Problem 21
Question
Two identical pendulums \(A\) and \(B\) are suspended from the same point. The bobs are given positive charges, with \(A\) having more charge than \(B\). They diverge and reach at equilibrium, with \(A\) and \(B\) making angles \(\theta_{1}\) and \(\theta_{2}\) with the vertical respectively : (a) \(\theta_{1}>\theta_{2}\) (b) \(\theta_{1}<\theta_{2}\) (c) \(\theta_{1}=\theta_{2}\) (d) the tension in \(A\) is greater than that in \(B\)
Step-by-Step Solution
Verified Answer
The correct options are (a) \( \theta_1 > \theta_2 \) and (d) the tension in \( A \) is greater than that in \( B \).
1Step 1: Understanding the Problem
We have two pendulums with charged bobs that diverge due to repulsion and reach a state of equilibrium. We need to determine which condition about the angles and tensions between these pendulums is correct.
2Step 2: Analyzing the Forces on Each Bob
At equilibrium, the forces acting on each bob are gravity (acting vertically downward), tension (acting along the pendulum string), and electrostatic repulsion between the charges. Since bob \( A \) has more charge, it experiences a greater repulsive force than bob \( B \).
3Step 3: Comparing the Angles
With bob \( A \) having more charge, it will be pushed further away due to stronger repulsion, causing it to make a larger angle \( \theta_1 \) with the vertical than bob \( B \), which makes angle \( \theta_2 \). Thus, \( \theta_1 > \theta_2 \).
4Step 4: Evaluating Tensions in the Strings
The tension in each string must balance the components of gravitational force and electrostatic force. Since bob \( A \) is at a larger angle, its tension has to counteract both a larger component of gravitational force parallel to the pendulum and the increased electrostatic force. Therefore, the tension in pendulum \( A \) is greater than that in pendulum \( B \).
5Step 5: Conclusion
Based on the analysis, both \( \theta_1 > \theta_2 \) and tension in \( A \) being greater than in \( B \) are true. Therefore, correct options are (a) \( \theta_1 > \theta_2 \) and (d) the tension in \( A \) is greater than that in \( B \).
Key Concepts
Electrostatic ForcesEquilibrium ConditionsTension in Strings
Electrostatic Forces
When dealing with electrostatics in pendulums, a key concept is the electrostatic force, which acts between charged objects. In our scenario, the pendulum bobs are given positive charges. Due to like charges repelling each other, these bobs experience a force pushing them apart.
This force is described by Coulomb's law, which states that the force between two point charges is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them. Mathematically, it is given by \[ F = k \frac{|q_1 \, q_2|}{r^2} \]where:
This force is described by Coulomb's law, which states that the force between two point charges is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them. Mathematically, it is given by \[ F = k \frac{|q_1 \, q_2|}{r^2} \]where:
- \( F \) is the magnitude of the force between the charges
- \( q_1 \) and \( q_2 \) are the magnitudes of the charges
- \( r \) is the distance between the centers of the two charges
- \( k \) is Coulomb's constant
Equilibrium Conditions
Equilibrium for pendulums involves a balance of forces resulting in no net motion. In physics, equilibrium is reached when all the forces acting on an object sum to zero. For the pendulum bobs, they are in equilibrium when the pulling force of gravity, the pushing electrostatic force, and the tension in the string are balanced.
The gravitational force acts downward toward the Earth and is opposed by the tension in the string, which pulls upward and along the string's length. Simultaneously, the electrostatic force, due to charge repulsion, pushes the bobs apart, making them swing outwards to form angles \( \theta_1 \) and \( \theta_2 \) with the vertical.
Since bob A has more charge, it experiences a stronger electrostatic force and swings out further, resulting in \( \theta_1 > \theta_2 \). This visualization of forces and the understanding of equilibrium conditions provide insights into why pendulum bobs do not keep moving indefinitely but instead stabilize at certain angles.
The gravitational force acts downward toward the Earth and is opposed by the tension in the string, which pulls upward and along the string's length. Simultaneously, the electrostatic force, due to charge repulsion, pushes the bobs apart, making them swing outwards to form angles \( \theta_1 \) and \( \theta_2 \) with the vertical.
Since bob A has more charge, it experiences a stronger electrostatic force and swings out further, resulting in \( \theta_1 > \theta_2 \). This visualization of forces and the understanding of equilibrium conditions provide insights into why pendulum bobs do not keep moving indefinitely but instead stabilize at certain angles.
Tension in Strings
In the context of pendulums, tension is crucial because it provides the necessary force to balance both gravitational and electrostatic influences on the bob.
Tension in the string arises due to its role in maintaining equilibrium. For pendulum bob A, which swings at a larger angle due to its greater charge, the string must handle a larger component of gravitational force pulling downward and a stronger electrostatic force pushing outward.
The tension force can be decomposed into:
Tension in the string arises due to its role in maintaining equilibrium. For pendulum bob A, which swings at a larger angle due to its greater charge, the string must handle a larger component of gravitational force pulling downward and a stronger electrostatic force pushing outward.
The tension force can be decomposed into:
- A vertical component, which balances the gravitational force \((mg)\)
- A horizontal component, which balances the electrostatic repulsion force
Other exercises in this chapter
Problem 16
Two positively charged particles each having charge \(Q\) are \(d\) distance apart. A third charge is introduced in midway on the line joining the two. Find nat
View solution Problem 18
Two negative charges of unit magnitude and a positive charge \(q\) are placed along a straight line. The charge \(q\) is placed between negative charges as such
View solution Problem 22
Two balls of same radius and mass are suspended on threads of length \(1 \mathrm{~m}\) as shown. The mass of each ball and charge is \(15 \mathrm{~g}\) and \(12
View solution Problem 23
Mark correct option or options: (a) A point charge can not exert force on itself (b) Coulomb's force is stronger than the gravitational force (c) Electric field
View solution