Problem 21
Question
In a frictionless, constant-area flow of a perfect gas, the inlet conditions are \(\rho_{1}=100 \mathrm{kPa}, \rho_{1}=1 \mathrm{~kg} / \mathrm{m}^{3}\), and \(u_{1}=100 \mathrm{~m} / \mathrm{s}\). At a downstream station the gas is at \(200 \mathrm{~m} / \mathrm{s}\). Assuming the medium is air, calculate the corresponding static pressure and density, \(p_{2}\) and \(p_{2}\), respectively. $$ \left[R_{\text {air }}=287 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, \gamma_{\text {air }}=1.4\right] $$
Step-by-Step Solution
Verified Answer
The corresponding static pressure and density at the downstream station are \(p_2=125 \, kPa\) and \(\rho_2 = 0.5 \, kg/m^3\), respectively.
1Step 1: Formulate Isentropic Flow Relations
The continuity equation for one-dimensional isentropic flow gives the relationship between density and velocity: \(\rho_1 u_1 = \rho_2 u_2\). Similarly, the energy equation leads to the relation: \(\frac{u_1^2}{2} + \frac{p_1}{\rho_1} = \frac{u_2^2}{2} + \frac{p_2}{\rho_2}\). These equations allow us to relate the conditions at the two points in the flow.
2Step 2: Calculate Intermediate Velocity Ratio
First determine the velocity ratio \( \frac{u_2}{u_1} = 2 \). Substituting this value into the continuity equation will allow us to find the ratio \(\frac{\rho_2}{\rho_1}\).
3Step 3: Calculate Density Ratio
From the continuity equation we find \(\frac{\rho_2}{\rho_1} = \frac{1}{2}\). This gives us the density at the downstream point, \( \rho_2 = 0.5 \, kg/m^3 \).
4Step 4: Calculate Pressure Ratio
Substitute the values of upstream and downstream velocities and densities into the energy equation. Simplifying will give the ratio \(\frac{p_2}{p_1} = \frac{5}{4}\). Hence we find the static pressure at point 2 to be \(p_2=125 \, kPa\).
Key Concepts
Continuity EquationEnergy EquationDensity RatioPressure Ratio
Continuity Equation
In fluid dynamics, the continuity equation is a fundamental principle that describes the conservation of mass in a flow system. For one-dimensional isentropic flow, the continuity equation states that the product of density (\( \rho \)) and velocity (\( u \)) remains constant along the flow. This is expressed as \( \rho_1 u_1 = \rho_2 u_2 \). This relationship ensures that the mass flow rate is the same at all points in the system.
- Initial conditions are used to calculate downstream properties. For example, if velocity increases downstream, density must decrease to maintain mass conservation.
- In our problem, we have an initial velocity and density, allowing us to find the downstream density using the continuity equation.
Energy Equation
The energy equation for fluid flow incorporates principles of energy conservation. In isentropic (no energy loss due to heat transfer or friction) and adiabatic (no heat exchange) processes, the energy in the flow is conserved across the system. This is represented by the Bernoulli equation, adapted for compressible flows, as: \[ \frac{u_1^2}{2} + \frac{p_1}{\rho_1} = \frac{u_2^2}{2} + \frac{p_2}{\rho_2} \] Here, the kinetic energy per unit mass and the flow work term contribute to the total energy at any point in the system. Energy conservation helps us relate pressure and velocity changes across the flow.
- This equation allows us to relate the input conditions to the output conditions, particularly finding how pressure changes when velocity increases without external work being done.
- Using this equation, we understand that when velocity doubles, downstream pressure can be calculated, keeping the system isolated from external influences.
Density Ratio
The density ratio in isentropic flow reveals how the density of a fluid changes as it moves through a system with varying velocities. Using the continuity equation, for our scenario, we found that the density changes in response to velocity changes. Since \( \rho_1 u_1 = \rho_2 u_2 \), we can rearrange to find \( \rho_2 = \rho_1 \frac{u_1}{u_2} \).
Given the velocity ratio \( \frac{u_2}{u_1} = 2 \), the density ratio is \( \frac{\rho_2}{\rho_1} = \frac{1}{2} \). Thus, the downstream density becomes half of the initial density, highlighting how density is inversely related to velocity in a conservation setup.
The density ratio indicates that as fluid speeds up, its density decreases, a critical understanding in applications like air intakes in aircraft.
The density ratio indicates that as fluid speeds up, its density decreases, a critical understanding in applications like air intakes in aircraft.
Pressure Ratio
The pressure ratio is a crucial quantity in analyzing flow changes in systems where pressure and velocity vary. Isentropic relations help us in connecting the changes in the fluid properties as it progresses downstream.
We use the energy equation to derive the pressure ratio in our example. With velocity doubling, we found:
We use the energy equation to derive the pressure ratio in our example. With velocity doubling, we found:
- The calculated pressure ratio from the energy equation is \( \frac{p_2}{p_1} = \frac{5}{4} \).
- This means the downstream pressure is 1.25 times the initial pressure, resulting in \( p_2 = 125 \, \text{kPa} \).
Other exercises in this chapter
Problem 18
A frictionless, constant-area duct flow of a perfect gas is heated to a choking condition. The rate of heat transfer per unit mass flow rate is \(500 \mathrm{~k
View solution Problem 20
In an adiabatic, constant-area flow of a perfect gas, the inlet conditions are \(p_{1}=100 \mathrm{kPa}, \rho_{1}=1 \mathrm{~kg} / \mathrm{m}^{3}\), and \(u_{1}
View solution Problem 22
Consider a one-dimensional adiabatic flow of a perfect gas with friction. Air enters a circular duct of \(20-\mathrm{cm}\) diameter at Mach \(0.5\) and an avera
View solution Problem 23
A perfect gas flows in a well-insulated, constant-area pipe with friction at \(M_{1}=2.0\). For an average wall friction coefficient of \(C_{f}=0.004\), calcula
View solution