Problem 21
Question
Perform each of the following elementary row operations on the augmented matrix \(\left[\begin{array}{rrrr}3 & 6 & -9 & 0 \\ 1 & 5 & -2 & 1 \\ -2 & 2 & -2 & 5\end{array}\right]\) $$ R_{2} \leftrightarrow R_{3} $$
Step-by-Step Solution
Verified Answer
The matrix after performing \( R_2 \leftrightarrow R_3 \) is \( \left[ \begin{array}{rrrr}3 & 6 & -9 & 0 \\ -2 & 2 & -2 & 5 \\ 1 & 5 & -2 & 1 \end{array} \right] \).
1Step 1: Identify Row Swap Operation
We need to perform the row operation \( R_2 \leftrightarrow R_3 \), which means we are going to swap row two with row three in the matrix.
2Step 2: Write Initial Matrix
The augmented matrix we are starting with is: \[\begin{bmatrix}3 & 6 & -9 & 0 \1 & 5 & -2 & 1 \-2 & 2 & -2 & 5\end{bmatrix}\]
3Step 3: Perform Row Swap
According to the operation \( R_2 \leftrightarrow R_3 \), switch the second row with the third row. After the swap, the matrix becomes: \[\begin{bmatrix}3 & 6 & -9 & 0 \-2 & 2 & -2 & 5 \1 & 5 & -2 & 1\end{bmatrix}\]
4Step 4: Verify the Result
Double-check the swapped rows to ensure accuracy. The second row \([-2, 2, -2, 5]\) is now in the former position of the third, and the third row \([1, 5, -2, 1]\) is where the second row was, confirming a correct operation.
Key Concepts
Augmented MatrixRow Swap OperationMatrix Manipulation
Augmented Matrix
An augmented matrix is a tool used to represent a system of linear equations. It combines the coefficients of the variables and the constants from each equation into a single matrix. For example, in the given problem, the augmented matrix is: \[ \begin{bmatrix}3 & 6 & -9 & 0 \ 1 & 5 & -2 & 1 \ -2 & 2 & -2 & 5\end{bmatrix} \]In this matrix, the first three columns represent the coefficients of the variables, while the last column contains the constants from each equation. The structure of an augmented matrix is particularly helpful because it allows us to use matrix operations, such as row swaps and other manipulations, to find solutions to the system of equations involved.
- First three columns: Coefficients of variables.
- Last column: Constants of the equations.
- Represents a full system of linear equations.
Row Swap Operation
The row swap operation is a simple yet powerful technique used in matrix manipulation, especially when working with an augmented matrix. The operation is denoted as \(R_i \leftrightarrow R_j\), where \(R_i\) and \(R_j\) are the rows being swapped in the matrix. In the original exercise, the operation was given as:\[ R_2 \leftrightarrow R_3 \]This means that we exchange row 2 with row 3. After performing this operation on the given augmented matrix, the new matrix configuration becomes:\[ \begin{bmatrix}3 & 6 & -9 & 0 \ -2 & 2 & -2 & 5 \ 1 & 5 & -2 & 1\end{bmatrix} \]Why would you perform a row swap? Here are some reasons:
- To simplify the matrix and reveal solutions.
- To position pivotal elements in convenient spots.
- To handle unique cases like rearranging equations for clarity.
Matrix Manipulation
Matrix manipulation involves using various operations to transform a matrix into a desired form. These operations can rearrange, scale, or modify rows and columns to simplify or solve systems of equations. In this context, the main operation involved is the row swap, but there are several others commonly used in conjunction with it:
- Row Addition: Add a multiple of one row to another row.
- Row Scaling: Multiply all entries of a row by a non-zero scalar.
- Row Swap: Exchange two rows in the matrix.
Other exercises in this chapter
Problem 20
Solve each system. $$ \left\\{\begin{array}{l} 4 x-3 y+5 z=23 \\ 2 x-5 y-3 z=13 \\ -4 x-6 y+7 z=7 \end{array}\right. $$
View solution Problem 21
Evaluate each determinant. $$ \left|\begin{array}{cc} -6 & -2 \\ 15 & 4 \end{array}\right| $$
View solution Problem 21
Solve each system by elimination. See Examples 3 and 4 $$ \left\\{\begin{array}{l} x-y=7 \\ x+y=11 \end{array}\right. $$
View solution Problem 21
Solve each system. $$ \left\\{\begin{array}{l} 4 x-5 y-8 z=-52 \\ 2 x-3 y-4 z=-26 \\ 3 x+7 y+8 z=31 \end{array}\right. $$
View solution