Problem 21
Question
Probability A coin is tossed ten times. The probability of heads on each toss is \(0.5 .\) Evaluate each probability. a. exactly 5 heads \(\quad\) b. exactly 6 heads \(\quad\) c. exactly 7 heads
Step-by-Step Solution
Verified Answer
The probability of getting exactly a) 5 heads is calculated in step 1; b) 6 heads is calculated in step 2; c) 7 heads is calculated in step 3. Each step provides the respective probability.
1Step 1: Evaluating probability for exactly 5 heads
Substitute \(k = 5, n = 10, p = q = 0.5\) into the formula and calculate the probability: \[ P(5;10,0.5) = C(10, 5) \cdot (0.5^5) \cdot ((1-0.5)^{10-5}) \]
2Step 2: Evaluating probability for exactly 6 heads
Substitute \(k = 6, n = 10, p = q = 0.5\) into the formula and calculate the probability: \[ P(6;10,0.5) = C(10, 6) \cdot (0.5^6) \cdot ((1-0.5)^{10-6}) \]
3Step 3: Evaluating probability for exactly 7 heads
Substitute \(k = 7, n = 10, p = q = 0.5\) into the formula and calculate the probability: \[ P(7;10,0.5) = C(10, 7) \cdot (0.5^7) \cdot ((1-0.5)^{10-7}) \]
Key Concepts
Probability TheoryCombinatoricsCoin Toss Experiment
Probability Theory
Probability theory is a branch of mathematics that deals with the likelihood of different outcomes. In simple terms, it helps us to understand how probable something is to happen. If you think about any random event, such as a coin toss, this theory provides a structured way to calculate how often we can expect a certain result.
When you toss a fair coin, there are two possible outcomes: heads or tails. Each outcome has a probability of 0.5 because the coin is fair and balanced. This idea of assigning numbers to uncertain events is at the heart of probability theory. In more complex situations, like the one in our problem where the coin is tossed ten times, probability theory allows us to calculate the likelihood of getting a specific number of heads.
When you toss a fair coin, there are two possible outcomes: heads or tails. Each outcome has a probability of 0.5 because the coin is fair and balanced. This idea of assigning numbers to uncertain events is at the heart of probability theory. In more complex situations, like the one in our problem where the coin is tossed ten times, probability theory allows us to calculate the likelihood of getting a specific number of heads.
- Probability ranges from 0 to 1: 0 means an event will not happen, and 1 means it certainly will.
- The sum of probabilities for all possible outcomes in an experiment is always 1.
- Binomial probability, like in the exercise, involves experiments where there are two discrete outcomes, often referred to as success and failure.
Combinatorics
Combinatorics is all about counting how many ways things can be organized or arranged, which is crucial in computing probabilities in experiments like our coin toss. In our example, we want to determine the number of ways we can get a specific number of heads when tossing a coin 10 times.
A significant tool used in combinatorics is the binomial coefficient, often represented as \( C(n, k) \) or "n choose k," which calculates the number of ways to choose \( k \) successes (e.g., heads) out of \( n \) trials (e.g., tosses). This coefficient is calculated as:
\[ C(n, k) = \frac{n!}{k!(n-k)!} \]
A significant tool used in combinatorics is the binomial coefficient, often represented as \( C(n, k) \) or "n choose k," which calculates the number of ways to choose \( k \) successes (e.g., heads) out of \( n \) trials (e.g., tosses). This coefficient is calculated as:
\[ C(n, k) = \frac{n!}{k!(n-k)!} \]
- \( n!\) ("n factorial") means you multiply all positive integers from 1 to \( n \).
- Combinatorics helps consider all possible arrangements to assess probabilities properly.
- In our coin toss experiment, combinatorics helps us calculate the number of ways to achieve a specific outcome, like getting exactly 5, 6, or 7 heads.
Coin Toss Experiment
The coin toss experiment is a classic example in probability that serves as a perfect introduction to understanding probabilistic events. Tossing a coin is one of the simplest types of experiments because it involves only two outcomes: heads or tails. When you expand this simple experiment to multiple tosses, it becomes more complex and interesting because you can apply probability and combinatorial principles to assess outcomes.
In the exercise, we are asked to calculate the probability of obtaining a certain number of heads when a coin is tossed 10 times. This situation is modeled by a binomial distribution because:
In the exercise, we are asked to calculate the probability of obtaining a certain number of heads when a coin is tossed 10 times. This situation is modeled by a binomial distribution because:
- There are a fixed number of trials (10 tosses).
- Each trial has two possible outcomes (heads or tails).
- The probability of success (getting heads) is the same on every trial.
Other exercises in this chapter
Problem 20
Divide using synthetic division. $$\left(3 x^{3}+17 x^{2}+21 x-9\right) \div(x+3)$$
View solution Problem 20
Find a cubic model for each function. Then use your model to estimate the value of \(y\) when \(x=17\) . $$ (10,500),(14,588),(16,512),(20,0) $$
View solution Problem 21
Evaluate each expression. \(_{6} \mathrm{C}_{2}\)
View solution Problem 21
Find all the zeros of each function. $$ y=x^{3}-4 x^{2}+9 x-36 $$
View solution