Problem 21
Question
Use an identity to write each expression as a single trigonometric function or as a single number in exact form. Do not use a calculator. $$2 \cos ^{2} 67.5^{\circ}-1$$
Step-by-Step Solution
Verified Answer
The expression simplifies to \(-\frac{\sqrt{2}}{2}\).
1Step 1: Identify the Identity
The expression \(2 \cos^2 \theta - 1\) is a well-known trigonometric identity, which can be simplified using the double angle identity: \(2 \cos^2 \theta - 1 = \cos 2\theta\). Our goal is to express the given expression as a single trigonometric function or a number.
2Step 2: Substitute the Angle
Substitute \(\theta = 67.5^\circ\) into the expression for the cosine double angle identity. This gives us \(\cos(2 \times 67.5^\circ)\).
3Step 3: Calculate the Double Angle
Calculate the angle for the double angle identity. \(2 \times 67.5^\circ = 135^\circ\). So, the expression simplifies to \(\cos 135^\circ\).
4Step 4: Evaluate \(\cos 135^\circ\) in Exact Form
Determine \(\cos 135^\circ\) using the unit circle. \(135^\circ\) is in the second quadrant, where cosine is negative. By symmetry, \(\cos 135^\circ = -\cos 45^\circ\). \(\cos 45^\circ = \frac{\sqrt{2}}{2}\), therefore, \(\cos 135^\circ = -\frac{\sqrt{2}}{2}\).
Key Concepts
Double Angle FormulaCosine FunctionUnit Circle
Double Angle Formula
The Double Angle Formula is an essential tool in trigonometry that simplifies expressions and calculations. It provides a way to relate angles that are multiples of each other, making complex trigonometric problems more manageable.
One of the most common forms of this formula is for the cosine function:
One of the most common forms of this formula is for the cosine function:
- \( \cos 2\theta = 2 \cos^2 \theta - 1 \)
- Alternatively, \( \cos 2\theta = 1 - 2 \sin^2 \theta \)
- Or \( \cos 2\theta = \cos^2 \theta - \sin^2 \theta \)
Cosine Function
The cosine function is a fundamental part of trigonometry and represents the horizontal coordinate of a point on the unit circle as it traverses around the circle. Cosine is one of the core trigonometric functions, alongside sine and tangent.
Some key characteristics of the cosine function include:
Some key characteristics of the cosine function include:
- Periodicity: Cosine is a periodic function with a period of \(360^\circ\) or \(2\pi\). That means \(\cos(\theta) = \cos(\theta + 360^\circ)\).
- Symmetry: Cosine is an even function, meaning \(\cos(-\theta) = \cos(\theta)\).
- Amplitude: The range of cosine is from -1 to 1, which corresponds to its amplitude in the unit circle context.
Unit Circle
The unit circle is a circle with a radius of one, centered at the origin of a coordinate plane. It is a powerful tool in trigonometry, used to define the sine, cosine, and tangent functions for all real numbers.
Here's how the unit circle is utilized:
Here's how the unit circle is utilized:
- Every point \((x, y)\) on the unit circle corresponds to a cosine and sine value: \(\cos\theta = x\) and \(\sin\theta = y\).
- The unit circle helps visualize angles and their corresponding trig values. For example, \(135^\circ\) is located in the second quadrant where cosine values are negative.
- Symmetry and special angles assist in the quick calculation of values. For instance, knowing \(45^\circ\) has \(\cos 45^\circ = \sin 45^\circ = \frac{\sqrt{2}}{2}\), we can deduce that \(\cos 135^\circ = -\cos 45^\circ\).
Other exercises in this chapter
Problem 21
Solve each equation in part (a) analytically over the interval \([0,2 \pi) .\) Then use a graph to solve each inequality in part (b). (a) \(\cos x=\cos 2 x\) (b
View solution Problem 21
Find the exact value of each real number \(y .\) Do not use a calculator. $$y=\sin ^{-1} \frac{\sqrt{2}}{2}$$
View solution Problem 21
Solve each equation for solutions over the interval \([0,2 \pi)\) by first solving for the trigonometric finction. Do not use a calculator. $$2 \sin x-1=\csc x$
View solution Problem 21
Use identities to find the exact value of each expression. Do not use a calculator. $$\frac{\tan 80^{\circ}+\tan 55^{\circ}}{1-\tan 80^{\circ} \tan 55^{\circ}}$
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