Problem 21
Question
In \(15-26,\) write the first five terms of each geometric sequence. $$ a_{1}=-1, a_{2}=4 $$
Step-by-Step Solution
Verified Answer
The first five terms are \( -1, 4, -16, 64, -256 \).
1Step 1: Understand a Geometric Sequence
A geometric sequence is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio, denoted as \( r \).
2Step 2: Find the Common Ratio
The common ratio \( r \) can be found by dividing the second term \( a_2 \) by the first term \( a_1 \). Substituting the given values, \( r = \frac{a_2}{a_1} = \frac{4}{-1} = -4 \).
3Step 3: Calculate the Third Term
The third term \( a_3 \) of the sequence is obtained by multiplying the second term \( a_2 \) by the common ratio \( r \). That is, \( a_3 = a_2 \times r = 4 \times -4 = -16 \).
4Step 4: Calculate the Fourth Term
The fourth term \( a_4 \) is calculated by multiplying the third term \( a_3 \) by the common ratio \( r \). Therefore, \( a_4 = a_3 \times r = -16 \times -4 = 64 \).
5Step 5: Calculate the Fifth Term
The fifth term \( a_5 \) is found by multiplying the fourth term \( a_4 \) by the common ratio \( r \). Consequently, \( a_5 = a_4 \times r = 64 \times -4 = -256 \).
6Step 6: Write the First Five Terms
Having calculated all necessary terms, the first five terms of the sequence are \( -1, 4, -16, 64, -256 \).
Key Concepts
Common RatioSequence TermsMultiplying Series
Common Ratio
In a geometric sequence, the concept of a common ratio is fundamental. This is the fixed number that we multiply by to get from one term in the sequence to the next. If you know the first two terms of the sequence, like in this example with the first term (\(a_1 = -1\)) and the second term (\(a_2 = 4\)), you can find the common ratio.
To find the common ratio, divide the second term by the first term. Here, it looks like this:
This simple division helps you unlock the mystery of how each term relates in the series, making it the cornerstone of understanding geometric sequences.
To find the common ratio, divide the second term by the first term. Here, it looks like this:
- Common Ratio (\(r\)) = \(\frac{a_2}{a_1} = \frac{4}{-1} = -4\)
This simple division helps you unlock the mystery of how each term relates in the series, making it the cornerstone of understanding geometric sequences.
Sequence Terms
Understanding sequence terms in a geometric sequence revolves around how each term is generated using the common ratio. Once we have the common ratio, calculating subsequent terms is straightforward. Let's look at how this works in practice, using the sequence from the problem:
We already know:
We already know:
- First term (\(a_1\)) = -1
- Second term (\(a_2\)) = 4
- Third term (\(a_3\)): Multiply the second term by the common ratio:
\(a_3 = a_2 \times r = 4 \times -4 = -16\) - Fourth term (\(a_4\)): Multiply the third term by the common ratio:
\(a_4 = a_3 \times r = -16 \times -4 = 64\) - Fifth term (\(a_5\)): Multiply the fourth term by the common ratio:
\(a_5 = a_4 \times r = 64 \times -4 = -256\)
Multiplying Series
The concept of multiplying series in a geometric sequence is both elegant and practical. Since each term is a multiple of the previous one by a fixed amount, or common ratio, identifying these terms enables us to easily build a series.
This method applies to any geometric sequence consistently:
This method applies to any geometric sequence consistently:
- Identify or calculate the common ratio.
- Compute each subsequent term by multiplying the previous term by the common ratio.
- Starting from the first term \(a_1 = -1\), multiply by the common ratio \(-4\) to get the second term \(a_2 = 4\).
- Repeat this multiplication to progress through the sequence. Each multiplication turns the term into the next sequence term: \(-1 \rightarrow 4 \rightarrow -16 \rightarrow 64 \rightarrow -256\).
Other exercises in this chapter
Problem 21
In \(15-26,\) write each series in sigma notation. $$ \frac{1}{2}+\frac{2}{3}+\frac{3}{4}+\frac{4}{5}+\frac{5}{6}+\frac{6}{7}+\frac{7}{8}+\frac{8}{9}+\frac{9}{1
View solution Problem 21
In \(15-22 :\) a. Write each sum as a series. b. Find the sum of each series. $$ 100+\sum_{k=1}^{6} 100\left(\frac{1}{2}\right)^{k} $$
View solution Problem 21
In \(19-30 :\) a. Write an algebraic expression that represents \(a_{n}\) for each sequence. b. Find the ninth term of each sequence. $$ 1,4,7,10, \dots $$
View solution Problem 21
In \(19-24 :\) a. Write each arithmetic series as the sum of terms. b. Find the sum. $$ \sum_{n=0}^{9}(20-2 n) $$
View solution