Problem 21
Question
Use the given conditions to write an equation for each line in point-slope form and slope-intercept form. Slope \(=\frac{1}{2},\) passing through the origin
Step-by-Step Solution
Verified Answer
The equation of the line both in point-slope form and slope-intercept form is \(y = \frac{1}{2}x\).
1Step 1: Deriving the point-slope form equation
First, we need to write the equation of the line using the point-slope form \(y - y1 = m(x - x1)\). In this formula, plug in the slope which is \(\frac{1}{2}\) for the \(m\) and the point \(0,0\) for \((x1, y1)\).So, the equation becomes \(y - 0 = \frac{1}{2} (x - 0)\) which simplifies to \(y = \frac{1}{2}x\).
2Step 2: Deriving the slope-intercept form equation
Now, we need to write the equation of the line using the slope-intercept form \(y = mx + b\). In this formula, plug in the slope \(\frac{1}{2}\) for \(m\) and since it passes through the origin, \(b\) will be \(0\). So, the equation becomes \(y = \frac{1}{2}x + 0\), which simplifies to \(y = \frac{1}{2}x\).
Key Concepts
slope-intercept formlinear equationsslope of a line
slope-intercept form
The slope-intercept form of a linear equation is one of the most common ways to represent a line graphically. This form is given by the equation \(y = mx + b\), where:
In this particular exercise, the slope \(m\) is given as \(\frac{1}{2}\), and since the line passes through the origin (0,0), the y-intercept \(b\) is 0. Therefore, the slope-intercept form is simplified to \(y = \frac{1}{2}x\). This simplicity makes it easy to graph and understand the relationship of the line to the coordinate plane.
- \(m\) represents the slope of the line, showing how steep it is.
- \(b\) represents the y-intercept, which is the point where the line crosses the y-axis.
In this particular exercise, the slope \(m\) is given as \(\frac{1}{2}\), and since the line passes through the origin (0,0), the y-intercept \(b\) is 0. Therefore, the slope-intercept form is simplified to \(y = \frac{1}{2}x\). This simplicity makes it easy to graph and understand the relationship of the line to the coordinate plane.
linear equations
Linear equations are expressions that create straight lines when graphed on a coordinate plane. They are written in the form \(ax + by = c\), but can also be rearranged into different formats such as point-slope form and slope-intercept form.
Linearity implies a constant rate of change, signified by the slope. These equations can also tell us whether lines are parallel, intersecting, or overlapping by comparing their slopes.
Linearity implies a constant rate of change, signified by the slope. These equations can also tell us whether lines are parallel, intersecting, or overlapping by comparing their slopes.
- Lines with equal slopes are parallel and don’t intersect.
- Lines with different slopes intersect at exactly one point.
slope of a line
The slope of a line is a measure of its steepness and direction. It is calculated as the ratio of the vertical change (rise) to the horizontal change (run) between two points on the line. Mathematically, slope \(m\) is calculated as \(m = \frac{y_2 - y_1}{x_2 - x_1}\).
In our exercise, the slope is given as \(\frac{1}{2}\). This indicates a gentle incline of the line, where for every 2 units moved horizontally along the x-axis (run), there is a rise of 1 unit vertically along the y-axis. The slope tells us not only how steep the line is but also its direction:
In our exercise, the slope is given as \(\frac{1}{2}\). This indicates a gentle incline of the line, where for every 2 units moved horizontally along the x-axis (run), there is a rise of 1 unit vertically along the y-axis. The slope tells us not only how steep the line is but also its direction:
- A positive slope means the line inclines upwards as it moves from left to right.
- A negative slope indicates the line decreases or falls as you move from left to right.
Other exercises in this chapter
Problem 21
Determine whether each equation defines y as a function of \(x .\) $$x+y^{3}=8$$
View solution Problem 21
Graph each equation.Let \(x=-3,-2,-1,0\) \(1,2,\) and 3 $$y=2|x|$$
View solution Problem 22
You have 600 feet of fencing to enclose a rectangular field. Express the area of the field, \(A\), as a function of one of its dimensions, \(x\).
View solution Problem 22
Find the midpoint of each line segment with the given endpoints. $$(-4,-7) \text { and }(-1,-3)$$
View solution