Problem 21
Question
Perform the indicated operation and write the result in standard form. $$(12+5 i)-(7-i)$$
Step-by-Step Solution
Verified Answer
The result is \(5 + 6i\).
1Step 1: Understand the complex numbers structure
Complex numbers are in the form \(a + bi\), where \(a\) is the real part and \(bi\) is the imaginary part. Here we have two complex numbers and we need to subtract one from the other, which means we should subtract the real part from the real part and the imaginary part from the imaginary part.
2Step 2: Perform the subtraction for the real parts
We subtract \(7\) (the real part of the second number) from \(12\) (the real part of the first number). This results in \(12 - 7 = 5\).
3Step 3: Perform the subtraction for the imaginary parts
We subtract \(-1\) (the imaginary part of the second number, don't forget about the minus in front of it) from \(5\) (the imaginary part of the first number). This results in \(5 -(-1) = 5 + 1 = 6\). After the subtraction, we multiply the result by \(i\) (the imaginary unit) to retain the imaginary part.
4Step 4: Write out the answer in standard form
The result of the subtraction of the two complex numbers is \(5 + 6i\), which is the final result in standard form for a complex number.
Key Concepts
Standard Form of a Complex NumberComplex Numbers OperationsImaginary Numbers Arithmetic
Standard Form of a Complex Number
A complex number is a mathematical entity comprising both a real number and an imaginary number. It's expressed in the standard form as:
\( a + bi \),
where \( a \) represents the real part and \( bi \) represents the imaginary part, with \( i \) being the imaginary unit, satisfying \( i^2 = -1 \). The beauty of the standard form lies in its simplicity, allowing us to perform arithmetic operations much like we do with real numbers, while keeping the distinct components organized.
For instance, the complex numbers in our exercise, \( 12 + 5i \) and \( 7 - i \), are displayed in this clear, standard form, making it straightforward to identify and manipulate their respective real and imaginary parts.
\( a + bi \),
where \( a \) represents the real part and \( bi \) represents the imaginary part, with \( i \) being the imaginary unit, satisfying \( i^2 = -1 \). The beauty of the standard form lies in its simplicity, allowing us to perform arithmetic operations much like we do with real numbers, while keeping the distinct components organized.
For instance, the complex numbers in our exercise, \( 12 + 5i \) and \( 7 - i \), are displayed in this clear, standard form, making it straightforward to identify and manipulate their respective real and imaginary parts.
Complex Numbers Operations
Operations with complex numbers follow the same fundamental principles as with real numbers but with added attention to both the real and imaginary components. When adding or subtracting complex numbers, we combine like terms; that is, real numbers with real numbers, and imaginary numbers with imaginary numbers.
Subtraction of Complex Numbers
In subtraction, such as in our example, we individually subtract the real part of the second number from the real part of the first, and do the same with the imaginary parts. The subtraction is performed as:- Real Parts: \( 12 - 7 = 5 \)
- Imaginary Parts: \( 5i - (-i) = 5i + i = 6i \)
Imaginary Numbers Arithmetic
Imaginary number arithmetic involves performing operations with the imaginary unit \( i \), which can seem daunting at first. However, treating \( i \) as a variable—with the unique property that \( i^2 = -1 \)—simplifies the process. We can then apply the standard arithmetic rules as we would with algebraic expressions.
In the subtraction task from our exercise, one key step is managing the sign in front of the imaginary part, ensuring that \( -(-i) \) becomes \( +i \), due to the rule of signs in standard arithmetic. This results in an intuitive addition:
In the subtraction task from our exercise, one key step is managing the sign in front of the imaginary part, ensuring that \( -(-i) \) becomes \( +i \), due to the rule of signs in standard arithmetic. This results in an intuitive addition:
- \( 5i + i = 6i \)
Other exercises in this chapter
Problem 21
Compare the graph of \(f(x)=1 / x\) with the graph of \(g\). $$g(x)=-f(x)=-\frac{1}{x}$$
View solution Problem 21
Find all the zeros of the function and write the polynomial as a product of linear factors. $$f(x)=x^{3}+24 x^{2}+214 x+740$$
View solution Problem 21
(a) list the possible rational zeros of \(f_{t}\) (b) sketch the graph of \(f\) so that some of the possible zeros in part (a) can be discarded, and (c) determi
View solution Problem 22
Use synthetic division to divide. Divisor \(x-2\) Dividend $$9 x^{3}-16 x-18 x^{2}+32$$
View solution