Problem 21
Question
In Problems 17-22, find the Cartesian equations of the graphs of the given polar equations. \(r \sin \theta-1=0\)
Step-by-Step Solution
Verified Answer
The Cartesian equation is \(y = 1\).
1Step 1: Convert Polar to Cartesian Equations
The given polar equation is \(r \sin \theta - 1 = 0\). In polar coordinates, \(x = r \cos \theta\) and \(y = r \sin \theta\). We know that \(r \sin \theta = y\). Substitute this into the equation to get \(y - 1 = 0\).
2Step 2: Solve for Cartesian Equation
The equation \(y - 1 = 0\) simplifies to \(y = 1\). This is the Cartesian equation of the given polar equation.
Key Concepts
Understanding Polar CoordinatesConverting Equations between Polar and Cartesian SystemsGraphing Equations using Different Coordinate Systems
Understanding Polar Coordinates
Polar coordinates are a way of describing the position of a point in a plane using a distance and an angle. It is different from the typical way we've learned, which uses x and y coordinates. Instead of saying "how far to the left or right" (x-axis) and "how far up or down" (y-axis), polar coordinates use:
When working with polar equations, you'll often come across forms like \( r = f(\theta) \), which provides a relationship between the radius and the angle. Moving between cartesian and polar coordinates sometimes makes solving particular math problems more convenient.
- The radius \( r \), which tells us how far the point is from the origin (like the center of a circle).
- The angle \( \theta \), which tells us the direction from the origin to the point. It's usually measured in radians or degrees from the positive x-axis.
When working with polar equations, you'll often come across forms like \( r = f(\theta) \), which provides a relationship between the radius and the angle. Moving between cartesian and polar coordinates sometimes makes solving particular math problems more convenient.
Converting Equations between Polar and Cartesian Systems
The conversion between polar and cartesian coordinates is essential when different forms of equations are given. Each system has its own advantages, depending on the problem type and context. The relationship between polar and cartesian coordinates can be summarized using the following:
- The x-coordinate in the cartesian plane can be expressed as \( x = r \cos \theta \).
- The y-coordinate is given by \( y = r \sin \theta \).
- The radius \( r \) can be found using \( r = \sqrt{x^2 + y^2} \).
- The angle can be calculated using \( \theta = \tan^{-1}(\frac{y}{x}) \).
Graphing Equations using Different Coordinate Systems
Once equations are converted to a usable form, graphing becomes straightforward. In our example, after conversion, we find the equation \( y = 1 \).
This is remarkably simple to visualize in the cartesian plane, as it is a horizontal line at \( y = 1 \) which stretches infinitely to the left and right.
This is remarkably simple to visualize in the cartesian plane, as it is a horizontal line at \( y = 1 \) which stretches infinitely to the left and right.
- In a polar context, equations may describe circles, or portions of curves, making them complex to draw by hand.
- Using a cartesian equation provides clarity and precision, especially for linear graphs.
Other exercises in this chapter
Problem 20
Sketch the limaçon \(r=3-6 \sin \theta\), and find the area of the region that is inside its large loop, but outside its small loop.
View solution Problem 20
Find the equations of the tangent and the normal lines to the given parabola at the given point. Sketch the parabola, the tangent line, and the normal line. $$x
View solution Problem 21
In Problems \(21-30\), find \(d y / d x\) and \(d^{2} y / d x^{2}\) without eliminating the parameter. $$ x=3 \tau^{2}, y=4 \tau^{3} ; \tau \neq 0 $$
View solution Problem 21
Sketch the graph of the given equation. $$ (y-1)^{2}=16 $$
View solution