Problem 21
Question
Use the method of your choice to factor each trinomial, or state that the trinomial is prime. Check each factorization using FOIL multiplication. $$8 x^{2}+33 x+4$$
Step-by-Step Solution
Verified Answer
The trinomial \(8x^{2}+33x+4\) is prime and cannot be factorized.
1Step 1: Factorize the trinomial
Here we have to find two numbers that multiply to \(8*4=32\), but add up to \(33\). Unfortunately, there are no such numbers. Thus, the trinomial is prime and cannot be factorized.
2Step 2: Verify non-factorization
One way to verify if a trinomial is prime is to use the discriminant method, where we calculate \(b^{2}-4ac\). In this case, a coefficient is \(8\), b coefficient is \(33\), and c coefficient is \(4\). For our case, the discriminant method results in \(33^{2}-4*8*4 = 961\), which is not a perfect square. Thus, it confirms that the trinomial is prime and can’t be factored with integers.
Key Concepts
Prime PolynomialFOIL MultiplicationQuadratic DiscriminantAlgebraic Expressions
Prime Polynomial
A prime polynomial is an interesting concept in algebra. It refers to a polynomial that cannot be factored further with integer coefficients. Imagine it like a prime number, which can't be divided by any number other than 1 and itself. In our exercise with the trinomial \(8x^2 + 33x + 4\), we tried to factor it but found no suitable pairs of numbers that multiply to 32 (product of the constants) and add to 33 (the linear coefficient). As a result, this polynomial is considered prime.
- If a polynomial is prime, it can't be broken into simpler polynomial factors.
- The prime nature was confirmed through the quadratic discriminant showing no perfect square.
FOIL Multiplication
FOIL multiplication is an essential method for multiplying two binomials. It's named FOIL for an easy-to-remember process:
- F stands for multiplying the **First** terms of each binomial.
- O stands for the **Outside** terms multiplication.
- I stands for **Inside** terms multiplication.
- L stands for **Last** terms multiplication.
Quadratic Discriminant
The quadratic discriminant is a valuable tool that gives insights into the nature of the solutions of a quadratic equation. It is found using the formula \(b^2 - 4ac\), where \(a\), \(b\), and \(c\) are coefficients of the quadratic expression \(ax^2 + bx + c\). For the trinomial \(8x^2 + 33x + 4\), we calculated:\[33^2 - 4 \times 8 \times 4 = 961\]Since 961 is not a perfect square, it indicates that the trinomial has no real roots. Here's why it's significant:
- If the discriminant is a perfect square, the polynomial can be factored with rational numbers.
- A non-perfect square discriminant means it can't be factored using integers, confirming it's prime.
Algebraic Expressions
Algebraic expressions are combinations of numbers, variables, and arithmetic operators like addition and multiplication. They form the backbone of algebra and are used to represent mathematical relationships and operations.The given expression \(8x^2 + 33x + 4\) is an example of a quadratic algebraic expression. It includes:
- **Coefficient**: The numerical factor of a term. For instance, 8 in \(8x^2\).
- **Variable**: The letter that represents a number, like \(x\) in this polynomial.
- **Degree**: The highest exponent of the variable, here it's 2, making it a quadratic expression.
Other exercises in this chapter
Problem 21
Now let's move on to factorizations that may require two or more techniques. Factor completely, or state that the polynomial is prime. Check factorizations usin
View solution Problem 21
Factor each polynomial using the greatest common factor. If there is no common factor other than 1 and the polynomial cannot be factored, so state. $$x^{2}+5 x$
View solution Problem 22
Factor each trinomial, or state that the trinomial is prime. Check each factorization using FOIL multiplication. $$x^{2}+4 x+5$$
View solution Problem 22
Use factoring to solve each quadratic equation. Check by substitution or by using a graphing utility and identifying \(x\) -intercepts. $$x^{2}=8 x$$
View solution