Problem 21
Question
the general term of a sequence is given and involves a factorial. Write the first four terms of each sequence. $$ a_{n}=2(n+1) ! $$
Step-by-Step Solution
Verified Answer
The first four terms of the sequence are \(4, 12, 48, 240\).
1Step 1: Compute the first term of the sequence
To begin, substitute \(n=1\) into the equation. Therefore, \(a_{1}=2(1+1) !=2*2!=4\). So, the first term is 4.
2Step 2: Compute the second term of the sequence
Next, substitute \(n=2\) into the equation. Therefore, \(a_{2}=2(2+1) !=2*3!=12\). So, the second term is 12.
3Step 3: Compute the third term of the sequence
Now, substitute \(n=3\) into the equation. Therefore, \(a_{3}=2(3+1) !=2*4!=48\). So, the third term is 48.
4Step 4: Compute the fourth term of the sequence
Lastly, substitute \(n=4\) into the equation. Therefore, \(a_{4}=2(4+1) !=2*5!=240\). So, the fourth term is 240.
Key Concepts
General Term of a SequenceFactorialsArithmetic Sequences
General Term of a Sequence
In sequences, the general term often represents an expression that can define all terms of the sequence. This expression is a formula where you can substitute an "n" value to find specific terms in the sequence. In the case of our original exercise, the general term is given by the formula:
- \(a_{n} = 2(n+1) !\)
Factorials
Factorials are a fundamental concept in mathematics, often denoted with an exclamation mark (!). When you see \((n)!\), it refers to the product of all positive integers up to \(n\). For example:
- \(3! = 3 \times 2 \times 1 = 6\)
- \(4! = 4 \times 3 \times 2 \times 1 = 24\)
Arithmetic Sequences
Arithmetic sequences are characterized by a constant difference between consecutive terms. Unlike the sequence described in the original exercise, arithmetic sequences don't involve rapidly increasing terms like those derived from factorial calculations.
Instead, in an arithmetic sequence, you start with an initial number and repeatedly add a fixed amount, called the common difference. For instance, the sequence:
In contrast, sequences with factorials, such as \(a_{n} = 2(n+1)!\), don't fit into the category of arithmetic sequences because their terms don't have a constant difference. Instead, they increase at a varying rate determined by the factorial operation and additional multipliers involved in the general term.
Instead, in an arithmetic sequence, you start with an initial number and repeatedly add a fixed amount, called the common difference. For instance, the sequence:
- 2, 5, 8, 11, 14,...
In contrast, sequences with factorials, such as \(a_{n} = 2(n+1)!\), don't fit into the category of arithmetic sequences because their terms don't have a constant difference. Instead, they increase at a varying rate determined by the factorial operation and additional multipliers involved in the general term.
Other exercises in this chapter
Problem 21
Use the Binomial Theorem to expand each binomial and express the result in simplified form. $$ \left(2 x^{3}-1\right)^{4} $$
View solution Problem 21
Evaluate each expression. \(\frac{7 P_{3}}{3 !}-_{7} C_{3}\)
View solution Problem 21
Use mathematical induction to prove that each statement is true for every positive integer n. \(1 \cdot 2+2 \cdot 3+3 \cdot 4+\cdots+n(n+1)=\frac{n(n+1)(n+2)}{3
View solution Problem 21
Find the indicated term of the arithmetic sequence with first term, \(a_{1},\) and common difference, \(d .\) Find \(a_{60}\) when \(a_{1}=35, d=-3\)
View solution