Problem 21
Question
Sketch the graph of the function \(f\) and evaluate \(\lim _{x \rightarrow a} f(x)\), if it exists, for the given value of \(a\). \(f(x)=\left\\{\begin{array}{ll}|x| & \text { if } x \neq 0 \\ 1 & \text { if } x=0\end{array} \quad(a=0)\right.\)
Step-by-Step Solution
Verified Answer
The graph of the function \(f(x) = \begin{cases}
|x| & \text{if } x \neq 0 \\
1 & \text{if } x = 0
\end{cases}\) is a V-shaped graph following the absolute value function, with a "hole" at the origin and a "dot" at the point (0,1). Evaluating the limit as x approaches 0, we find that both one-sided limits are equal to 0.
Therefore, \(\lim_{x \rightarrow 0} f(x) = 0\).
1Step 1: Analyze the function for x≠0
For x≠0, the function is defined as f(x) = |x|. This is the absolute value function, which is a V-shaped graph with a vertex at the origin (0,0). It is continuous for all x-values and has values of f(x) approaching 0 as x approaches 0 from both the left and the right.
2Step 2: Analyze the function for x=0
For x=0, the function is defined as f(x) = 1. So, at the point x=0, instead of following the expected V-shape with point (0,0), the function has a defined value of 1. This creates a "hole" in the graph at the origin and a "dot" at point (0,1).
3Step 3: Sketch the graph
To sketch the graph, we combine the observations from Steps 1 and 2. Draw the V-shape of the absolute value function with a "hole" at the origin. Then, add a "dot" at the point (0,1) to represent the value of the function when x=0.
4Step 4: Evaluate the limit as x approaches 0
Now we will evaluate the limit as x approaches 0. From the graph, we can see that as x approaches 0 from the left and right, the function f(x) approaches 0 because of the absolute value part. But, since f(x) is defined as being equal to 1 at the point x=0, we have a jump discontinuity. In order for the limit to exist, the function must approach the same value from both the left and right.
In this case, we can see that:
\(\lim_{x \rightarrow 0^{-}} f(x) = 0\)
\(\lim_{x \rightarrow 0^{+}} f(x) = 0\)
Since both one-sided limits are equal to 0, the limit exists and is equal to 0:
\(\lim_{x \rightarrow 0} f(x) = 0\)
Key Concepts
Absolute Value FunctionGraph SketchingDiscontinuity
Absolute Value Function
The absolute value function is represented by the notation \( |x| \) and is pivotal in understanding various mathematical concepts. It converts all negative inputs into their positive counterparts while leaving positive inputs unchanged, rendering the output of \( |x| \) always non-negative.
Visually, the graph of an absolute value function is a V-shape, symmetrically rising from the origin to both the left and the right. This symmetry results from the fact that for every value \( x \) on the number line, the points \( (x, |x|) \) and \( (-x, |-x|) \) are mirrored across the y-axis. Here's an important thing to note: although the concept might sound simple, its implications are significant in calculus, especially when dealing with limits and continuity.
Students often encounter the absolute value when addressing distance and real-world problem-solving, such as finding the shortest path or determining a difference in values without considering direction.
Visually, the graph of an absolute value function is a V-shape, symmetrically rising from the origin to both the left and the right. This symmetry results from the fact that for every value \( x \) on the number line, the points \( (x, |x|) \) and \( (-x, |-x|) \) are mirrored across the y-axis. Here's an important thing to note: although the concept might sound simple, its implications are significant in calculus, especially when dealing with limits and continuity.
Students often encounter the absolute value when addressing distance and real-world problem-solving, such as finding the shortest path or determining a difference in values without considering direction.
Graph Sketching
Sketching the graph of a function is a fundamental skill in calculus, serving not just to visualize the function but also to analyze its behavior at various points. When sketching, focus on identifying key features: intercepts, slopes, maxima, minima, and points of discontinuity.
In our given problem, we're dealing with a special case where the function changes definition at \( x=0 \). For \( x eq 0 \) the graph follows the standard V-shape of the absolute value function. At \( x=0 \) we have a different value which creates a unique point, needing to be marked distinctly on the graph – often with a dot or a circle to indicate its special status.
In our given problem, we're dealing with a special case where the function changes definition at \( x=0 \). For \( x eq 0 \) the graph follows the standard V-shape of the absolute value function. At \( x=0 \) we have a different value which creates a unique point, needing to be marked distinctly on the graph – often with a dot or a circle to indicate its special status.
Quick Sketching Tips:
- Identify the overall shape (like the V-shape for the absolute value function).
- Mark key points, including where the function changes definition.
- Consider behavior at and near discontinuities carefully.
Discontinuity
In calculus, a discontinuity is a point at which a function is not continuous. Discontinuities can appear in various forms such as jump, point, infinite, or removable discontinuities.
A function is continuous at a point if it meets three conditions: The function is defined at that point, the limit exists, and the function's value equals the limit. Conversely, if any of these conditions fail, we have a discontinuity.
In the given problem, the function displays a jump discontinuity at \( x=0 \). Despite the V-shape of the absolute value indicating the function approaches zero from either side, the function's definition abruptly changes the value to 1 at \( x=0 \).
A function is continuous at a point if it meets three conditions: The function is defined at that point, the limit exists, and the function's value equals the limit. Conversely, if any of these conditions fail, we have a discontinuity.
In the given problem, the function displays a jump discontinuity at \( x=0 \). Despite the V-shape of the absolute value indicating the function approaches zero from either side, the function's definition abruptly changes the value to 1 at \( x=0 \).
Understanding Limits and Discontinuity:
The limit of a function as \( x \) approaches a certain value is all about the function's behavior as \( x \) gets infinitely close to that value - not the function's actual value at the point. This distinction plays a crucial role in differentiating between the limit of a function at a point and its continuity.Other exercises in this chapter
Problem 21
Find the slope of the tangent line to the graph of each function at the given point and determine an equation of the tangent line. \(f(x)=-\frac{1}{x}\) at \(\l
View solution Problem 21
In Exercises 21-38, find the indicated one-sided limit, if it exists. \(\lim _{x \rightarrow 1^{+}}(2 x+4)\)
View solution Problem 22
Find the derivative of each function. \(f(t)=\left(5 t^{3}+2 t^{2}-t+4\right)^{-3}\)
View solution Problem 22
Find the derivative of each function. \(f(x)=\frac{x^{3}-2}{x^{2}+1}\)
View solution