Problem 21
Question
Simplify each expression by taking as much out from under the radical as possible. You may assume that all variables represent positive numbers $$\sqrt{32 x^{2} y^{3}}$$
Step-by-Step Solution
Verified Answer
The simplified expression is \( 4xy\sqrt{2y} \).
1Step 1: Prime factorize the number
First, we need to factor the number under the square root: \( 32 \). This can be expressed as \( 32 = 2^5 \).
2Step 2: Write the expression inside the square root
Write the expression inside the square root using the prime factorization and variables: \( \sqrt{2^5 \cdot x^2 \cdot y^3} \).
3Step 3: Simplify using properties of square roots
Apply the property \( \sqrt{a \cdot b} = \sqrt{a} \cdot \sqrt{b} \). Separate the factors: \( \sqrt{2^5} \cdot \sqrt{x^2} \cdot \sqrt{y^3} \).
4Step 4: Simplify each radical
Simplify each radical: \( \sqrt{2^5} = 2^2 \sqrt{2} = 4\sqrt{2} \), \( \sqrt{x^2} = x \), and \( \sqrt{y^3} = y\sqrt{y} \).
5Step 5: Combine the simplified terms
Now, combine all the simplified terms: \( 4x y \sqrt{2y} \). This is the simplified expression where no further factor can be taken out of the square root.
Key Concepts
Prime FactorizationProperties of Square RootsExpression SimplificationMathematical Operations
Prime Factorization
Prime factorization is a crucial step when dealing with radicals. It involves breaking down a number into its basic building blocks, which are prime numbers. A prime number is a natural number greater than 1 that is not divisible by any other numbers except for 1 and itself. For the number 32, the process goes like this:
- 32 is even, so divide by 2 to get 16.
- 16 is also even, divide by 2 to get 8.
- 8 continues to be divisible by 2, giving 4.
- 4 divides by 2 to get 2, and finally, 2 is already prime.
Properties of Square Roots
Understanding and using the properties of square roots are vital for simplifying radical expressions. One such property states that the square root of a product equals the product of the square roots of the factors: \[\sqrt{a \cdot b} = \sqrt{a} \cdot \sqrt{b}\]This property allows you to handle complex roots more efficiently. Suppose you have \(\sqrt{32x^2y^3}\). To make things simpler, you break this into parts:
- \( \sqrt{32} \) using our prime factorization becomes \( \sqrt{2^5} \)
- \( \sqrt{x^2} \) and \( \sqrt{y^3} \) represent the variable components.
Expression Simplification
Expression simplification combines several techniques to make a mathematical expression more manageable. Once numbers and variables are factored and roots are taken, simplification is the next logical step. Consider \(\sqrt{32x^2y^3}\). After applying knife-edge prime factorization and the properties of square roots, we rewrite this as:
- \( \sqrt{2^5} \) is equivalent to \(2^2 \sqrt{2} = 4\sqrt{2}\).
- \( \sqrt{x^2} \) simplifies directly to \(x\).
- \( \sqrt{y^3} \) factors into \(y\sqrt{y}\).
Mathematical Operations
At the heart of simplifying expressions lie mathematical operations. These operations interconnect processes we use in breaking down, rearranging, and simplifying radical expressions. They are the bridge between complex expressions and simplified results.In our original problem, fundamental operations include multiplication and the distributive property seen when applying roots:
- Multiplication - used to combine factors under a single radical (\(32x^2y^3\)).
- Distributive property of square roots - allowing \(\sqrt{a \cdot b} = \sqrt{a} \cdot \sqrt{b}\) to separate and simplify parts.
Other exercises in this chapter
Problem 21
Simplify each of the following expressions without using a calculator. $$3 \sqrt{25}+9 \sqrt{49}$$
View solution Problem 21
Simplify each square root, then combine if possible. Assume all variables represent positive numbers. $$4 \sqrt{20 x^{3}}+3 \sqrt{45 x^{3}}$$
View solution Problem 21
Solve each equation. $$0.5 x+0.1(x+20)=3.2$$
View solution Problem 21
Complete the following table by converting each decimal to a fraction. Decimal \(0.125 \quad 0.250 \quad 0.375 \quad 0.500 \quad 0.625 \quad 0.750 \quad 0.875\)
View solution