Problem 21
Question
Solve each equation. $$ 6 x+5=4 x-11 $$
Step-by-Step Solution
Verified Answer
The solution is \( x = -8 \).
1Step 1: Simplify the equation
To simplify the given equation, we need to get all terms with the variable on one side and constants on the other side. We start by subtracting \(4x\) from both sides of the equation: \[ 6x + 5 - 4x = 4x - 11 - 4x \] This simplifies to: \[ 2x + 5 = -11 \]
2Step 2: Isolate the variable term
Next, we need to get \(x\) on its own by moving the constant term (5) to the other side. Subtract 5 from both sides of the equation:\[ 2x + 5 - 5 = -11 - 5 \] This simplifies to: \[ 2x = -16 \]
3Step 3: Solve for the variable
Now, to solve for \(x\), we need to divide both sides by 2: \[ \frac{2x}{2} = \frac{-16}{2} \] This gives us: \[ x = -8 \]
Key Concepts
Algebraic ManipulationVariablesIsolating the Variable
Algebraic Manipulation
Algebraic manipulation is a crucial skill in solving linear equations like the one in this exercise. It involves rearranging and simplifying equations to make them easier to solve. This process includes operations such as addition, subtraction, multiplication, and division, which help us to both simplify and solve equations.
When we begin to solve an equation, our goal is to make it easier to handle. We do this by simplifying, which often means combining like terms. In the equation from our exercise, we simplified by subtracting terms like \(4x\) from both sides, making the equation more straightforward. This step is essential as it reduces the equation to a form where further simplification is possible.
When we begin to solve an equation, our goal is to make it easier to handle. We do this by simplifying, which often means combining like terms. In the equation from our exercise, we simplified by subtracting terms like \(4x\) from both sides, making the equation more straightforward. This step is essential as it reduces the equation to a form where further simplification is possible.
- Combine like terms to simplify the equation.
- Perform same operations on both sides to maintain equality.
Variables
In algebra, variables are symbols that stand for unknown values. They allow us to write equations that describe a wide range of situations. In our exercise, the variable is \(x\), which we need to find the value of.
Variables are placeholders for numbers we don't yet know, and they are often represented by letters. The use of variables allows us to generalize mathematical relationships, solving real-world problems where the numbers may change but the relationships remain constant.
Variables are placeholders for numbers we don't yet know, and they are often represented by letters. The use of variables allows us to generalize mathematical relationships, solving real-world problems where the numbers may change but the relationships remain constant.
- Variables can represent any number within a given set.
- They are used to form expressions and equations.
Isolating the Variable
Isolating the variable is one of the final steps in solving an equation. It involves manipulating the equation until the variable is by itself on one side of the equation, which allows us to determine its value.
In the example exercise, we aimed to get the variable \(x\) by itself. Initially, \(x\) was part of the term \(2x + 5\). We removed the constant term 5 by subtracting it from both sides of the equation, which helped us to isolate \(2x\). Eventually, we divided both sides by 2 to solve for \(x\).
In the example exercise, we aimed to get the variable \(x\) by itself. Initially, \(x\) was part of the term \(2x + 5\). We removed the constant term 5 by subtracting it from both sides of the equation, which helped us to isolate \(2x\). Eventually, we divided both sides by 2 to solve for \(x\).
- Move constant terms to one side and variable terms to the other.
- Divide or multiply to solve for the variable.
Other exercises in this chapter
Problem 21
For problems \(17-46\), find the value of each expression. $$ -5 s-2 t+1, \text { if } s=2 \text { and } t=-2 $$
View solution Problem 21
The sum of five consecutive integers is \(-5 .\) What are they?
View solution Problem 21
Solve each equation. Be sure to check each result. $$ 2 m=-62 $$
View solution Problem 21
Verify that each given value is a solution to the given equation. $$-3 y+7=2 y-15, y=\frac{22}{5}$$
View solution