Problem 21
Question
Use the product rule to simplify the expressions in Exercises \(13-22\). In Exercises \(17-22,\) assume that variables represent nonnegative real numbers. $$\sqrt{2 x^{2}} \cdot \sqrt{6 x}$$
Step-by-Step Solution
Verified Answer
The simplified expression is \(2x^{2}\sqrt{3}\).
1Step 1: Break Down the Expression
First, you need to decompose each square root into its simplest form. This implies that \(\sqrt{2 x^{2}}\) will become \(x\sqrt{2}\) and \(\sqrt{6x}\) turns into \(\sqrt{6}\sqrt{x}\).
2Step 2: Apply the Product Rule
The product rule for roots specifies that the product of two radical expressions of the same radical type can be written as a single radical expression. This implies \(\sqrt{a}\sqrt{b}\) can be written as \(\sqrt{ab}\). Apply this rule to the decomposed expression by multiplying \(x\sqrt{2}\) and \(\sqrt{6}\sqrt{x}\), resulting in \(x\sqrt{2}\cdot \sqrt{6}\cdot x\). It can then be simplified to \(x^{2}\sqrt{12}\).
3Step 3: Simplify the Result
Further simplify \(x^{2}\sqrt{12}\) where you simplify the constant under the radical to \(\sqrt{12}\) = \(2\sqrt{3}\). Finally, the expression simplifies to \(2x^{2}\sqrt{3}\).
Key Concepts
Understanding Radical ExpressionsMastering Square Root SimplificationEffective Algebraic Simplification Techniques
Understanding Radical Expressions
Radical expressions are mathematical expressions that involve roots, most commonly square roots. A radical expression is written with the radical sign \( \sqrt{} \), and the number or expression under the radical sign is called the radicand.
For example, in the expression \( \sqrt{2x^2} \), \(2x^2\) is the radicand.When working with radical expressions, particularly when simplifying them, the goal is to express them in their simplest form. This can involve:
For example, in the expression \( \sqrt{2x^2} \), \(2x^2\) is the radicand.When working with radical expressions, particularly when simplifying them, the goal is to express them in their simplest form. This can involve:
- Reducing the radicand to its most basic components.
- Combining radical expressions, when possible, using rules like the product rule.
- Ensuring that there are no radicals in the denominator (rationalizing the denominator if necessary).
Mastering Square Root Simplification
Square root simplification revolves around expressing a given square root in its simplest form. To accomplish this, you need to identify and reduce any perfect squares within the radicand.
Suppose you have \(\sqrt{12}\). Begin by factoring \(12\) into its prime factors: \(12 = 2^2 \times 3\). The perfect square here is \(2^2\), which can be extracted, simplifying the expression to \(2\sqrt{3}\).The process involves:
Suppose you have \(\sqrt{12}\). Begin by factoring \(12\) into its prime factors: \(12 = 2^2 \times 3\). The perfect square here is \(2^2\), which can be extracted, simplifying the expression to \(2\sqrt{3}\).The process involves:
- Identifying any perfect squares in the radicand.
- Extracting these perfect squares out of the radical.
- Simplifying the expression to its simplest terms.
Effective Algebraic Simplification Techniques
Algebraic simplification involves reducing mathematical expressions to their most efficient forms, making them easier to work with. It could involve basic operations, factoring, or using specific rules such as distributing or combining like terms.When simplifying expressions like \(x^2\sqrt{12}\) to \(2x^2\sqrt{3}\), things to keep in mind include:
- Ensuring all like terms are combined and all possible factors are factored out.
- Using rules such as the distributive property to combine terms effectively.
- Recognizing equivalent expressions that appear in different forms and simplifying them accordingly.
Other exercises in this chapter
Problem 21
Multiply or divide as indicated. $$\frac{x^{3}-8}{x^{2}-4} \cdot \frac{x+2}{3 x}$$
View solution Problem 21
Factor each trinomial, or state that the trinomial is prime. $$ x^{2}-8 x+15 $$
View solution Problem 21
Find each product. $$(x-5)(x+3)$$
View solution Problem 21
Evaluate each exponential expression in Exercises 1–22. $$\frac{2^{3}}{2^{7}}$$
View solution