removed from a compound by a base, it acts as a nucleophile and is characterized by its resonance structures.
Here's a quick look at how enolate ions are formed and how they participate in reactions:
Here's a quick look at how enolate ions are formed and how they participate in reactions:
- When a base such as hydroxide or alkoxide abstracts an alpha hydrogen, it generates an enolate ion. This is due to the high acidity of alpha hydrogens adjacent to a carbonyl group.
- The resulting enolate ion possesses a high electron density on the alpha carbon, allowing it to attack the electrophilic carbon of a carbonyl group.
Alpha Hydrogen
Alpha hydrogens are pivotal to the entire aldol condensation process. They are atoms that sit adjacent to a carbonyl group, such as a ketone or aldehyde. These hydrogens are slightly acidic due to the electron-withdrawing nature of the carbonyl group. This acidity allows them to be easily removed by a base, leading to the formation of an enolate ion.
- An alpha hydrogen's acidity makes it susceptible to deprotonation, resulting in an enolate ion that is ready to engage in reactions.
- In aldol condensation, compounds with accessible alpha hydrogens, like butan-2-one, can readily participate by offering these hydrogens for deprotonation.
Carbonyl Compound
Carbonyl compounds, including aldehydes and ketones, form the backbone of aldol condensation reactions. Their unique structure, featuring a carbon-oxygen double bond, provides both acidity (through alpha hydrogens) and electrophilicity (at the carbon of the carbonyl group).
- The carbonyl carbon is electrophilic, making it a prime target for nucleophilic attack from enolate ions generated in the reaction.
- The carbonyl oxygen's partial negative charge helps stabilize the enolate ion via resonance, enhancing the reaction's feasibility and yield.
Other exercises in this chapter
Problem 19
Dimerisation is carboxylic acids is due to (a) intermolecular hydrogen bond (b) coordinate bond (c) ionic bond (d) covalent bond
View solution Problem 20
Carboxylic acids are more acidic than phenol and alcohol because of (a) formation of dimers (b) highly acidic hydrogen (c) resonance stabilization of their conj
View solution Problem 22
Acetaldehyde cannot exhibit (a) Iodoform test (b) Benedict's test (c) Lucas test (d) Tollen's test
View solution Problem 23
Ketones \(\left(\mathrm{R}_{1} \mathrm{COR}_{2}\right) ; \mathrm{R}_{1}=\mathrm{R}_{2}=\) alkyl group, can be obtained in one step by (a) hydrolysis of esters (
View solution