Problem 21
Question
Verify the Identity. $$\sin ^{4} r-\cos ^{4} r=\sin ^{2} r-\cos ^{2} r$$
Step-by-Step Solution
Verified Answer
The identity \(\sin^{4} r - \cos^{4} r = \sin^{2} r - \cos^{2} r\) is verified.
1Step 1: Understand the Identity
The identity we need to verify is \(\sin^{4} r - \cos^{4} r = \sin^{2} r - \cos^{2} r\). We will use algebraic identities and trigonometric identities to verify it.
2Step 2: Factor the Expression on the Left
Notice that \(a^4 - b^4\) can be factored using the difference of squares: \((a^2 - b^2)(a^2 + b^2)\). Thus, \(\sin^{4} r - \cos^{4} r = (\sin^{2} r - \cos^{2} r)(\sin^{2} r + \cos^{2} r)\).
3Step 3: Use the Pythagorean Identity
From trigonometry, we know the Pythagorean identity: \(\sin^{2} r + \cos^{2} r = 1\). Substitute this into our expression: \((\sin^{2} r - \cos^{2} r)(\sin^{2} r + \cos^{2} r) = (\sin^{2} r - \cos^{2} r)(1)\).
4Step 4: Simplify the Expression
Since multiplying by 1 does not change an expression, we have \((\sin^{2} r - \cos^{2} r)(1) = \sin^{2} r - \cos^{2} r\). Thus, the left side simplifies exactly to the right side.
5Step 5: Conclusion
Both sides of the original equation \(\sin^{4} r - \cos^{4} r = \sin^{2} r - \cos^{2} r\) are equal, confirming that the identity is verified.
Key Concepts
Pythagorean IdentityDifference of SquaresAlgebraic Identities
Pythagorean Identity
The Pythagorean identity is a fundamental trigonometric identity that is immensely helpful in simplifying expressions and verifying other identities. It states:
The horizontal and vertical components can be described using sine and cosine, which when squared and summed, always give one. This property is crucial because it allows us to transform and simplify trigonometric expressions by substituting \(\sin^2 r + \cos^2 r\) with 1.
In our original exercise, employing the Pythagorean identity allows us to simplify \((\sin^2 r + \cos^2 r)\) to 1. This simplification is key in proving the given identity \(\sin^{4} r - \cos^{4} r = \sin^{2} r - \cos^{2} r\).
- \(\sin^2 r + \cos^2 r = 1\)
The horizontal and vertical components can be described using sine and cosine, which when squared and summed, always give one. This property is crucial because it allows us to transform and simplify trigonometric expressions by substituting \(\sin^2 r + \cos^2 r\) with 1.
In our original exercise, employing the Pythagorean identity allows us to simplify \((\sin^2 r + \cos^2 r)\) to 1. This simplification is key in proving the given identity \(\sin^{4} r - \cos^{4} r = \sin^{2} r - \cos^{2} r\).
Difference of Squares
The difference of squares is a powerful algebraic identity that helps factorise expressions. It states that for any two numbers \(a\) and \(b\):
In our exercise, this concept is extended to factor the expression \(\sin^{4} r - \cos^{4} r\). Recognizing \(a^4 - b^4\) as \((a^2 - b^2)(a^2 + b^2)\), we can set \(a = \sin^2 r\) and \(b = \cos^2 r\). This results in:
- \(a^2 - b^2 = (a - b)(a + b)\)
In our exercise, this concept is extended to factor the expression \(\sin^{4} r - \cos^{4} r\). Recognizing \(a^4 - b^4\) as \((a^2 - b^2)(a^2 + b^2)\), we can set \(a = \sin^2 r\) and \(b = \cos^2 r\). This results in:
- \(\sin^{4} r - \cos^{4} r = (\sin^2 r - \cos^2 r)(\sin^2 r + \cos^2 r)\)
Algebraic Identities
Algebraic identities are fundamental properties that help in simplifying and manipulating algebraic expressions. They are known truths that don’t change, no matter what values you substitute into the variables. The basic algebraic identities include:
In our original exercise, using the difference of squares is a direct application of algebraic identities. Recognizing \(\sin^{4} r - \cos^{4} r\) as \(a^4 - b^4\), we were able to employ the identity to write it in factored form.
This step was pivotal in confirming \(\sin^{4} r - \cos^{4} r = \sin^{2} r - \cos^{2} r\) by showing the expression was indeed equal on both sides of the equation.
- \((a + b)^2 = a^2 + 2ab + b^2\)
- \((a - b)^2 = a^2 - 2ab + b^2\)
- \(a^2 - b^2 = (a - b)(a + b)\)
In our original exercise, using the difference of squares is a direct application of algebraic identities. Recognizing \(\sin^{4} r - \cos^{4} r\) as \(a^4 - b^4\), we were able to employ the identity to write it in factored form.
This step was pivotal in confirming \(\sin^{4} r - \cos^{4} r = \sin^{2} r - \cos^{2} r\) by showing the expression was indeed equal on both sides of the equation.
Other exercises in this chapter
Problem 21
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