Problem 21
Question
Verify that the infinite series converges. $$ \sum_{n=0}^{\infty} 2\left(\frac{3}{4}\right)^{n} $$
Step-by-Step Solution
Verified Answer
The series \(\sum_{n=0}^{\infty} 2\left(\frac{3}{4}\right)^{n}\) is a convergent series.
1Step 1: Identify the geometric series and its ratio
The series \(\sum_{n=0}^{\infty} 2\left(\frac{3}{4}\right)^{n}\) is a geometric series, where the constant factor between terms (the ratio) is \(r = \frac{3}{4}\). This is calculated by dividing one term of the series by the previous term.
2Step 2: Verification of the ratio
A geometric series will converge if the absolute value of the ratio r is less than 1. So, we check the magnitude of r: \(|r| = |\frac{3}{4}| < 1\). Since the condition is met, the series converges.
3Step 3: Conclusion
The series \(\sum_{n=0}^{\infty} 2\left(\frac{3}{4}\right)^{n}\) is deemed a convergent series, because the ratio is such that its absolute is less than 1.
Key Concepts
Geometric SeriesRatio TestConvergent Series
Geometric Series
A geometric series is a series where every term after the first is found by multiplying the previous one by a fixed, non-zero number called the "ratio." In mathematical terms, a geometric series has the form \( a + ar + ar^2 + ar^3 + \ldots \), where \( a \) is the first term and \( r \) is the common ratio. This type of series is fundamental in mathematics due to its predictable pattern and wide applications.
- The terms grow or shrink exponentially based on the ratio.
- If the ratio \( |r| < 1 \), the series is said to converge, which means it approaches a specific finite sum.
- Conversely, if \( |r| \geq 1 \), the series diverges, growing without bound.
Ratio Test
The ratio test is a mathematical technique to determine the convergence or divergence of an infinite series. This test is particularly useful because it can be applied to a wide range of series. To use the ratio test:
- Consider the series \( \sum a_n \) with terms \( a_n \).
- Calculate \( L = \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| \).
- Interpret the value of \( L \):
- If \( L < 1 \), the series converges absolutely.
- If \( L > 1 \) or \( L \) is infinite, the series diverges.
- If \( L = 1 \), the test is inconclusive, and another method is required.
Convergent Series
A convergent series is one in which the sum of its terms approaches a specific finite number as more terms are added. This property is essential because it indicates that an infinite sum can have a meaningful total. Specifically, convergence means:
Convergent series are foundational in calculus and have applications ranging from physics to economics, where they model real-world phenomena that require summing infinite sequences.
- There exists a limit \( S = \lim_{N \to \infty} \sum_{n=1}^{N} a_n \) for the series \( \sum a_n \).
- This implies that as we progressively add more terms, the partial sums approach \( S \).
Convergent series are foundational in calculus and have applications ranging from physics to economics, where they model real-world phenomena that require summing infinite sequences.
Other exercises in this chapter
Problem 20
Approximate the sum of the series by using the first six terms. (See Example 4.) $$ \sum_{n=1}^{\infty} \frac{(-1)^{n+1} n}{2^{n}} $$
View solution Problem 20
Use the power series $$\frac{1}{1+x}=\sum_{n=0}^{\infty}(-1)^{n} x^{n}$$ to determine a power series, centered at 0 , for the function. Identify the interval of
View solution Problem 21
In Exercises 21-24, simplify the ratio of factorials. \(\frac{(n+1) !}{n !}\)
View solution Problem 21
In Exercises \(19-24,\) find the \(n\) th Taylor polynomial centered at \(c\). $$ f(x)=\sqrt{x}, \quad n=4, \quad c=1 $$
View solution