Problem 21
Question
Name the following acids. Assume each compound is dissolved in water. $$\mathrm{HClO}_{2}$$
Step-by-Step Solution
Verified Answer
The acid \(
\mathrm{HClO}_{2}\) is named chlorous acid.
1Step 1: Introduction to Naming Oxyacids
Oxyacids are acids that contain hydrogen, oxygen, and another element. To name an oxyacid, the name of the polyatomic ion (the base ion) is used, with specific changes to its suffix.
2Step 2: Identifying the Polyatomic Ion
For the compound \(\mathrm{HClO}_{2}\), determine the polyatomic ion present. The ion is \(\mathrm{ClO}_{2}^{-}\), which is known as chlorite.
3Step 3: Applying the Naming Rules for Oxyacids
When naming the acid form of an ion ending in '-ite', the '-ite' suffix changes to '-ous,' and 'acid' is added at the end. Therefore, the name of \(\mathrm{HClO}_{2}\) is chlorous acid.
Key Concepts
Acid Naming RulesPolyatomic IonsChemistry Education
Acid Naming Rules
Naming oxyacids can seem tricky at first, but once you understand the rules, it becomes much easier. Oxyacids are acids that contain hydrogen, oxygen, and another element, typically a non-metal. The key to naming these acids lies in the polyatomic ion from which they are derived. The common rule is to alter the suffix of the polyatomic ion's name, and then add the word 'acid' at the end.
- If the polyatomic ion ends in '-ate,' the suffix changes to '-ic.' For example, \( \text{H}_2\text{SO}_4 \) (which includes sulfate) is sulfuric acid.
- If the polyatomic ion ends in '-ite,' the suffix changes to '-ous.' For example, \( \text{HClO}_2 \) includes chlorite and becomes chlorous acid.
Polyatomic Ions
Polyatomic ions play a crucial role in chemistry, especially when dealing with oxyacids. A polyatomic ion is a charged species composed of two or more atoms covalently bonded. They act as a single entity when participating in chemical reactions.
Identifying the polyatomic ion within a compound is crucial for naming acids correctly. For example, in \( \text{HClO}_2 \), the polyatomic ion is \( \text{ClO}_2^- \), known as chlorite. You need to recognize these ions and remember their typical names and charges.
Learning common polyatomic ions such as sulfate \( \text{SO}_4^{2-} \), nitrate \( \text{NO}_3^- \), and phosphate \( \text{PO}_4^{3-} \), will help you in identifying them in chemical compounds and naming acids accurately.
Identifying the polyatomic ion within a compound is crucial for naming acids correctly. For example, in \( \text{HClO}_2 \), the polyatomic ion is \( \text{ClO}_2^- \), known as chlorite. You need to recognize these ions and remember their typical names and charges.
Learning common polyatomic ions such as sulfate \( \text{SO}_4^{2-} \), nitrate \( \text{NO}_3^- \), and phosphate \( \text{PO}_4^{3-} \), will help you in identifying them in chemical compounds and naming acids accurately.
Chemistry Education
Chemistry is like learning a new language, and acid naming is one of its many vocabulary lessons. Gaining a solid understanding of these concepts through exercises and practice allows students to decode and understand a wide range of chemical reactions. Educational exercises, like naming acids, offer stepping stones to more complex chemistry topics and help reinforce learning.
To make learning chemistry easier, keep these tips in mind:
To make learning chemistry easier, keep these tips in mind:
- Break down the information into simple, understandable parts.
- Consistently practice naming various compounds to reinforce memory.
- Utilize lots of visual aids such as flashcards or diagrams to help with memorization.
Other exercises in this chapter
Problem 19
Name the following acids. Assume each compound is dissolved in water. $$\mathrm{Hl}$$
View solution Problem 20
Name the following acids. Assume each compound is dissolved in water. $$\mathrm{HClO}_{3}$$
View solution Problem 22
Name the following acids. Assume each compound is dissolved in water. $$\mathrm{H}_{2} \mathrm{SO}_{4}$$
View solution Problem 23
Name the following acids. Assume each compound is dissolved in water. $$\mathrm{H}_{2} \mathrm{S}$$
View solution