Problem 21
Question
Sketch a triangle that has acute angle \(\theta\), and find the other five trigonometric ratios of \(\theta\). $$\cot \theta=1$$
Step-by-Step Solution
Verified Answer
\(\sin \theta = \frac{\sqrt{2}}{2}, \cos \theta = \frac{\sqrt{2}}{2}, \tan \theta = 1, \csc \theta = \sqrt{2}, \sec \theta = \sqrt{2}\), and \(\cot \theta = 1\).
1Step 1: Understand the Given Information
We know that \(\cot \theta = 1\). Since \(\cot \theta = \frac{1}{\tan \theta}\), it implies that \(\tan \theta = 1\).
2Step 2: Identify the Right Triangle Configuration
A triangle where \(\tan \theta = 1\) indicates that the opposite side and the adjacent side are of equal length (because \(\tan \theta = \frac{\text{opposite}}{\text{adjacent}}\)). One such right triangle is the isosceles right triangle (45°-45°-90° triangle), where both the legs are equal and angles are 45° each.
3Step 3: Calculate the Hypotenuse
For an isosceles right triangle where each leg is 1, the hypotenuse can be found using the Pythagorean theorem: \[ c = \sqrt{1^2 + 1^2} = \sqrt{2} \]
4Step 4: Determine Sine and Cosine Ratios
Using the legs and hypotenuse, calculate:\(\sin \theta = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{1}{\sqrt{2}} = \frac{\sqrt{2}}{2}\), and \(\cos \theta = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{1}{\sqrt{2}} = \frac{\sqrt{2}}{2}\).
5Step 5: Determine Secant and Cosecant Ratios
Use the reciprocal identities: \(\csc \theta = \frac{1}{\sin \theta} = \sqrt{2}\), and \(\sec \theta = \frac{1}{\cos \theta} = \sqrt{2}\).
6Step 6: Verifying the Tangent Ratio Again
\(\tan \theta\) was given as 1, which matches our earlier identification of the triangle as an isosceles right triangle. Thus, all calculations align with the given \(\cot \theta = 1\).
Key Concepts
Right TriangleIsosceles Right TriangleSine and CosinePythagorean TheoremReciprocal Identities
Right Triangle
In trigonometry, a right triangle is fundamental. It is a triangle with one angle measuring
exactly 90 degrees. The essence of studying these triangles lies within their sides:
- Legs: These are the two shorter sides adjacent to the right angle.
- Hypotenuse: This is the longest side opposite the right angle.
Isosceles Right Triangle
An isosceles right triangle is a special kind of right triangle. As its name suggests, this triangle has two equal sides (the legs) and a right angle. It also features two equal angles, both measuring 45 degrees.
This specific configuration simplifies calculations, since:
This specific configuration simplifies calculations, since:
- When one leg is equal to 1 unit, the other leg will also be 1 unit.
- The hypotenuse, using the Pythagorean theorem, is \[ \sqrt{2} \].
Sine and Cosine
In trigonometry, sine and cosine are two essential ratios that relate an angle to the lengths of sides in a right triangle.
For an angle \( \theta \):
For an angle \( \theta \):
- The sine function (\( \sin \theta \)) is the ratio of the opposite side to the hypotenuse.
- The cosine function (\( \cos \theta \)) is the ratio of the adjacent side to the hypotenuse.
- \( \sin \theta = \frac{1}{\sqrt{2}} = \frac{\sqrt{2}}{2} \)
- \( \cos \theta = \frac{1}{\sqrt{2}} = \frac{\sqrt{2}}{2} \)
Pythagorean Theorem
The Pythagorean theorem is a powerful tool in trigonometry, guiding us to solve right triangle problems effortlessly. It is mathematically expressed as:
\[a^2 + b^2 = c^2\]where \( a \) and \( b \) are the legs, and \( c \) is the hypotenuse of a right triangle.
For our isosceles right triangle example:
\[a^2 + b^2 = c^2\]where \( a \) and \( b \) are the legs, and \( c \) is the hypotenuse of a right triangle.
For our isosceles right triangle example:
- Taking each leg \( a = b = 1 \),
- The hypotenuse \( c = \sqrt{1^2 + 1^2} = \sqrt{2} \).
Reciprocal Identities
Reciprocal identities in trigonometry offer an alternate perspective on basic trigonometric functions. They relate the primary functions (sine, cosine, and tangent) to other functions:
- The cosecant of \( \theta \) (\( \csc \theta \)) is the reciprocal of sine: \( \csc \theta = \frac{1}{\sin \theta} \).
- The secant of \( \theta \) (\( \sec \theta \)) is the reciprocal of cosine: \( \sec \theta = \frac{1}{\cos \theta} \).
- The cotangent of \( \theta \) (\( \cot \theta \)) is the reciprocal of tangent: \( \cot \theta = \frac{1}{\tan \theta} \).
Other exercises in this chapter
Problem 21
Find all angles \(\theta\) between \(0^{\circ}\) and \(180^{\circ}\) satisfying the given equation. $$\sin \theta=\frac{1}{2}$$
View solution Problem 21
Use the Law of sines to solve for all possible triangles that satisfy the given conditions. $$a=20, \quad c=45, \quad \angle A=125^{\circ}$$
View solution Problem 21
Find the degree measure of the angle with the given radian measure. $$-1.2$$
View solution Problem 22
Find the exact value of the trigonometric function. $$\cos 660^{\circ}$$
View solution