Problem 21
Question
Two data points on the rheological diagram of a biofluid are provided. Determine the consistency index and the flow behavior index and the strain rate if the shear stress is increased to 3 dynes \(/ \mathrm{cm}^{2}\). Assume that this is a two-dimensional flow. $$ \begin{aligned} &\frac{d V}{d y}=15 \frac{\mathrm{rad}}{\mathrm{s}}, \tau=0.868 \text { dynes } / \mathrm{cm}^{2} \\ &\frac{d V}{d y}=30 \frac{\mathrm{rad}}{\mathrm{s}}, \tau=0.355 \text { dynes } / \mathrm{cm}^{2} \end{aligned} $$
Step-by-Step Solution
Verified Answer
K is approximately 5.049, n is -1.292, and the new strain rate is 8.73 rad/s.
1Step 1: Understand the Problem Context
We are given two data points from a rheological diagram, which relate shear stress (\( \tau \)) and strain rate (\( \frac{dV}{dy} \)). These parameters are typically described by the power-law model for non-Newtonian fluids. We need to find the consistency index (\( K \)), the flow behavior index (\( n \)), and calculate the new strain rate if shear stress is increased.
2Step 2: Setup the Power-Law Model Equations
The power-law model is given by the equation: \[ \tau = K \left( \frac{dV}{dy} \right)^n \] We have two equations from the data points:\[ 0.868 = K \cdot 15^n \]\[ 0.355 = K \cdot 30^n \]
3Step 3: Solve for the Flow Behavior Index (n)
Divide the first equation by the second to eliminate \( K \):\[ \frac{0.868}{0.355} = \frac{15^n}{30^n} \]Simplifying gives:\[ \left(\frac{15}{30}\right)^n = 2.445 \]This can be expressed as:\[ (0.5)^n = 2.445 \]Taking the natural logarithm of both sides:\[ n \cdot \ln(0.5) = \ln(2.445) \]Solving for \( n \):\[ n = \frac{\ln(2.445)}{\ln(0.5)} \approx -1.292 \]
4Step 4: Solve for the Consistency Index (K)
Substitute \( n = -1.292 \) back into one of the original equations:\[ 0.868 = K \cdot 15^{-1.292} \]Solving for \( K \):\[ K = \frac{0.868}{15^{-1.292}} \approx 5.049 \]
5Step 5: Determine the Strain Rate for New Shear Stress
Use the power-law model to find the new strain rate \( \frac{dV}{dy} \) when \( \tau = 3 \, \text{dynes/cm}^2 \):\[ 3 = 5.049 \left( \frac{dV}{dy} \right)^{-1.292} \]Solving for \( \frac{dV}{dy} \):\[ \frac{dV}{dy} = \left( \frac{3}{5.049} \right)^{\frac{1}{-1.292}} \approx 8.734 \frac{\text{rad}}{\text{s}} \]
Key Concepts
Power-Law ModelConsistency IndexFlow Behavior IndexShear StressStrain Rate
Power-Law Model
The power-law model is crucial in describing non-Newtonian fluids, often illustrated in rheological studies like this. It predicts how the viscosity of a fluid changes with varying applied forces, which is especially significant for biofluids. The general formula of the power-law model is given by \( \tau = K \left( \frac{dV}{dy} \right)^n \) where:
- \( \tau \) represents the shear stress.
- \( K \) is the consistency index.
- \( \left( \frac{dV}{dy} \right) \) indicates the strain rate.
- \( n \) is the flow behavior index.
Consistency Index
The consistency index, denoted as \( K \), is a parameter within the power-law model that indicates the fluid's viscosity at a reference shear rate. It depicts how thick a fluid is under normal conditions. For a given shear stress-strain rate relationship, once the flow behavior index \( n \) has been determined, \( K \) can be extracted from the rheological data points. Using the power-law model equation
- Substitute \( n \) into any of the known equation \( \tau = K \left( \frac{dV}{dy} \right)^n \).
- Solve for \( K \) using the provided data. In this exercise, \( K \approx 5.049 \).
Flow Behavior Index
The flow behavior index \( n \) demonstrates how fluid viscosity changes concerning shear rate, reflecting whether a fluid behaves more like a solid or a liquid under stress. To derive \( n \) in the power-law model, compare shear stress and strain rate from two data points. By eliminating the consistency index \( K \), we can focus solely on \( n \) with the equation
- Calculate the ratio of the shear stresses.
- Take the ratio of the strain rates.
- Use logarithmic equations to solve for \( n \).
Shear Stress
Shear stress, expressed as \( \tau \), is the force per unit area exerted by the fluid in response to an applied force. It is a critical factor in understanding fluid flow, especially in complex fluids like biofluids. In the equation \( \tau = K \left( \frac{dV}{dy} \right)^n \), shear stress can be evaluated for a known strain rate and fluid properties like \( K \) and \( n \). Understanding shear stress is essential for predicting how fluids behave under different conditions:
- Low shear stress means the fluid resists flow more strongly.
- Higher shear stress indicates that the fluid flows more easily.
Strain Rate
The strain rate, denoted by \( \frac{dV}{dy} \), describes the rate at which the fluid particles deform or move in response to applied forces. High strain rates lead to greater deformation as the particles in the fluid slide past each other more quickly. The power-law model defines this relationship as \( \tau = K \left( \frac{dV}{dy} \right)^n \). From known values of shear stress \( \tau \), we can calculate the strain rate if consistency index \( K \) and flow behavior index \( n \) are known. In this problem, given an increased shear stress of 3 dynes/cm², the new strain rate calculates to be approximately
- \( 8.734 \text{ rad/s} \)
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