Problem 21
Question
Simplify. $$\left(8 x^{4} y^{-3}\right)\left(\frac{1}{2} x^{-5} y^{2}\right)$$
Step-by-Step Solution
Verified Answer
The simplified expression is \(\frac{4}{xy}\).
1Step 1: Group Like Terms
Start by grouping the terms with the same variables. Consider the expression: \( \left(8 x^{4} y^{-3}\right)\left(\frac{1}{2} x^{-5} y^{2}\right) \). Break it down into: \((8 \cdot \frac{1}{2}) (x^{4} \cdot x^{-5}) (y^{-3} \cdot y^{2})\) for easier simplification.
2Step 2: Simplify the Coefficients
Simplify the coefficients. Multiply \(8\) and \(\frac{1}{2}\) to get \(4\). So now we have: \(4 (x^{4} \cdot x^{-5}) (y^{-3} \cdot y^{2})\).
3Step 3: Apply the Exponent Rules for \(x\)
Use the rule \(x^a \cdot x^b = x^{a+b}\). For \(x\): \(x^{4} \cdot x^{-5} = x^{4 + (-5)} = x^{-1}\).
4Step 4: Apply the Exponent Rules for \(y\)
Similarly, apply the exponent rule to \(y\). For \(y\): \(y^{-3} \cdot y^{2} = y^{-3+2} = y^{-1}\).
5Step 5: Write the Final Expression
Combine the simplified terms to write the final expression. We have \(4 \cdot x^{-1} \cdot y^{-1}\), which can also be written as \(\frac{4}{x \cdot y}\), since negative exponents denote the reciprocal.
Key Concepts
Exponent RulesNegative ExponentsProduct of PowersReciprocal of Exponents
Exponent Rules
When dealing with exponents, it is essential to understand the rules that govern their behavior. These rules simplify expressions and help us manipulate terms with exponents effortlessly.
Here are some key exponent rules:
Here are some key exponent rules:
- Multiplying with the same base: If you multiply terms with the same base, you add the exponents. For instance, if you have \(x^a \cdot x^b\), the result is \(x^{a+b}\).
- Dividing with the same base: When dividing, subtract the exponents, so \(\frac{x^a}{x^b} = x^{a-b}\).
- Power of a power: Raising a power to another power means multiplying the exponents: \((x^a)^b = x^{a \cdot b}\).
- Zero exponent: Any base raised to the power of zero is equal to one, \(x^0 = 1\).
Negative Exponents
Negative exponents might seem confusing at first, but they just indicate that the base is on the other side of a fraction. In other words, a negative exponent tells you to take the reciprocal of the base.
Here's what you need to know:
Here's what you need to know:
- Reciprocal meaning: \(x^{-a} = \frac{1}{x^a}\).
- Negative to positive: To make negative exponents positive, move the base to the opposite part of the fraction (numerator to denominator or vice versa).
Product of Powers
The product of powers rule is a convenient and powerful tool in algebra that helps you efficiently simplify and combine terms with exponents.
In your original exercise, you encounter terms like \(x^4 \cdot x^{-5}\), where the product of powers rule comes into play:
In your original exercise, you encounter terms like \(x^4 \cdot x^{-5}\), where the product of powers rule comes into play:
- When multiplying, simply add the exponents together. In the example: \(x^4 \cdot x^{-5} = x^{4 + (-5)} = x^{-1}\).
- This rule also applies to other variables like \(y\) in the exercise: \(y^{-3} \cdot y^2 = y^{-1}\).
Reciprocal of Exponents
The reciprocal of exponents is a vital concept that stems from understanding negative exponents. When a term contains a negative exponent, you can express it as the reciprocal of the positive exponent.
For instance, from your exercise:
Mastering this concept makes handling expressions with multiple negative exponents much easier.
For instance, from your exercise:
- \(x^{-1} = \frac{1}{x}\)
- \(y^{-1} = \frac{1}{y}\)
Mastering this concept makes handling expressions with multiple negative exponents much easier.
Other exercises in this chapter
Problem 20
Write the expression in the form \(a+b i,\) where \(a\) and \(b\) are real numbers. $$\frac{5}{2-7 i}$$
View solution Problem 21
The two given numbers are coordinates of points \(A\) and \(B\), respectively, on a coordinate line. Express the indicated statement as an inequality involving
View solution Problem 21
Express as a polynomial. $$(3 x+2 y)^{2}(3 x-2 y)^{2}$$
View solution Problem 21
Factor the polynomial. $$64 x^{3}-y^{6}$$
View solution