Problem 21
Question
What is the probability of tossing 7 heads in 10 tosses of a fair coin?
Step-by-Step Solution
Verified Answer
The probability of tossing exactly 7 heads in 10 tosses of a fair coin is 0.1171875.
1Step 1: Understanding the Problem
This problem is an example of a binomial distribution, where there are two possible outcomes for each trial (tossing a head or a tail), and we want to find the probability of getting exactly 7 heads in 10 trials (tosses).
2Step 2: Computing Individual Trial Probability
Since the coin is fair, the probability of getting a head (success) on any single toss is 0.5. This is because there are 2 possible outcomes, and each of them is equally likely.
3Step 3: Using the Binomial Probability Formula
The binomial probability formula is given by: \( P(X = k) = {n \choose k} p^k (1-p)^{n-k} \), where \( n \) is the number of trials, \( k \) is the number of successes we are looking for, \( p \) is the probability of success on a single trial, and \( {n \choose k} \) is the binomial coefficient. For this case, \( n=10, k=7, \) and \( p=0.5 \).
4Step 4: Calculating the Binomial Coefficient
The binomial coefficient \( {n \choose k} \) represents the number of ways to choose k successes out of n trials, and is calculated as \( {n \choose k} = \frac{n!}{k!(n-k)!} \). Substituting the values we get \( {10 \choose 7} = \frac{10!}{7!3!} = 120 \).
5Step 5: Applying the Values to the Formula
Now apply the values to the binomial probability formula to get the probability: \( P(X = 7) = {10 \choose 7} \times 0.5^7 \times (1-0.5)^{10-7}\).
6Step 6: Solving the Probability
Finally, calculate the probability: \(P(X=7) = 120 \times 0.5^7 \times 0.5^3 = 120 \times 0.5^{10} = 120 \times 0.0009765625 = 0.1171875\).
Key Concepts
Probability TheoryBinomial CoefficientBinomial Distribution Formula
Probability Theory
Probability theory is the branch of mathematics concerned with analyzing random events and quantifying the likelihood of different outcomes. In the context of a fair coin flip, the results (heads or tails) are random. Yet, we can predict the statistical frequency of these outcomes over a large number of trials based on probability principles.
At its core, probability values range from 0 to 1, where 0 indicates an impossibility and 1 represents a certainty. The probability of flipping a head with a fair coin is exactly 0.5, which means there is an equal chance for heads or tails. In the given exercise, we examine the event of flipping a coin 10 times and finding the probability of getting precisely 7 heads, applying principles of probability theory to solve the problem.
At its core, probability values range from 0 to 1, where 0 indicates an impossibility and 1 represents a certainty. The probability of flipping a head with a fair coin is exactly 0.5, which means there is an equal chance for heads or tails. In the given exercise, we examine the event of flipping a coin 10 times and finding the probability of getting precisely 7 heads, applying principles of probability theory to solve the problem.
Binomial Coefficient
The binomial coefficient is a fundamental concept in combinatorics, representing the number of ways to choose a subset of items from a larger set, without regard to order. It is denoted as \( {n \choose k} \), where \( n \) is the total number of items and \( k \) is the number of items to choose.
Calculated using the factorials of the numbers involved (\( n! \) is the factorial of \( n \) and stands for the product of all positive integers up to \( n \)), the binomial coefficient formula is \( {n \choose k} = \frac{n!}{k!(n-k)!} \). In our exercise, to figure out the number of ways to get 7 heads out of 10 tosses, the binomial coefficient \( {10 \choose 7} \) reveals there are 120 different combinations where 7 heads could occur.
Calculated using the factorials of the numbers involved (\( n! \) is the factorial of \( n \) and stands for the product of all positive integers up to \( n \)), the binomial coefficient formula is \( {n \choose k} = \frac{n!}{k!(n-k)!} \). In our exercise, to figure out the number of ways to get 7 heads out of 10 tosses, the binomial coefficient \( {10 \choose 7} \) reveals there are 120 different combinations where 7 heads could occur.
Binomial Distribution Formula
The binomial distribution formula is a blueprint for determining the probability of achieving a certain number of successes in a fixed number of trials, with just two possible outcomes (success or failure) and a constant probability of success in each trial. The formula, expressed as \( P(X = k) = {n \choose k} p^k (1-p)^{n-k} \), combines the concepts of individual trial probability (\( p \) for success), the binomial coefficient (\( {n \choose k} \)), the number of successes (\( k \) heads), and the number of trials (\( n \)) for a complete probability calculation.
In the context of our exercise seeking the probability of flipping 7 heads in 10 coin tosses, we observed the formula at work with a balanced probability (\( p = 0.5 \) for heads) and applied it to evaluate the precise chance of this specific outcome. Ultimately, it quantified the likelihood to be approximately 0.1172, meaning there is close to a 12% chance of flipping exactly 7 heads in 10 tosses.
In the context of our exercise seeking the probability of flipping 7 heads in 10 coin tosses, we observed the formula at work with a balanced probability (\( p = 0.5 \) for heads) and applied it to evaluate the precise chance of this specific outcome. Ultimately, it quantified the likelihood to be approximately 0.1172, meaning there is close to a 12% chance of flipping exactly 7 heads in 10 tosses.
Other exercises in this chapter
Problem 17
A binomial experiment is repeated \(n\) times, with a probability \(p\) of success on one trial. Find the probability \(P(x)\) of \(x\) successes, if $$n=7, p=0
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A binomial experiment is repeated \(n\) times, with a probability \(p\) of success on one trial. Find the probability \(P(x)\) of \(x\) successes, if $$n=9, p=0
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If male and female births are equally likely, what is the probability of five births being all girls?
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A certain multiple-choice test has 20 questions, each of which has four choices, only one of which is correct. If a student were to guess every answer, what is
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